Improvement to Palmer's Endless Self-computing Scale and Key: Adapting it to the Different Professions, with Examples and Illustrations for Each Profession; and Also to Colleges, Academies and Schools, with a Time Telegraph, Making, by Uniting the Two, a Computing Telegraphpublisher, 1846 - 72 σελίδες |
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Σελίδα 13
... RULE . First find the multiplier on the circular . Place it opposite 1 , then opposite the multiplicand found on the fixed part , is the product on the circular . Example . - What is the product of 4 by 2 ? Place 2 opposite 1 : then ...
... RULE . First find the multiplier on the circular . Place it opposite 1 , then opposite the multiplicand found on the fixed part , is the product on the circular . Example . - What is the product of 4 by 2 ? Place 2 opposite 1 : then ...
Σελίδα 14
... Place 3 opposite 1 , then opposite 13 ( found be tween the large 1 and 2 ) is 39 , the answer . What is the product ... RULE . Find the divisor on the circular . Place it opposite 1 : then opposite the dividend , found also on the ...
... Place 3 opposite 1 , then opposite 13 ( found be tween the large 1 and 2 ) is 39 , the answer . What is the product ... RULE . Find the divisor on the circular . Place it opposite 1 : then opposite the dividend , found also on the ...
Σελίδα 15
... Place 3 opposite 1 : then opposite 12 is 4 , the answer . How many times 4 in 14 ? Place 4 opposite 1 : then ... RULE . - Place the multiplier on the circular oppo- site the divisor : then , opposite the multiplicand is the result ...
... Place 3 opposite 1 : then opposite 12 is 4 , the answer . How many times 4 in 14 ? Place 4 opposite 1 : then ... RULE . - Place the multiplier on the circular oppo- site the divisor : then , opposite the multiplicand is the result ...
Σελίδα 16
... Place 83 opposite 6 : then opposite 1 is $ 13 83 , the answer . In of a dollar how many dollars ? Place 8 opposite 4 : then opposite 1 is $ 2 , the answer . TO REDUCE A MIXED NUMBER TO AN IMPROPER FRACTION . RULE . Place the mixed ...
... Place 83 opposite 6 : then opposite 1 is $ 13 83 , the answer . In of a dollar how many dollars ? Place 8 opposite 4 : then opposite 1 is $ 2 , the answer . TO REDUCE A MIXED NUMBER TO AN IMPROPER FRACTION . RULE . Place the mixed ...
Σελίδα 17
... Place 12 opposite 16 : now 9 is opposite 12 ( † ) 6 is opposite 8 ( § , ) and 3 is opposite 4 ( , ) the answer . TO DIVIDE A FRACTION BY A WHOLE NUMBER . RULE . - Place the whole number found on the cir- cular opposite 1 : then opposite ...
... Place 12 opposite 16 : now 9 is opposite 12 ( † ) 6 is opposite 8 ( § , ) and 3 is opposite 4 ( , ) the answer . TO DIVIDE A FRACTION BY A WHOLE NUMBER . RULE . - Place the whole number found on the cir- cular opposite 1 : then opposite ...
Άλλες εκδόσεις - Προβολή όλων
Improvement to Palmer's Endless Self-Computing Scale and Key: Adapting It to ... John E. Fuller Δεν υπάρχει διαθέσιμη προεπισκόπηση - 2017 |
Improvement to Palmer's Endless Self-Computing Scale and Key: Adapting It to ... John E. Fuller Δεν υπάρχει διαθέσιμη προεπισκόπηση - 2018 |
Improvement to Palmer's Endless Self-Computing Scale and Key: Adapting It to ... John E Fuller Δεν υπάρχει διαθέσιμη προεπισκόπηση - 2015 |
Συχνά εμφανιζόμενοι όροι και φράσεις
12 inches 14 opposite Aaron Palmer acre amount answer in feet avoirdupois ball circular inch circular opposite circumference COMPUTE INTEREST cubic inches cylinder decimal diam diameter opposite Dodecagon ENDLESS SELF-COMPUTING SCALE Example Example.-A Example.-What feet long find the Area FIND THE SOLID fixed FRUSTRUM fulcrum gauge point given diameter given number horse-power inches diameter inches in diameter inclined plane Inscribed Circles lever Nonagon number of days numerator found oppo opposite 12 opposite 365 opposite 50 opposite 9 opposite any diameter opposite fig opposite the denominator opposite the gauge opposite the given opposite the length opposite the number ounces piston Place 14 Place 2 opposite Place 7 opposite Place this opposite point for days pounds pressure raised rate per cent rods RULE RULE.-Place SCALE AND KEY screw set of three-throw shillings side sized figures solid contents specific gravity square inch square root triangle Undecagon vulgar fraction weight WHOLE NUMBER
Δημοφιλή αποσπάσματα
Σελίδα 2 - District Clerk's Office. BE IT REMEMBERED, That on the seventh day of May, AD 1828, in the fifty-second year of the Independence of the UNITED STATES OF AMERICA, SG Goodrich, of the said District, has deposited in this office the title of a book, the right whereof he claims as proprietor, in the words following...
Σελίδα 70 - The breadth of the back or head of the wedge being three inches, and the length of either of its inclined sides 10 inches, required the power necessary to separate two substances with a force of 150 Ibs; As 10 : 1 1-2 :: 150 : 22 1-2 Ibs., Ans.
Σελίδα 37 - Divide trie square of the given diameter by 2, and extract tJie square root of the quotient. (Art. 581. Obs. 1.) 17. The diameter of a round table is 4 ft. ; what is the side of the greatest square table which can be made from it 1 631.
Σελίδα 62 - ... 007 2. By the cooling in the cylinder and pipes 016 3. By the friction of the piston and loss .... 125 4. By the force required to expel the steam through the passages 007 5.
Σελίδα 70 - Wlten two bodies are farced from one, another by means of a wedge, in a direction parallel to its back. RULE. As the length of the wedge is to half its back or head, so is the resistance to the power. EXAMPLE. The breadth of the back or head of the wedge being 3 inches, and the length of either of its inclined sides 10 inches, required the power necessary to separate two substances with a force of 150 Ibs.
Σελίδα 60 - He found, that an engine which indicated 50 horses power, when fully loaded, showed, after the load and the whole of the machinery was thrown off, 5 horses, or one-tenth of the whole power. 2nd. 190 feet of horizontal, and 80 feet of upright shafting, with 34 bearings, whose superficial area was 3300 square inches, together with 11 pair of spur and bevel wheels, varying from 2 feet to 9 feet in diameter, required a power equal to 7'65 horses.
Σελίδα 54 - Multiply the square of the diameter of the cylinder in inches by the velocity of the piston in feet per minute, and -divide the product by 6,000 ; the quotient is the number of nominal horses power.
Σελίδα 17 - To multiply a whole number by a fraction, or a fraction by a -whole number, RULE.
Σελίδα 33 - CONTENTS OF A PYRAMID. RULE. — Multiply the area of the base by | of the perpendicular height, whether it be a square, triangular, or circular pyramid.
Σελίδα 67 - ... one-fifth of the space. The products, therefore, arising from the multiplication of the respective weights and velocities are the same. EXAMPLE 2. — A weight of 1 ton is to be raised with a lever 8 feet in length, by a man who can exert, for a short time, a force of rather more than 4 cwt. : required at what part of the lever the fulcrum must be placed ? - , = 5 : that is, the weight is to the power as 4 cwt.