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DEFINITIONS.

XXVII. A PARALLELOGRAM

is a four-sided figure whose oppo

site sides are parallel.

D

For brevity we often designate a parallelogram by two letters only, which mark opposite angles. Thus we call the figure in the margin the parallelogram AC.

XXVIII. A RECTANGLE is

a parallelogram, having one of its angles a right angle.

XXIX. A RHOMBUS is a parallelogram, having its sides equal.

XXX. A SQUARE is a parallelogram, having its sides equal and one of its angles a right angle.

XXXI. A TRAPEZIUM is a four-sided figure of which two sides only are parallel.

XXXII. A DIAGONAL of a four-sided figure is the straight line joining two of the opposite angular points.

XXXIII. The ALTITUDE of a Parallelogram is the perpendicular distance of one of its sides from the side opposite, regarded as the Base.

The altitude of a triangle is the perpendicular dis

tance of one of its angular points from the side opposite, regarded as the base.

Thus if ABCD be a parallelogram, and AE a perpendicular let fall from A to CD, AE is the altitude of the parallelogram, and also of the triangle ACD.

B

D E

If a perpendicular be let fall from B to DC produced, meeting DC in F, BF is the altitude of the parallelogram.

EXERCISES.

Prove from the definitions just given the following theo

rems:

1. All the angles of a Square are right angles.

2. All the angles of a Rectangle are right angles.

3. The diagonals of a square make with each of the sides an angle equal to half a right angle.

4. If two straight lines bisect each other, the lines joining their extremities will form a parallelogram.

5. Straight lines bisecting two adjacent angles of a parallelogram intersect at right angles.

6. If the straight lines joining two opposite angular points of a parallelogram bisect the angles, the parallelogram is a rhombus.

7. If the opposite angles of a quadrilateral be equal, the quadrilateral is a parallelogram.

8. If two opposite sides of a quadrilateral figure be equal to one another, and the two remaining sides be also equal to one another, the figure is a parallelogram.

9. If one angle of a rhombus be equal to two-thirds of two right angles, the diagonal drawn from that angular point divides the rhombus into two equilateral triangles.

PROPOSITION XXXIV. THEOREM.

The opposite sides and angles of a parallelogram are equal to one another, and the diagonal bisects it.

and

and

Let ABDC be a □, and BC a diagonal of the.

Then must AB DC and AC=DB,

▲ BAC= ▲ CDB, and ▲ ABD= 4 ACD

▲ ABC= ▲ DCB.

For AB is

to CD, and BC meets them,

.. LABC

alternate 2 DCB;

I. 29.

and AC is to BD, and BC meets them,

.. LACB alternate DBC.

Then in As ABC, DCB,

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:: LABC= L DCB, and 4 ACB= L DBC,

I. 29.

and BC is common, a side adjacent to the equals in each;

.. AB=DC, and AC=DB, and L BAC

and AABC= ▲ DCB.

LCDB,

I. B.

Also

L ABC= L BCD, and ▲ CBD= L ACB,

.. 48 ABC, CBD together= 48 BCD, ACB together, that is, ABD= ▲ ACD.

I. 4.

Q. E. D.

Ex. 1. Shew that the diagonals of a parallelogram bisect each other.

Ex. 2. Shew that the diagonals of a rectangle are equal. Ex. 3. Prove that the four triangles, into which a parallelogram is divided by its diagonals, are equal to each other.

PROPOSITION XXXV. THEOREM.

Parallelograms on the same base and between the same parallels are equal.

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Let the s ABCD, EBCF be on the same base BC, and between the same s AF, BC.

[blocks in formation]

CASE I. If there be a space between the sides AD, EF.

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Now

ABCD with ▲ FDC=figure ABCF;

and EBCF with ▲ EAB=figure ABCF;

ABCD with ▲ FDC=□EBCF with ▲ EAB;

CASE II.

thus:

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If the sides AD, EF overlap one another,

ED F

the same method of proof applies.

CASE III. If the sides opposite to BC be terminated in the same point D, thus:

B

the same method of proof is applicable,
but it is easier to reason thus:

Each of the s is double of ▲ BDC;

ABCD=DBCF.

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I. 34.

Q. E.D.

Parallelograms on equal bases, and between the same parallels, are equal to one another.

[blocks in formation]

Let the s ABCD, EFGH be on equal bases BC, FG, and between the same s AH, BG.

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they are on the same base BC and between the same ||s;

and

EBCH=□EFGH,

I. 35.

they are on the same base EH and between the same s ;

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