The Practical Model Calculator, for the Engineer, Mechanic, Machinist, Manufacturer of Engine-work, Naval Architect, Miner, and Millwright

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H.C. Baird, 1863 - 588 σελίδες

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Σελίδα 18 - Operations with Fractions A) To change a mixed number to an improper fraction, simply multiply the whole number by the denominator of the fraction and add the numerator.
Σελίδα 10 - Los números cardinales 0: zero 1: one 2: two 3: three 4: four 5: five 6: six 7: seven 8: eight 9: nine 10: ten 11: eleven 12: twelve 13: thirteen 14: fourteen 15: fifteen 16: sixteen 17: seventeen 18: eighteen 19: nineteen 20: twenty...
Σελίδα 238 - To ascertain the nominal power by this method, multiply the square of the diameter of the cylinder in inches by the cube root of the stroke in feet, and divide the product by 47 ; the quotient is the number of nominal horses power of the engine...
Σελίδα 133 - Practical, Short, and Direct Method of Calculating the Logarithm of any given Number and the Number corresponding to any given Logarithm," discovered by Oliver Byrne, the author of the present work.
Σελίδα 19 - To reduce fractions of different denominators to equivalent fractions having a common denominator. RULE.! Multiply each numerator into all the denominators except its own for a new numerator, and all the denominators together for a common denominator.
Σελίδα 6 - TABLE. 20 grains (gr.) make 1 scruple, sc. or 9. 3 scruples " 1 dram, dr. or 3. .8 drams " 1 ounce, oz. or §. 12 ounces
Σελίδα 152 - Multiply the square of the diameter of the cylinder in inches by the length of the stroke in inches, and by 171; and divide the product by the diameter of the driving-wheels in feet.
Σελίδα 24 - RULE. Divide as in whole numbers, and from the right hand of the quotient point off as many places for decimals as the decimal places in the dividend exceed those in the divisor.
Σελίδα 27 - Multiply each term in the multiplicand, beginning at the lowest, by the feet in the multiplier, and write...
Σελίδα 44 - If the errors are alike, divide the difference of the products by the difference of the errors, and the quotient will be the answer.

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