First Course in Algebra, Βιβλίο 1Macmillan, 1919 - 334 σελίδες |
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Σελίδα 39
... 18. ) WRITTEN EXERCISES Simplify each of the following expressions . 1. 2-6 + 4-3-2 . 3. 1-2 + 3-4 + 5-6 + 7 . 2. 2 + 4-6 + 7 + 3 . ---- 4. 1 + ( - 2 ) ( − 3 ) +4 . 5. 2 - ( - 3 ) + ( - 4 ) - ( - 6 ) -7 . 6. 25-30 + 17-21-45 . 7 ...
... 18. ) WRITTEN EXERCISES Simplify each of the following expressions . 1. 2-6 + 4-3-2 . 3. 1-2 + 3-4 + 5-6 + 7 . 2. 2 + 4-6 + 7 + 3 . ---- 4. 1 + ( - 2 ) ( − 3 ) +4 . 5. 2 - ( - 3 ) + ( - 4 ) - ( - 6 ) -7 . 6. 25-30 + 17-21-45 . 7 ...
Σελίδα 50
... Simplify the following expressions by uniting terms . 1. 6x - 2x + 4x - 7x + 10x . [ HINT . This is the same as 6 x + ( − 2 x ) +4 x + ( − 7 x ) +10 x . ] 2. -2b + 3b + 7b - b - 7b . 3. 6 ar - 7 ar + 15 ar - 2 ar - ar . 4. 11 x1y - 2 ...
... Simplify the following expressions by uniting terms . 1. 6x - 2x + 4x - 7x + 10x . [ HINT . This is the same as 6 x + ( − 2 x ) +4 x + ( − 7 x ) +10 x . ] 2. -2b + 3b + 7b - b - 7b . 3. 6 ar - 7 ar + 15 ar - 2 ar - ar . 4. 11 x1y - 2 ...
Σελίδα 64
... simplified in either of two ways : ( 1 ) By getting the value of the part in parentheses and adding it to 10. Thus , 10+ ( 6 + 2 ) = 10 + 8 = 18 . ( 2 ) By removing the parentheses and simplifying the 64 [ IV , § 39 FIRST COURSE IN ALGEBRA.
... simplified in either of two ways : ( 1 ) By getting the value of the part in parentheses and adding it to 10. Thus , 10+ ( 6 + 2 ) = 10 + 8 = 18 . ( 2 ) By removing the parentheses and simplifying the 64 [ IV , § 39 FIRST COURSE IN ALGEBRA.
Σελίδα 65
Walter Burton Ford, Charles Ammerman. ( 2 ) By removing the parentheses and simplifying the result thus obtained . Thus , 10+ ( 6 + 2 ) = 10 + 6 + 2 = 18 . Other illustrations , which should be carefully examined , follow . 2+ ( 4-1 ) ...
Walter Burton Ford, Charles Ammerman. ( 2 ) By removing the parentheses and simplifying the result thus obtained . Thus , 10+ ( 6 + 2 ) = 10 + 6 + 2 = 18 . Other illustrations , which should be carefully examined , follow . 2+ ( 4-1 ) ...
Σελίδα 67
... Simplify 8a- [ 3b + 4 a + ( − a + 2b ) ] . SOLUTION . The rule of § 40 gives 8 a- [ 3 b + 4 a + ( − a + 2 b ) ... Simplify each of the following expressions by removing all the signs of grouping . - 1. a- ( 2a + 4a ) — ( 5a + 10 ) . 2 ...
... Simplify 8a- [ 3b + 4 a + ( − a + 2b ) ] . SOLUTION . The rule of § 40 gives 8 a- [ 3 b + 4 a + ( − a + 2 b ) ... Simplify each of the following expressions by removing all the signs of grouping . - 1. a- ( 2a + 4a ) — ( 5a + 10 ) . 2 ...
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a²+2 ab+b² added algebra Appendix arithmetic Axiom ball called cents check your answer coefficient common denominator common factor common multiple completing the square cube diameter divisor Draw the graph equal EXAMPLE EXERCISES Solve figure Find the L. C. M. Find the number Find the value following equations following exercises following expressions fraction further exercises given equation gives highest common factor HINT illustrated inches length lowest common means metic miles an hour minuend monomial multiply negative numbers numerator and denominator ORAL EXERCISES parentheses perfect square polynomial quadratic quadratic equation quotient radicand radius ratio represents result Similarly Simplify simultaneous equations SOLUTION Solve the equation square root subtract subtrahend SUPPLEMENTARY EXERCISES surd triangle trinomial unknown letter weight wheel write WRITTEN EXERCISES x²y² yards
Δημοφιλή αποσπάσματα
Σελίδα 17 - The square of the hypotenuse of a right triangle is equal to the sum of the squares of the other two sides.
Σελίδα 235 - Then divide the first term of the remainder by the first term of the divisor...
Σελίδα 228 - A and B can do a piece of work in 10 days, A and C in 12 days, and В and C in 20 days.
Σελίδα 97 - Prove that the square of the sum of any two numbers equals the square of the first number, plus twice the product of the two numbers, plus the square of the second number.
Σελίδα 136 - Both terms of a fraction may be divided by the same number without changing the value of the fraction.
Σελίδα 232 - Find the greatest square in the left-hand period and write its root for the first figure of the required root. Square this root, subtract the result from the left-hand period, and to the remainder annex the next period for a dividend.
Σελίδα 232 - ... subtract the product from the dividend, and to the remainder annex the next period for the next dividend.
Σελίδα 98 - That is, the square of the difference of two numbers is equal to the square of the first number, minus twice the product of the two numbers, plus the square of the second number.
Σελίδα 69 - Any term may be transposed from one side of an equation to the other provided its sign be changed.
Σελίδα 235 - Arrange the terms of the polynomial with reference to the consecutive powers of some letter. Extract the square root of the first term, write the result as the first term of the root, and subtract its square from the given polynomial.