PROBLEMS PRODUCING QUADRATIC EQUATIONS. I bought certain number of cows for eighty pounds; if four more had been bought for the same sum they would have cost a sovereign less each. How many were bought, and what was the price? Let the number bought. x + 4 x2-4x+(2)2=32+4. x-2=18 a=16 and 0=5. I bought a certain number of pigs for eight pounds eight shillings. If I had purchased two more for the same outlay each pig would have cost four shillings less money. What was the number of pigs purchased? Let the number required. 168 Then cost of each. x+2 There are two numbers, the difference of which is six, and twice the product minus thirty-two is thirtythree and a third times the less; what are the numbers? A person bought sheep for forty pounds, and sold them all but four for forty-eight pounds, gaining thereby one pound on each: what was the number he bought? Let the number required. Divide seventy-two into two such parts that their product may be equal to one hundred and sixty times their difference. Let the greater part. Then 72-x= the less. - x2-248x= -11520. x2+248x11520. x2 +248x+(124)2 x+124 = 26896 +164. x = 40. = 11520+15376. 72-40 32. I bought a certain number of oxen for six hundred and seventy-five pounds, and sold them again for forty-eight pounds each, gaining the price of a single builock: how many did I buy? |