Elementary Chemical Arithmetic: With 1100 ProblemsMacmillan and Company, 1882 - 286 σελίδες |
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Σελίδα 5
... formed by the last one , two , or three figures on the right is divisible by 2 , 4 , or 8 respectively . ( ii ) Every number ending with 5 or 0 is divisible by 5 or 10 respectively . ( iii ) Every number is divisible by 3 or 9 , when ...
... formed by the last one , two , or three figures on the right is divisible by 2 , 4 , or 8 respectively . ( ii ) Every number ending with 5 or 0 is divisible by 5 or 10 respectively . ( iii ) Every number is divisible by 3 or 9 , when ...
Σελίδα 6
... formed by 80 lbs . of mercury ? Since 100 lbs . of mercury form 108 lbs . of mercuric oxide , 108 1 lb. forms " " " " 100 " 9 99 108 and 80 lbs . form 99 × 80 86.4 lbs . of 100 mercuric oxide . * In comparing two quantities of the same ...
... formed by 80 lbs . of mercury ? Since 100 lbs . of mercury form 108 lbs . of mercuric oxide , 108 1 lb. forms " " " " 100 " 9 99 108 and 80 lbs . form 99 × 80 86.4 lbs . of 100 mercuric oxide . * In comparing two quantities of the same ...
Σελίδα 7
... formed by 80 lbs . of mercury ? = X 100 80 108 : ? Ans . ( or x ) . : 108 × 80 = 86.4 lbs . mercuric oxide . Since or 30 Thus , if 100 α = C a 2-1-2-1 , a b c d a + b b = d ; abb :: cd : d . a : 5 :: 12 : 4 , a = 60 4 = 15 . or 30 And ...
... formed by 80 lbs . of mercury ? = X 100 80 108 : ? Ans . ( or x ) . : 108 × 80 = 86.4 lbs . mercuric oxide . Since or 30 Thus , if 100 α = C a 2-1-2-1 , a b c d a + b b = d ; abb :: cd : d . a : 5 :: 12 : 4 , a = 60 4 = 15 . or 30 And ...
Σελίδα 24
... formed is M , if no permanent change of volume takes place , 3 M1 Δ , + M2 2 M2 M + + & c . A , A , = M & Δ . Thus , the native alloy of mercury ( A13.59 ) and gold ( A19 · 3 ) ( Hg , Au , ) consists of 600 parts of mercury alloyed with ...
... formed is M , if no permanent change of volume takes place , 3 M1 Δ , + M2 2 M2 M + + & c . A , A , = M & Δ . Thus , the native alloy of mercury ( A13.59 ) and gold ( A19 · 3 ) ( Hg , Au , ) consists of 600 parts of mercury alloyed with ...
Σελίδα 27
... 40 parts of magnesium oxide . And if it be required to find how many grams of magnesium oxide are formed on burning 10 grams of magnesium , the equation shews that 24 grams of magnesium form 40 INTRODUCTION . 27 Magnesium.
... 40 parts of magnesium oxide . And if it be required to find how many grams of magnesium oxide are formed on burning 10 grams of magnesium , the equation shews that 24 grams of magnesium form 40 INTRODUCTION . 27 Magnesium.
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Άλλες εκδόσεις - Προβολή όλων
Elementary Chemical Arithmetic: With 1100 Problems Sydney Lupton Δεν υπάρχει διαθέσιμη προεπισκόπηση - 2016 |
Elementary Chemical Arithmetic: With 1100 Problems Sydney Lupton Δεν υπάρχει διαθέσιμη προεπισκόπηση - 2016 |
Συχνά εμφανιζόμενοι όροι και φράσεις
20 grams 2H₂O 2HCl acid alloy aluminium ammonia antimony arsenic atomic weight barium bromine burnt c.c. of gas c.c. of hydrogen calcium Cambridge carbon dioxide cent CHAPTER CO₂ College copper Crown 8vo cubic cupric oxide Edition evolved Extra fcap fcap ferrous Find its formula Find the atomic Find the density Find the formula Find the mass Find the percentage formed grams grams of hydrogen grams of lead grams of phosphorus grams of potassium grams of silver grams of water H₂ H₂O H₂SO₁ Hence hydrate hydrogen chloride hydrogen nitrate hydrogen sulphate iron kilograms kilos litres litres of hydrogen logarithm m.m. is given magnesium manganese dioxide mercury metres molecular weight multiplied nitric oxide obtained oxygen percentage composition potassium chlorate potassium dichromate pressure silicon sodium solution specific heat substance contains sulphide sulphur dioxide temperature vapour volume of carbon volume of chlorine volume of hydrogen volume of oxygen zinc
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