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Βιβλία Βιβλία 1 - 10 από 73 για Divide the greater number by the less, the divisor by the remainder, and thus continue....
" Divide the greater number by the less, the divisor by the remainder, and thus continue to divide the last divisor by the last remainder until there is no remainder ; the last divisor will be the greatest common divisor. "
Higher Arithmetic: Designed for the Use of High Schools, Academies, and ... - Σελίδα 22
των George Roberts Perkins - 1851 - 342 σελίδες
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The popular educator

Popular educator - 1767
...KULE. — Divide tho greater by the loss, then the preceding divisor by the remainder, and so on, nntil there is no remainder. The last divisor will be the greatest common measure required. EXAMPLE. — To find tho greatest common measure of 532 and 1274. Arrange the process thus...

The shipwright's vade-mecum [by D. Steel].

David Steel - 1805
...common measure, divide the greater number by the lesser, and the last divisor by the remainder till there is no remainder; the last divisor will be the greatest common measure. EXAMPLE I. Reduce the fraction 4f£f *° 'ts lowest terms. 9767-7-4418=2, remainder 931. 4418-7-931=4,...

Treatise on the elements of algebra

James Bryce - 1837
...The greatest common measure of two numbers is found by dividing the greater by the less, and the last divisor by the last remainder, until there is no remainder : the last divisor is the measure required. Let a and /, be the quantities whose common measure is required, and let a...

Elements of algebra

William Foster - 1840
...letter : divide the greater by the less, and the preceding divisor by the last remainder, and so on till there is no remainder, the last divisor will be the greatest common measure. Ex. Find the greatest common measure of 2« + 1 + -r' and 2*4 ¿"+2*+ 1. We arrange the quantities...

Higher Arithmetic: Designed for the Use of High Schools, Academies, and Colleges

George Roberts Perkings - 1841 - 252 σελίδες
...measure of two numbers by the following RULE, Divide the greater by the less, then divide the divisor by the remainder, and thus continue to divide the...last divisor will be the greatest common measure. Examples. 1. What ia the greatest common measure of 360, and 630 ? OPBRATION. 360)630(1 360 270)360(1...

Elements of Algebra: Embracing ... the Theory and Application of Logarithms ...

Davis Wasgatt Clark - 1844 - 346 σελίδες
...remainder, divide the first divisor by this remainder. 3. Continue to divide in the same manner till there is no remainder ; the last divisor will be the greatest common measure. Note 1. — If, in the course of the reduction, one factor is found to be common to all the terms of one...

An Elementary Arithmetic ...: Serving as an Introduction to the Higher ...

George Roberts Perkins - 1846 - 258 σελίδες
...greater number by the less, then the less numbtr by the remainder ; thus continue to divide the last divisor by the last remainder, until there is no remainder. The last divisor will be the greatest common divisor. NOTE. — When there are more than two numbers whoae greatest common divisor is required,...

Elements of Algebra: Embracing Also the Theory and Application of Logarithms ...

Davis Wasgatt Clark - 1846 - 358 σελίδες
...remainder, divide the first divisor by this remainder. 3. Continue to divide in the same manner till there is no remainder ; the last divisor will be the greatest common measure. Note 1.—If, in the course of the reduction, one factor is found to be common to all the terms of one of...

Arithmetic, in Two Parts

Frederic A. Adams - 1846 - 212 σελίδες
...less, and then take the divisor for a new dividend, and divide it by the remainder, and so on, till there is no remainder ; the last divisor will be the greatest common divisor. . i Apply the above rule to the sixth example. 187)221(1 187 ~34"U87C5 greatest common divisor...

A Treatise on Algebra: Embracing, Besides the Elementary Principles, All the ...

George Roberts Perkins - 1847 - 420 σελίδες
...equivalent to the following RULE. Divide ¿he denominator by the numerator ; then divide this divisor by the remainder, and thus continue to divide the...preceding divisor by the last remainder, until there is no • tmainder, or until we have obtained as many terms as we wish; then will these successive quotients...




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