Hawney's Complete Measurer: Or, The Whole Art of Measuring: Being a Plain and Comprehensive Treatise on Practical Geometry and MensurationF. Lucas, Jr. J. Robinson, printer., 1820 - 312 σελίδες |
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Σελίδα ix
... spheroid , To find the solidity of the segment of a sphe- roid , To find the solidity of the middle zone of a spheroid . · 13. To find the solidity of a parabolic conoid , 181 181 · 185 187 190 191 193 194 • 197 To find the solidity of ...
... spheroid , To find the solidity of the segment of a sphe- roid , To find the solidity of the middle zone of a spheroid . · 13. To find the solidity of a parabolic conoid , 181 181 · 185 187 190 191 193 194 • 197 To find the solidity of ...
Σελίδα 184
... SPHEROID . A spheroid is 184 Mensuration of Solids . To find the convex surface of any segment zone of a sphere,
... SPHEROID . A spheroid is 184 Mensuration of Solids . To find the convex surface of any segment zone of a sphere,
Σελίδα 185
... spheroid , and resembles a turnip , or an orange . The earth and all the planets are consi- dered as oblate spheroids . In an oblong or prolate spheroid , the shorter axis is called the revolving axis , and the longer axis the fixed ...
... spheroid , and resembles a turnip , or an orange . The earth and all the planets are consi- dered as oblate spheroids . In an oblong or prolate spheroid , the shorter axis is called the revolving axis , and the longer axis the fixed ...
Σελίδα 186
... spheroid are 50 and 30 required the solidity ? Ans . 23562 . 4. The axes of an oblate spheroid are 50 and 30 ; required the solidity ? Ans . 39270 . Z I DEMONSTRATION . Suppose the figure NTnSN to represent a spheroid , formed by the ...
... spheroid are 50 and 30 required the solidity ? Ans . 23562 . 4. The axes of an oblate spheroid are 50 and 30 ; required the solidity ? Ans . 39270 . Z I DEMONSTRATION . Suppose the figure NTnSN to represent a spheroid , formed by the ...
Σελίδα 187
... spheroid , it will be very easy to deduce theorems for finding the solid content , either of the segment or middle zone of any spheroid , having the same height with that of the sphere ; for , As the solidity of the whole sphere is to ...
... spheroid , it will be very easy to deduce theorems for finding the solid content , either of the segment or middle zone of any spheroid , having the same height with that of the sphere ; for , As the solidity of the whole sphere is to ...
Άλλες εκδόσεις - Προβολή όλων
Hawney's Complete Measurer, Or, the Whole Art of Measuring: Being a Plain ... Thomas Keith,William Hawney,John D Craig Δεν υπάρχει διαθέσιμη προεπισκόπηση - 2018 |
Συχνά εμφανιζόμενοι όροι και φράσεις
12 feet 9 inches acres add the square area seg breadth bung-diameter cask centre chord circle circular segment circum circumference cone cube root cylinder cyphers depth diameter divided divisor ellipsis EXAMPLES Extend the compasses extent will reach feet 6 inches feet 9 figure find the area find the Solidity foot frustum gauge-point girt given number greater base greater end head-diameter hence inches broad length less base less end malt bushels mean proportional measure multiplicand parabolic parallel parallelogram pendicular perpendicular height piece of timber places of decimals polygon PROBLEM pyramid quarter-girt quotient radius regular polygons Required the area Required the solidity resolvend rhombus right angles Scale and Compasses segment side slant height Sliding Rule solid content solid feet sphere spheroid square pyramid square root subtract superficial content Suppose surface thickness third trapezium triangle Triple square unit's place vulgar fraction whole numbers wine gallons yards
Δημοφιλή αποσπάσματα
Σελίδα 59 - The circumference of every circle is supposed to be divided into 360 equal parts, called degrees ; each degree into 60 equal parts, called minutes ; and each minute into 60 equal parts, called seconds.
Σελίδα 29 - Reduce the fraction to its lowest terms, then extract the square root of the numerator for a new numerator, and the square root of the denominator for a new denominator.
Σελίδα 80 - To find the area of a parallelogram (65), whether it be a square, a rectangle, a rhombus, or a rhomboid. RULE. — Multiply the length by the breadth, or perpendicular height, and the product will be the area.
Σελίδα 242 - Windows are sometimes measured by taking the dimensions of one pane, and multiplying its superficies by the number of panes.' But, more generally, they measure the length and breadth of the window over all the panes and their frames for the length and breadth of the glazing. Circular or oval windows, as fan lights...
Σελίδα 41 - ... 2. Multiply each term in the multiplicand, beginning at the lowest, by the feet in the multiplier, and write...
Σελίδα 101 - Or, to take a case yet stronger, when it is affirmed, that " the area of a circle is equal to that of a triangle having the circumference for its base, and the radius for its altitude...
Σελίδα 165 - RULE. To twice the length of the base, add the length of the edge, multiply the sum by the breadth of the base, and this product by the perpendicular height of the wedge ; and | of the last product will be the solidity.
Σελίδα 89 - To the square of the base add the square of the perpendicular ; and the square root of the sum will give the hypothenuse (Prop.
Σελίδα 103 - As 7 is to 22, so is the diameter to the circumference; or, as 22 is to 7, so is the circumference to the diameter.
Σελίδα 105 - ... multiply the square of the diameter by ,7854 and the product will be- the area.