The New Practical Builder and Workman's Companion, Containing a Full Display and Elucidation of the Most Recent and Skilful Methods Pursued by Architects and Artificers ... Including, Also, New Treatises on Geometry ..., a Summary of the Art of Building ..., an Extensive Glossary of the Technical Terms ..., and The Theory and Practice of the Five Orders, as Employed in Decorative ArchitectureThomas Kelly, 1823 - 596 σελίδες |
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Σελίδα 72
... what is called a double ordinate : make ED equal to the height , in the middle of AC ; then , upon AC , as a side , describe a rectangle , AFGC , so that the opposite side may pass through 72 THE NEW PRACTICAL BUILDER , & c .
... what is called a double ordinate : make ED equal to the height , in the middle of AC ; then , upon AC , as a side , describe a rectangle , AFGC , so that the opposite side may pass through 72 THE NEW PRACTICAL BUILDER , & c .
Σελίδα 73
... ordinate , AE , and a given abscissa , ED * ( fig . 19 , pl . II ) . Make EC equal to EA , and complete the rectangle AFGC ; so that the op- posite side may pass through D. Proceed as in the two former problems , 33 and 34 ; excepting ...
... ordinate , AE , and a given abscissa , ED * ( fig . 19 , pl . II ) . Make EC equal to EA , and complete the rectangle AFGC ; so that the op- posite side may pass through D. Proceed as in the two former problems , 33 and 34 ; excepting ...
Σελίδα 76
... ordinate . Hence the same section may be found by the method already shown in the problem ; viz . by drawing any straight line , deb , fig . 4 : make de equal to DE , fig . 3 , and eb equal to EB , fig . 3. Through d draw the straight ...
... ordinate . Hence the same section may be found by the method already shown in the problem ; viz . by drawing any straight line , deb , fig . 4 : make de equal to DE , fig . 3 , and eb equal to EB , fig . 3. Through d draw the straight ...
Σελίδα 77
Peter Nicholson. pendicular to the line of section , DE . Make the ordinates qi , rk , sl , & c . each respectively equal to the ordinates Qa , Rb , Sc , & c .; and through the points D , i , k , l , & c . to E , draw a curve , which ...
Peter Nicholson. pendicular to the line of section , DE . Make the ordinates qi , rk , sl , & c . each respectively equal to the ordinates Qa , Rb , Sc , & c .; and through the points D , i , k , l , & c . to E , draw a curve , which ...
Σελίδα 78
... ordinates , ea , fb , gc , & c . , to in , ko , lp , & c .; then , through the points D , n , o , p , & c . draw the curve Dnop , & c . to E , and it will be the section cut by the plane , as required . PROBLEM 41 . 224. Given the great ...
... ordinates , ea , fb , gc , & c . , to in , ko , lp , & c .; then , through the points D , n , o , p , & c . draw the curve Dnop , & c . to E , and it will be the section cut by the plane , as required . PROBLEM 41 . 224. Given the great ...
Συχνά εμφανιζόμενοι όροι και φράσεις
ABCD abscissa adjacent angles altitude angle ABD annular vault axes axis major base bisect called centre chord circle circumference cone conic section conjugate contains COROLLARY 1.-Hence cutting cylinder describe a semi-circle describe an arc diameter distance divide draw a curve draw lines draw the lines edge ellipse Engraved equal angles equal to DF equation equiangular figure GEOMETRY given straight line greater groin homologous sides hyperbola intersection join joist latus rectum less Let ABC line of section meet multiplying Nicholson opposite sides ordinate parallel to BC parallelogram perpendicular PLATE points of section polygon PROBLEM produced proportionals quantity radius rectangle regular polygon ribs right angles roof segment similar triangles square straight edge subtracted surface Symns tangent THEOREM timber transverse axis triangle ABC vault vertex wherefore
Δημοφιλή αποσπάσματα
Σελίδα 27 - If two triangles have two angles of the one equal to two angles of the other, each to each, and one side equal to one side, viz.
Σελίδα 20 - The areas of two triangles which have an angle of the one equal to an angle of the other are to each other as the products of the sides including the equal angles. D c A' D' Hyp. In triangles ABC and A'B'C', ZA = ZA'. To prove AABC = ABxAC. A A'B'C' A'B'xA'C' Proof. Draw the altitudes BD and B'D'.
Σελίδα 51 - The area of a parallelogram is equal to the product of its base and its height: A = bx h.
Σελίδα 15 - AXIOMS. 1. Things which are equal to the same thing are equal to one another. 2. If equals be added to equals, the wholes are equal. 3. If equals be taken from equals, the remainders are equal.
Σελίδα 15 - LET it be granted that a straight line may be drawn from any one point to any other point.
Σελίδα 28 - ... angles of another, the third angles will also be equal, and the two triangles will be mutually equiangular. Cor.
Σελίδα 81 - C' (89) (90) (91) (92) (93) 112. In any plane triangle, the sum of any two sides is to their difference as the tangent of half the sum of the opposite angles is to the tangent of half their difference.
Σελίδα 80 - The sine of an arc is a straight line drawn from one extremity of the arc perpendicular to the radius passing through the other extremity. The tangent of an arc is a straight line touching the arc at one extremity, and limited by the radius produced through the other extremity.
Σελίδα 28 - After remarking that the mathematician positively knows that the sum of the three angles of a triangle is equal to two right angles...
Σελίδα 22 - The perpendicular is the shortest line that can be drawn from a point to a straight line.