 | Adrien Marie Legendre - 1819 - 574 σελίδες
...a given point to the same straight line, which is impossible (54). -. ' THEOREM. Fig;. 50. 102. In the same circle, or in equal circles, equal arcs are subtended by equal c/wrds, and conversely, equal chords subtend equal arcs. Demonstration. The radius AC (Jig. 50) being... | |
 | Adrien Marie Legendre - 1822 - 394 σελίδες
...straight lines drawn from the same point to the same straight line, which is impossible (Prop. 16. I.). PROPOSITION IV. THEOREM. In the same circle, or in...ENG ; then the chord AD will be equal to the chord EG. plied exactly to the semicircle ENGF, and the curve line AMDB will coincide entirely with the curve... | |
 | Adrien Marie Legendre - 1825 - 570 σελίδες
...lines drawn from a given point to the same straight line. which is impossible (54). THEOREM. 102. In the same circle, or in equal circles, equal arcs are...chords, and conversely, equal chords subtend equal arcs. Fig. so. Demonstration. The radius AC (fig. 50) being equal to the radius EO, and the arc AMD equal... | |
 | Adrien Marie Legendre, John Farrar - 1825 - 280 σελίδες
...lines drawn from a given point to the same straight line, which is impossible (54). THEOREM. 7 102. In the same circle, or in equal circles, equal arcs are...chords, and conversely, equal chords subtend equal arcs. Fig. 50. Demonstration. The radius AC (fig. 50) being equal to the radius £0, and the arc AMD equal... | |
 | Adrien Marie Legendre, John Farrar - 1825 - 294 σελίδες
...lines drawn from a given point to the same straight lin which is impossible (54). THEOREM. 102. In the same circle, or in equal circles, equal arcs are...chords, and conversely, equal chords subtend equal arcs. .Fig. 50. Demonstration. The radius AC (Jig. 50) being equal to the radius £0, and the arc AMD equal... | |
 | Adrien Marie Legendre - 1828 - 346 σελίδες
...drawn from the same point to the same straight line, which is impossible (54.). THEOREM. Ll 102. In the same circle, or in equal circles, equal arcs are...and, conversely, equal chords subtend equal arcs. v If the radii AC, EO, are equal, and the arcs AMD, ENG ; then the chord AD will be equal to the chord... | |
 | James Hayward - 1829 - 218 σελίδες
...equal angks at the centre are measured by equal arcs ; and equal arcs subtend equal angles. (2). In the same circle, or in equal circles, equal arcs are subtended by equal chords ; and when, in the same circle, the chord. are equal, the arcs are equal. As the triangle would not be changed... | |
 | Adrien Marie Legendre - 1830 - 344 σελίδες
...lines drawn from the same point to the same straight line, which is impossible (54.). THEOREM. 103. In the same circle, or in equal circles, equal arcs, are subtended by equal chorda ; and, conversely, equal chords subtend equal arcs. If the radii AC, EO, are equal, and the... | |
 | Pierce Morton - 1830 - 584 σελίδες
...another. And, in like manner, the converse. Therefore, &c. Cor. 1. (Eue. iii. 28 and 29.) In the same or in equal circles, equal arcs are subtended by equal chords ; and conversely (11. Cor.). Cor. 2. By a similar demonstration it may be shown that in the same or in equal circles,... | |
 | 1835 - 684 σελίδες
...another. And, in like manner, the converse. Therefore, &c. Cor. 1. (Eue. iii. 28 and 29.) In the same or in equal circles, equal arcs are subtended by equal chords ; and conversely (11. Cor.). Cor. 2. By a similar demonstration it may be shown that in the same or in equal circles,... | |
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In the same circle, or in equal circles, equal arcs are subtended by equal chords ; and, conversely, equal chords subtend equal arcs. 
