Elements of Geometry;: Containing the First Six Books of Euclid, with Two Books on the Geometry of Solids. To which are Added, Elements of Plane and Spherical TrigonometryBell & Bradfute, and G. G. & J. Robinson, London., 1795 - 400 σελίδες |
Αναζήτηση στο βιβλίο
Αποτελέσματα 1 - 5 από τα 10.
Σελίδα 72
... join AD , DB and DE , and let DE , meet the circumference in F. Then 30 11 : D because DA is equal to DB , the A E B a 5. 1 . angle DAB is equala to the angle DBA ; and because AE , a fide of F b 16. 1 . C 19. 1 . the triangle DAE , is ...
... join AD , DB and DE , and let DE , meet the circumference in F. Then 30 11 : D because DA is equal to DB , the A E B a 5. 1 . angle DAB is equala to the angle DBA ; and because AE , a fide of F b 16. 1 . C 19. 1 . the triangle DAE , is ...
Σελίδα 80
... joins the centres F , G , being produced , passes through the point A. H D G F E B For , if not , let it fall otherwise , if poffible , as FGDH , and join AF , AG : and because AG , GF are greater a than FA , that is , than FH , før FA ...
... joins the centres F , G , being produced , passes through the point A. H D G F E B For , if not , let it fall otherwise , if poffible , as FGDH , and join AF , AG : and because AG , GF are greater a than FA , that is , than FH , før FA ...
Σελίδα 81
... joins the points F , G shall pass through the point of contact A. For , if not , let it pass otherwise , if poffible , as FCDG , and join FA , AG : and because F is the centre of the circle ABC , AF is equal to FC : Alfo because Gis B ...
... joins the points F , G shall pass through the point of contact A. For , if not , let it pass otherwise , if poffible , as FCDG , and join FA , AG : and because F is the centre of the circle ABC , AF is equal to FC : Alfo because Gis B ...
Σελίδα 96
... join BC , EF : the fstraight line BC is equal to the straight line GF . Take a K , L the centres of the circles , and join BK , KC , EL , LF : and because the circumference BGC is equal to the b 27. 3. circumference EHF , the angle BKC ...
... join BC , EF : the fstraight line BC is equal to the straight line GF . Take a K , L the centres of the circles , and join BK , KC , EL , LF : and because the circumference BGC is equal to the b 27. 3. circumference EHF , the angle BKC ...
Σελίδα 157
... joins the vertices is parallel to that in which their bases are f , f 33. 1 . because the perpendiculars are both ... Join BE , CD ; then the triangle BDE is equal to the triangle CDE , because they are on the same base DE , and ...
... joins the vertices is parallel to that in which their bases are f , f 33. 1 . because the perpendiculars are both ... Join BE , CD ; then the triangle BDE is equal to the triangle CDE , because they are on the same base DE , and ...
Άλλες εκδόσεις - Προβολή όλων
Συχνά εμφανιζόμενοι όροι και φράσεις
ABCD alfo alſo angle ABC angle ACB angle BAC arch baſe baſe BC BC is equal becauſe becauſe the angle biſected Book VII caſe cauſe centre circle ABC circumference co-fine demonſtrated deſcribed diameter drawn equal angles equiangular equilateral polygon equimultiples Euclid exterior angle fame reaſon fides fimilar fince firſt folid fore given ſtraight line greater inſcribed interfect join leſs Let ABC line BC magnitudes oppoſite parallel parallelepiped parallelogram paſs perpendicular plane polygon priſm proportionals propoſition Q. E. D. PROP radius rectangle contained rectilineal figure remaining angle right angles ſame ſame baſe ſame manner ſame ratio ſecond ſection ſegment ſemicircle ſhall ſhall be equal ſhewn ſide ſolid ſpace ſpherical triangle ſquare of AC ſtand ſuch ſum ſuppoſed tangent THEOR theſe thoſe touches the circle triangle ABC wherefore
Δημοφιλή αποσπάσματα
Σελίδα 27 - If two triangles have two angles of the one equal to two angles of the other, each to each, and one side equal to one side, viz. either the sides adjacent to the equal...
Σελίδα 165 - If two triangles have one angle of the one equal to one angle of the other and the sides about these equal angles proportional, the triangles are similar.
Σελίδα 18 - If, at a point in a straight line, two other straight lines upon the opposite sides of it, make the adjacent angles, together equal to two right angles, these two straight lines shall be in one and the same straight line.
Σελίδα 9 - Wherefore, from the given point A, a straight line AL has been drawn equal to the given straight line BC.
Σελίδα 3 - A circle is a plane figure contained by one line, which is called the circumference, and is such that all straight lines drawn from a certain point within the figure to the circumference, are equal to one another.
Σελίδα 33 - Therefore all the angles of the figure, together with four right angles, are equal to twice as many right angles as the figure has sides.
Σελίδα 12 - ABC: and it has also been proved that the angle FBC is equal to the angle GCB, which are the angles upon the other side of the base. Therefore the angles at the base, &c.
Σελίδα 6 - Let it be granted that a straight line may be drawn from any one point to any other point.
Σελίδα 166 - But by the hypothesis, it is less than a right angle ; which is absurd. Therefore the angles ABC, DEF are not unequal, that is, they are equal : And the angle at A is equal to the angle at D ; wherefore...
Σελίδα 54 - If a straight line be bisected, and produced to any point ; the rectangle contained by the whole line thus produced, and the part of it produced...