 | 1801 - 658 σελίδες
...PROBLEM I. /K/ ^ n/vft ff/" a parallelogram ; whether it be a sa a rectangle, a rhombus, cr a rhomboid. Multiply the length by the breadth, or perpendicularheight, and the product will be the area. !--•-. * . EXAMPLES. * Take any rectangle ABCD, and divide each of its sides i ?. in as many equal... | |
 | Charles Vyse - 1806 - 342 σελίδες
...7"", by 8 Feet, 6', 7". (I2j Multiply 46 Feet, 6 In. 8', 4'", by 6 Feet, 4 In.8', &". t PROBLEM II. To find the Area of a Parallelogram, whether it be a Square, a Rectangle, a Rhombus, or a Rhomboides. RULE. Multiply the Length by the Height or perpendicular Breadth, and the Product will... | |
 | Charles Hutton - 1807 - 464 σελίδες
...the rectangle is said to contain, which in the present case is 12. PROBLEM I. To find the Area of any Parallelogram ,- "whether it be a Square, a Rectangle, a Rhombus, or a Rhomboid. MULTIPLY the length by the perpendicular breadth, or height, and the product will be the area*. EXAMPLES.... | |
 | Samuel Webber - 1808 - 466 σελίδες
...fathom 16i feet. or } . . 5$ yards } 1 pole or rod 40 poles 1 furlong SQJJARE MEASURES. PR0BLEM I. Tojmd the area of a parallelogram ; whether it be a square^...rhomboid. RULE.* Multiply the length by the breadth, or a perpendicular height, and the product will be the area. * Take any rectangle ABCD, and divide each... | |
 | Peter Nicholson - 1809 - 426 σελίδες
...altitude of the square. Hence we have the following rule for any parallelogram whatever. PROBLEM I. To find the area of a parallelogram, whether it be a square, a rectangle, a rhombus, or a rhomboides. Multiply the length by the perpendicular height, and the product will be the area. EXAMPLK... | |
 | Charles Hutton - 1811 - 494 σελίδες
...rectangle is said to contain, which in the present case is 12. PROBLEM I. 3*0 fold the Area of any Parallelogram ; whether it be a Square, a Rectangle, a Rhombus, or a Rhomboid. MULTIPLY the length by the perpendicular breadth, or height, and the product will be the area *. EXAMPLES.... | |
 | John Gummere - 1814 - 398 σελίδες
...survey and finding its area by dividing it into triangles and trapeziums. • • - • PROBLEM I. To find the Area of a Parallelogram, whether it be a Square, a Rectangle, a Rhombus, or a Rhomboides. RULE. Multiply the length by the height or perpendicular breadth, and the product will... | |
 | William Jillard Hort - 1822 - 308 σελίδες
...AB, the height of the tower will be found equal to 223-3 lect. MENSURATION OF PLANE FIGURES. Probltm. To find the area of a parallelogram, whether it be...square, a rectangle, a rhombus, or a rhomboid. Rule 1. Multiply the length by the perpendicular breadth, and the product will be the area. a. As the radius... | |
 | Charles Hutton - 1822 - 616 σελίδες
...rectangle is> said to contain which in the present case is 12. PROBLEM f. To find Ike Area, of any Parallelogram ; whether it be a Square, a Rectangle, a Rhombus, or a Rhomboid. MULTIPLY the length by the perpendicular breadth, or height, and the product will be the area.* EXAMPLES... | |
 | John Nicholson - 1825 - 822 σελίδες
...triangles, are to each other, as the squares of their like sides. MENSURATION OF SUPERFICIES. Prol. 1. To find the area of a parallelogram: whether it be a square, a rectangle, a rhombus, or a rhomboid. Multiply the length by the breadth, or perpendicular height, and the product will be the area. Ex.... | |
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To find the area of a parallelogram (65), whether it be a square, a rectangle, a rhombus, or a rhomboid. RULE. — Multiply the length by the breadth, or perpendicular height, and the product will be the area. 
