Norris's Hand-book for Locomotive Engineers and Machinists ...H. C. Baird, 1854 - 302 σελίδες |
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Σελίδα 102
... angle with the base , through both sides of the cone . The Hyperbola , by cutting through one side and the base parallel to the axis , or at a greater angle with the base than that made by the opposite side . The opposite Hyperbola is ...
... angle with the base , through both sides of the cone . The Hyperbola , by cutting through one side and the base parallel to the axis , or at a greater angle with the base than that made by the opposite side . The opposite Hyperbola is ...
Σελίδα 103
... angles to it . A Diameter is a right line drawn through the centre , in any direction , and terminated at each end by the curve . A Conjugate Diameter is a line drawn through the centre of any diameter , parallel to the tangent of the ...
... angles to it . A Diameter is a right line drawn through the centre , in any direction , and terminated at each end by the curve . A Conjugate Diameter is a line drawn through the centre of any diameter , parallel to the tangent of the ...
Σελίδα 105
... angle , when the lengths of the other two sides are given . RULE 1. - To find the hypothenuse , a c , fig . 7 , add together the squares of the two legs , a b and b c , and extract the square root of that sum . RULE 2. - To find one of ...
... angle , when the lengths of the other two sides are given . RULE 1. - To find the hypothenuse , a c , fig . 7 , add together the squares of the two legs , a b and b c , and extract the square root of that sum . RULE 2. - To find one of ...
Σελίδα 106
... angles , by the diagonal a c , and let two perpendicu- lars , bf , and de , fall on the diagonal from the opposite angles ; then , the sum of these perpendicu- lars multiplied by the diagonal , and divided by 2 , will be the area of the ...
... angles , by the diagonal a c , and let two perpendicu- lars , bf , and de , fall on the diagonal from the opposite angles ; then , the sum of these perpendicu- lars multiplied by the diagonal , and divided by 2 , will be the area of the ...
Σελίδα 145
... angles in the pipes . These should , therefore , be made as straight , and their internal surface as uniform and free from inequalities as may be practicable . The following proportions of velocity , from Mr. Tredgold , will exemplify ...
... angles in the pipes . These should , therefore , be made as straight , and their internal surface as uniform and free from inequalities as may be practicable . The following proportions of velocity , from Mr. Tredgold , will exemplify ...
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abscissa Atmospheric Railway avoirdupois axle blast-pipe boiler brass centre circle circular segments Circum circumference cloth coke conjugate connecting-rod copper crank Cube Root cubic feet cubic foot cubic inch curve cylinder cylinder in inches Dauphiny Decimal or Reciprocal diame diameter distance driving wheels eccentric-rod equal EXAMPLE.-Required find the Area find the Solidity fire-box Fraction or Numb friction Frustum fulcrum fulcrum and valve Gallons gauge give the solidity Height Length horses Hyperbola iron Length of Arc leverage locomotive engine metallic mile morocco motion multiply the sum North Shields ordinate Ounces Parabola pipes piston piston-rod plates Pounds pressure quotient radius rails Railway resistance revolving axis RULE RULE.-Multiply RULE.-To find screw segment shaft side smoke-box spindle square inch Square Root steam stroke subtract thickness throw tion tons trapezium tubes valve velocity Volume whole weight yards Zone