Mensuration and Practical Geometry: Containing Tables of Weights and Measures, Vulgar and Decimal Fractions, Mensuration of Areas, Lines, Surfaces, and Solids ... To which is Appended a Treatise on the Carpenter's Slide-rule and GaugingHarper & brothers, 1858 - 322 σελίδες |
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Σελίδα 14
... gallon . 4 gills = 1 pint . 2 gallons 1 peck . 2 pints = 1 quart . 4 pecks 1 bushel . MISCELLANEOUS . - 1 chaldron 36 bushels , or 57.244 cubic feet , when heaped in the form of a cone . NOTE . The standard U. S. bushel is the ...
... gallon . 4 gills = 1 pint . 2 gallons 1 peck . 2 pints = 1 quart . 4 pecks 1 bushel . MISCELLANEOUS . - 1 chaldron 36 bushels , or 57.244 cubic feet , when heaped in the form of a cone . NOTE . The standard U. S. bushel is the ...
Σελίδα 15
... gallons . 128 feet - 1 cord . 24.75 66-1 perch . Foreign . FRANCE . Stere ( 1 cubic metre ) = 61027.1 U. S. inches , or 35.3166 cubic feet . NOTE . For the solid measures of other foreign countries , take the cube of the measures given ...
... gallons . 128 feet - 1 cord . 24.75 66-1 perch . Foreign . FRANCE . Stere ( 1 cubic metre ) = 61027.1 U. S. inches , or 35.3166 cubic feet . NOTE . For the solid measures of other foreign countries , take the cube of the measures given ...
Σελίδα 213
... gallons , and each gallon 231 cubic inches ? Ans . { S16292571 hhds . 42 galls . 3 qts . 0 pts . 3.43 gills , or 217800000 cubic feet . 19. The ditch of a fortification is 1000 feet long , 9 feet deep , 20 feet broad at bottom , and 22 ...
... gallons , and each gallon 231 cubic inches ? Ans . { S16292571 hhds . 42 galls . 3 qts . 0 pts . 3.43 gills , or 217800000 cubic feet . 19. The ditch of a fortification is 1000 feet long , 9 feet deep , 20 feet broad at bottom , and 22 ...
Σελίδα 217
... gallons in 1 hour . 66 1 66 66 1 66 Hence , 110 gallons : 1 hour :: 60 gallons : .5454 hours = 32 minutes , 43 seconds , and 26 thirds = the result required . 49. A reservoir has three pipes ; the first can fill it in 12 days , the ...
... gallons in 1 hour . 66 1 66 66 1 66 Hence , 110 gallons : 1 hour :: 60 gallons : .5454 hours = 32 minutes , 43 seconds , and 26 thirds = the result required . 49. A reservoir has three pipes ; the first can fill it in 12 days , the ...
Σελίδα 218
... gallons ; the supply pipe gives 14 gallons in 9 minutes ; the tap discharges 40 gallons in 31 minutes ; now , supposing the tap , the tub being empty , to be carelessly left open , and the water to be turned on at 2 o'clock in the ...
... gallons ; the supply pipe gives 14 gallons in 9 minutes ; the tap discharges 40 gallons in 31 minutes ; now , supposing the tap , the tub being empty , to be carelessly left open , and the water to be turned on at 2 o'clock in the ...
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Συχνά εμφανιζόμενοι όροι και φράσεις
12 inches 15 feet 20 feet 20 inches abscissa acres angle ascertain the Area ascertain the Contents base breadth cask Centre of Gravity chord of half Circular Spindle circumference cone conic section contents in cubic contents required convex surface cube cubic feet cubic foot cubic inches curve cycloid cylinder decimals diam divided equal eter EXAMPLE EXAMPLE.-The diameter EXAMPLE.-What figure fraction gauge point geometrical centre give the contents half the arc head diameter Hence hexahedron hyperbola hyperboloid Hyperboloid of Revolution inches in diameter inscribed sphere length less diameter linear edge Loomis's middle diameter middle frustrum miles multiply the sum ordinate parabolic spindle perpendicular prism product will give prolate spheroid pyramid quired quotient radii radius remainder result required rule sector segment slant height spherical square root subtract surface required transverse diameter triangle ungula versed sine vertex volume VULGAR FRACTIONS yards zone
Δημοφιλή αποσπάσματα
Σελίδα 45 - The circumference of every circle is supposed to be divided into 360 equal parts, • called degrees, each degree into 60 minutes, and each minute into 60 seconds, etc.
Σελίδα 22 - To reduce a compound fraction to an equivalent simple one. RULE. — Multiply all the numerators together for a numerator, and all the denominators together for the denominator, and they will form the simple fraction sought.
Σελίδα 22 - To reduce a whole number to an equivalent fraction, having a given denominator. RULE. Multiply the whole number by the given denominator, and place the product over the said denominator, and it will form the fraction required.
Σελίδα 22 - To reduce an improper fraction to its equivalent whole or mixed number. RULE. — Divide the numerator by the denominator, and the quotient will be the whole or mixed number sought.
Σελίδα 31 - ... from the right hand of the quotient, point off so many places for decimals, as the decimal places in the dividend exceed those in the divisor.
Σελίδα 39 - Multiply the divisor, thus augmented, by the last figure of the root, and subtract the product from the dividend, and to the remainder bring down the next period for a new dividend.
Σελίδα 20 - Divide by any number that will divide two or more of the given numbers without a remainder, and set the quotients, together with the undivided numbers, in a line beneath.
Σελίδα 69 - ... troublesome and laborious that it must have cost him incredible pains. It is said to have been thought so curious a performance, that the numbers were cut on his tomb-stone in St. Peter's Church-yard at Leyden.
Σελίδα 84 - FIND the area of the sector having the same arc with the segment, by the last problem. Find also the area of the triangle, formed by the chord of the segment and the two radii of the sector.