The New Practical Builder and Workman's Companion, Containing a Full Display and Elucidation of the Most Recent and Skilful Methods Pursued by Architects and Artificers ... Including, Also, New Treatises on Geometry ..., a Summary of the Art of Building ..., an Extensive Glossary of the Technical Terms ..., and The Theory and Practice of the Five Orders, as Employed in Decorative ArchitectureThomas Kelly, 1823 - 596 σελίδες |
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Αποτελέσματα 1 - 5 από τα 16.
Σελίδα 17
... suppose that one of them takes the A direction CD , and the other CE . B At the point C suppose CF to be drawn , perpendicular to AC ; then , be- cause ACD is , by hypothesis , a straight line , the angle FCD is a right angle ; ( Def ...
... suppose that one of them takes the A direction CD , and the other CE . B At the point C suppose CF to be drawn , perpendicular to AC ; then , be- cause ACD is , by hypothesis , a straight line , the angle FCD is a right angle ; ( Def ...
Σελίδα 18
... Suppose the triangle ABC to be placed upon the tri- B D angle DEF , so that AB may be upon DE ; then , because the angles A and D are equal , AC will fall upon DF ; and , because AB is equal to DE , and AC equal to DF , the point B will ...
... Suppose the triangle ABC to be placed upon the tri- B D angle DEF , so that AB may be upon DE ; then , because the angles A and D are equal , AC will fall upon DF ; and , because AB is equal to DE , and AC equal to DF , the point B will ...
Σελίδα 21
... suppose AD to be drawn from the vertex A to the middle point D , of the base BC ; then the two triangles ADB , ADC , will have the two sides AB , BD , of the one equal to the two sides B D AC , CD , of the other , each to each ; and AD ...
... suppose AD to be drawn from the vertex A to the middle point D , of the base BC ; then the two triangles ADB , ADC , will have the two sides AB , BD , of the one equal to the two sides B D AC , CD , of the other , each to each ; and AD ...
Σελίδα 22
... suppose it were possible to draw AB , AC , perpendi- cular from the same point A , upon the straight line DE ; pro- duce one of them , AB , to F , so that BF may be equal to AB , and join FC ; and , because AB is equal to BF , and BC is ...
... suppose it were possible to draw AB , AC , perpendi- cular from the same point A , upon the straight line DE ; pro- duce one of them , AB , to F , so that BF may be equal to AB , and join FC ; and , because AB is equal to BF , and BC is ...
Σελίδα 24
... suppose , if it be possible , that these sides are un- equal , and that BC is the greater . Take BG equal to EF , and join AG . The triangles ABG and DEF , having AB equal to DE , and BG equal to EF , by hypothesis , and also having the ...
... suppose , if it be possible , that these sides are un- equal , and that BC is the greater . Take BG equal to EF , and join AG . The triangles ABG and DEF , having AB equal to DE , and BG equal to EF , by hypothesis , and also having the ...
Συχνά εμφανιζόμενοι όροι και φράσεις
ABCD abscissa adjacent angles altitude angle ABD annular vault axes axis major base bisect called centre chord circle circumference cone conic section conjugate contains COROLLARY 1.-Hence cutting cylinder describe a semi-circle describe an arc diameter distance divide draw a curve draw lines draw the lines edge ellipse Engraved equal angles equal to DF equation equiangular figure GEOMETRY given straight line greater groin homologous sides hyperbola intersection join joist latus rectum less Let ABC line of section meet multiplying Nicholson opposite sides ordinate parallel to BC parallelogram perpendicular PLATE points of section polygon PROBLEM produced proportionals quantity radius rectangle regular polygon ribs right angles roof segment similar triangles square straight edge subtracted surface Symns tangent THEOREM timber transverse axis triangle ABC vault vertex wherefore
Δημοφιλή αποσπάσματα
Σελίδα 27 - If two triangles have two angles of the one equal to two angles of the other, each to each, and one side equal to one side, viz.
Σελίδα 20 - The areas of two triangles which have an angle of the one equal to an angle of the other are to each other as the products of the sides including the equal angles. D c A' D' Hyp. In triangles ABC and A'B'C', ZA = ZA'. To prove AABC = ABxAC. A A'B'C' A'B'xA'C' Proof. Draw the altitudes BD and B'D'.
Σελίδα 51 - The area of a parallelogram is equal to the product of its base and its height: A = bx h.
Σελίδα 15 - AXIOMS. 1. Things which are equal to the same thing are equal to one another. 2. If equals be added to equals, the wholes are equal. 3. If equals be taken from equals, the remainders are equal.
Σελίδα 15 - LET it be granted that a straight line may be drawn from any one point to any other point.
Σελίδα 28 - ... angles of another, the third angles will also be equal, and the two triangles will be mutually equiangular. Cor.
Σελίδα 81 - C' (89) (90) (91) (92) (93) 112. In any plane triangle, the sum of any two sides is to their difference as the tangent of half the sum of the opposite angles is to the tangent of half their difference.
Σελίδα 80 - The sine of an arc is a straight line drawn from one extremity of the arc perpendicular to the radius passing through the other extremity. The tangent of an arc is a straight line touching the arc at one extremity, and limited by the radius produced through the other extremity.
Σελίδα 28 - After remarking that the mathematician positively knows that the sum of the three angles of a triangle is equal to two right angles...
Σελίδα 22 - The perpendicular is the shortest line that can be drawn from a point to a straight line.