 | George Albert Wentworth - 1888 - 264 σελίδες
...§179 .-. 0 is the centre of symmetry of the figure. § 64 EXERCISES. 34. The median from the vertex to the base of an isosceles triangle is perpendicular to the base, and bisects the vertical angle. 35. State and prove the converse. 36. The bisector of an exterior angle... | |
 | Wooster Woodruff Beman, David Eugene Smith - 1899 - 416 σελίδες
...and substitute the definition for the name of the thing defined. Eg suppose it is to be proved that the median to the base of an isosceles triangle is perpendicular to the base. Instead of saying : " Given CMfthe median to the base of the isosceles triangle ABC " (see figure on... | |
 | Wooster Woodruff Beman, David Eugene Smith - 1899 - 265 σελίδες
...and substitute the definition for the name of the thing defined. Eg suppose it is to be proved that the median to the base of an isosceles triangle is perpendicular to the base. Instead of saying : " Given CM the median to the base of the isosceles triangle ABC " (see figure on... | |
 | Charles Austin Hobbs - 1899 - 266 σελίδες
...angle of 45°. Ex. 27. To divide an angle into four equal parts. Ex. 28. The median from the vertex to the base of an isosceles triangle is perpendicular to the base, and bisects the vertical angle. Ex. 29. .4BCand DBC are isosceles triangles on the same base ; prove... | |
 | George Albert Wentworth - 1899 - 278 σελίδες
...OC, and BO = OE, § 128 (being homologous sides of equal A). QED Ex. 13. The median from the vertex to the base of an isosceles triangle is perpendicular to the base, and bisects the vertical angle. Ex. 14. If two straight lines are cut by a transversal so that the... | |
 | George Albert Wentworth - 1899 - 496 σελίδες
...OC, and BO = OE, § 128 (being homologous sides of equal &). QED Ex. 13. The median from the vertex to the base of an isosceles triangle is perpendicular to the base, and bisects the vertical angle. Ex. 14. If two straight lines are cut by a transversal so that the... | |
 | Arthur Schultze - 1901 - 392 σελίδες
...= Z 4, (6ase /* of an isos. A). Z3 = Z2 + Z4, (Ax. 2.) AA'B'C' = («. as = sas). .-. AABC=AA'B'C'. QED Ex. 117. If the opposite sides of a quadrilateral...parallel. Ex. 122. If in the sides of an equilateral A ABC, the points D, E, and F be taken so that AD = BE = CF, then A DFE is equilateral. Ex. 123. If... | |
 | Arthur Schultze, Frank Louis Sevenoak - 1902 - 394 σελίδες
...isos. A). :-. Z1 + Z3 = Z2 + Z4, ZBAC=ZB'A'CI. .: AA'B'C' = AAB'C', (sas — sas). (Hyp.) (Ax. 2.) Ex. 117. If the opposite sides of a quadrilateral...parallel. Ex. 122. If in the sides of an equilateral A ABC, the points D, E, and F be taken so that AD = BE = CF, then A DFE is equilateral. Ex. 123. If... | |
 | Arthur Schultze - 1901 - 260 σελίδες
...(6ose /io/ an isos. A). Z1+Z3 = Z2 + Z4, (Ax. 2.) te . AA'B'C' = AAB'C', (sas = sas). .-. AABC=AA'B'C'. Ex. 117. If the opposite sides of a quadrilateral...parallel. Ex. 122. If in the sides of an equilateral A ABC, the points D, E, and F be taken so that AD = BE= CF, then &DFE is equilateral. E Ex. 123. If... | |
 | Arthur Schultze, Frank Louis Sevenoak - 1901 - 394 σελίδες
...AB' = A'B', and AC' = A'C'. (Hyp.) . Z 1 = Z 2, and Z 3 = Z 4, (base A of an isos. A). Z3 = Z2 + Z4, (Ax. 2.) AA'B'C' = AAB'C', (sas = sas). .: A ABC =...sides are equal. Ex. 120. The medians to the arms of au isosceles triangle are equal. Ex. 121. If the opposite sides of a quadrilateral are equal, the sides... | |
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The median to the base of an isosceles triangle is perpendicular to the base. 
