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XIII. MISCELLANEOUS EXERCISES IN ADDITION AND SUBTRACTION OF COMPOUND NUMBERS.

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| XIV. MULTIPLICATION OF COMPOUND NUM

BERS. ART. 104. MULTIPLICATION of Compound Numbers is the process of taking a compound number any proposed number of times.

Art. 105. To multiply when the multiplier is not more than 12.

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OPERATION.

We write the multiplier under £. 8. d. far. the

tar. the lowest denomination of the Multiplicand 14 5 8 2 multipl

multiplicand, and then say 9 Multiplier

9 times 2far. are 18far., equal to

- 4d. and 2far. We set down the Product 128 11 4 2 2far. under the number mul

tiplied, reserving the 4d. to be added to the next product. We then say 9 times 8d. are 72d., and the 4d. make 76d., equal to 6s. and 4d., and set the 4d. under the column of pence, reserving the 6s. to be added to the next product. Then, 9 times 58. are 458., and 6s. make 51s., equal to 2£. and 1 ls. We place the 1ls. under the column of shillings, reserving the 2£. to be added to the next product. Again, 9 times 14£. are 126£., and 2£. make 128£. This, placed under the column of pounds, gives us 128£. lls. 4d. 2far. for the answer.

QUESTIONS. — Art. 104. What is multiplication of compound numbers ? - Art. 105. Explain the operation. By what do you divide the product of each denomination? What do you do with the quotient and remainders thus obtained ?

RrLE. — Multiply each denomination of the compound number as in multiplication of simple numbers, and carry as in addition of compouna nuinbers.

NOTE. — Going a second time carefully over the work is a good way of testing its accuracy. On learning Division of Compound Numbers, the pupil will find that rule a better method of proving multiplication of compound numbers.

EXAMPLES FOR PRACTICE.
3.

4.

- 2.

iu ii 25 17 i 18 is si 1013 4 58 14 120 0 7 112 11 4

10 13 4

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5 12 103 11 0

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12.

pentru si

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13. rd. yd. ft. in. 3 2 9

9 213 2 0 9

98 0 4 2 NOTE. — The answers to the following questions are found in the corresponding questions in Division of Compound Numbers, p. 128.

14. What cost 7 yards of cloth at 18s. 9d. per yard ?

15. If a man travel 12m. 3fur. 29rd. in one day, how far will he travel in 9 days ?

16. If 1 acre produce 2 tons 13cwt. 191b. of hay, what will 8 acres produce ?

QUESTIONS. — What is the rule? How may the work be tested ?

17. If a family consume 49gal. 3qt. 1pt. of molasses in one month, what quantity will be sufficient for one year ?

18. John Smith has 12 silver spoons, each weighing 3oz. 17pwt. 14gr. ; what is the weight of all ?

19. Samuel Johnson bought 7 loads of timber, each measuring 7 tons 37ft. ; what was the whole quantity ?

20. If the moon move in her orbit 13° 11' 35" in 1 day, how far will she move in 10 days ?

21. If 1 dollar will purchase 21h 83 73 13 10gr. of ipecacuanha, what quantity would 9 dollars buy?

22. If i dollar will buy 2A. 3R. 15p. 30yd. 8ft. 100in. of wild land, what quantity may be purchased for 12 dollars ?

23. Joseph Doe will cut 2 cords 97ft. of wood in 1 day; how much will he cut in 9 days ?

24. If 1 acre of land produce 3ch. 6bu. 2pk. 7qt. lpt. of corn, what will 8 acres produce ?

ART. 106. When the multiplier is a composite number, and none of its factors exceed 12. Ex. 1. What cost 24 yards of broadcloth at 2£. 7s. 11d. per

Ans. 57£. 10s. Od.

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OPERATION. £. 8. d.

2 7 11 = price of 1 yard.

We find the number 24 equal to the product of 4 and

6; we therefore multiply the 911 8= price of 4 yards. price first by 4, and then that 6

product by 6, and the last

product is the answer. 57 10 0= price of 24 yards. Ex. 2. What cost 360 tons of iron at 17£. 169. 1d. per ton ?

Ans. 6409£. 10s. Od.

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d.
1=price of 1 ton.

We find the factors of

360 to be 6, 6, and 10. We 6=price of 6 tons. first multiply by 6, and then

that product by 6, and then

again the last product by (=price of 36 tons. 10.

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