Arithmetic, embracing all the rules simple and compound1878 |
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Σελίδα 36
... horses , £ 2341 , 9s . 6d .; pigs , £ 91 , 3s . 8d .; poultry , geese , ducks , and fowls , £ 50 , 9s . 4d .; sundry stock , £ 341 , 7s . 11d .; find the total value . 9. A market gardener sent into Sydney during the summer and autumn ...
... horses , £ 2341 , 9s . 6d .; pigs , £ 91 , 3s . 8d .; poultry , geese , ducks , and fowls , £ 50 , 9s . 4d .; sundry stock , £ 341 , 7s . 11d .; find the total value . 9. A market gardener sent into Sydney during the summer and autumn ...
Σελίδα 72
... horses take to plough a field if 3 horses can do it in 8 da . ? 19. A person travelling at the rate of 14 m . a day can perform a journey in 24 da .; in how many days would he perform it at the rate of 21 m . a day ? 20. If 7 railway ...
... horses take to plough a field if 3 horses can do it in 8 da . ? 19. A person travelling at the rate of 14 m . a day can perform a journey in 24 da .; in how many days would he perform it at the rate of 21 m . a day ? 20. If 7 railway ...
Σελίδα 73
... horses , and say , Will 18 horses cost more or less to keep than 21 ? Ans . Less ; therefore less , or 18 , is put for the middle term , and 21 for the first . ( 3. ) Going on from the 18 we come to 42 days , and say , Will the keep of ...
... horses , and say , Will 18 horses cost more or less to keep than 21 ? Ans . Less ; therefore less , or 18 , is put for the middle term , and 21 for the first . ( 3. ) Going on from the 18 we come to 42 days , and say , Will the keep of ...
Σελίδα 74
... horses in 10 days eat 6 quarters of oats , how many quarters will 28 consume in 20 days ? Here 42 horses in 10 days consume Then 1 horse in 10 days consumes 6 quarters . 6 42 6 Then 1 horse in day consumes 42 × 10 6 × 28 Hence 28 horses ...
... horses in 10 days eat 6 quarters of oats , how many quarters will 28 consume in 20 days ? Here 42 horses in 10 days consume Then 1 horse in 10 days consumes 6 quarters . 6 42 6 Then 1 horse in day consumes 42 × 10 6 × 28 Hence 28 horses ...
Σελίδα 75
Henry Evers. Or more briefly thus : Here 42 horses in 10 days consume Then 1 horse in 1 day consumes- Then 28 horses in 20 days consume 6 quarters of oats . 6 42 × 10 4 6 × 28 × 20 48 × 48 = 8 quarters . EXPLANATION OF THE ABOVE METHOD ...
Henry Evers. Or more briefly thus : Here 42 horses in 10 days consume Then 1 horse in 1 day consumes- Then 28 horses in 20 days consume 6 quarters of oats . 6 42 × 10 4 6 × 28 × 20 48 × 48 = 8 quarters . EXPLANATION OF THE ABOVE METHOD ...
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Arithmetic Embracing All the Rules Simple and Compound Henry Evers Δεν υπάρχει διαθέσιμη προεπισκόπηση - 2019 |
Arithmetic Embracing All the Rules Simple and Compound Henry Evers Δεν υπάρχει διαθέσιμη προεπισκόπηση - 2019 |
Συχνά εμφανιζόμενοι όροι και φράσεις
acres added aliquot amount annum answer ARITHMETIC Avoirdupois bill carry cloth column common cost cubic cyphers decimal fractions decimal point denominator divide dividend division divisor EXERCISES Express farthings Fcap feet figure Find the simple Find the sum Find the value gain gallons gals give goes guineas halfpenny hence horses hundred hundredweights improper fractions inches least common multiple lowest terms MEASURE method miles millions mixed number months multiply nine noughts ounces pence pounds present value profit quantity quarters quotient rate per cent recurring decimals Reduce remainder right hand Rule of Three sheep shillings simple interest sold square root subtract sugar tens thousands tons 17 cwt top line TROY WEIGHT units vulgar fractions weight whole number worth yard
Δημοφιλή αποσπάσματα
Σελίδα 12 - Thirty days hath September, April, June, and November ; All the rest have thirty-one, Except the second month alone, Which has but twenty-eight, in fine, Till leap year gives it twenty-nine.
Σελίδα 99 - To reduce a mixed number to an improper fraction. Multiply the whole number by the denominator of the fraction, and to the product add the given numerator.
Σελίδα 105 - Multiply the numerators together for a new numerator, and the denominators together for a new denominator.
Σελίδα 94 - The greatest common divisor of two or more numbers is the greatest number that will divide each of them without a remainder. Thus 6 is the greatest common divisor of 12, 18, and 24.