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" To measure a parallelogram, or long square. RULE. Multiply the length by the breadth, and the product will be the area, or superficial content. "
A Plain and Comprehensive Treatise of Decimals and Mensuration ... - Σελίδα 151
των William Crumpton - 1766 - 309 σελίδες
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Daboll's Schoolmaster's Assistant: Improved and Enlarged, Being a Plain ...

Nathan Daboll - 1815 - 250 σελίδες
...and 676-4-160=4"i 36r. the Answer. ART. 2. To measure a parallelogram, or long square. RULE. Multiply the length by the breadth, and the product will be the area, or superficial content. EXAMPLE8. 1. A certain garden, in form of a long square, is 96ft. ;ong, and 54...

Daboll's Schoolmaster's Assistant: Improved and Enlarged. Being a Plain ...

Nathan Daboll - 1818 - 246 σελίδες
...676-4-160=-4o. 36r. the Jlnswer. ART. 2. To measure a Parallelogram, or long square. RULE. Multiply the length by the breadth, and the product will be the area or superficial content. EXAMPLES. 1. A certain garden, in form of along square, is 96 ft, long, and 54...

The new practical gager

Matthew Iley - 1820 - 512 σελίδες
...area 11924-6 on A, against 109-2 on B. PROBLEM II. To find the Area of a Rectangle. RULE. Multiply the length by the breadth, and the product will be the area. Let ABCD be a rectangle whereof the length is G3 inches, and the breadth 42 inches ; the area is required....

A New and Complete System of Arithmetick: Composed for the Use of the ...

Nicolas Pike - 1822 - 562 σελίδες
...breadth, will point out the answer. ART. 2. To measure a Parallelogram or long Square. RULE. Multiply the length by the breadth, and the product will be the area, or superficial content.* Let ABCD represent a parallelogram, whose A length is 5 feet, and breadth, 4...

A Treatise on Practical Mensuration in Eight Parts ...

Anthony Nesbit - 1824 - 476 σελίδες
...the base to the termination at the top. PROBLEM II. Tojind the area of a rectangle. RULE. Multiply the length by the breadth, and the product will be the area* Kote. 1. If the length and breadth be in inches, their product must be divided by 144, in order to...

The Improved Arithmetic: Newly Arranged and Clearly Illustrated, Both ...

Daniel Parker - 1828 - 358 σελίδες
...30 rods squaw? Ans. 900. ARTICLE II. To measure a parallelogram, or long square. Rule. — Multiply the length by the breadth, and the product will be the area. Examples. 1. A hall, in the form of a parallelogram, is 80 feet long and 60 wide j how many square...

A Short System of Practical Arithmetic: Compiled from the Best Authorities ...

William Kinne - 1829 - 246 σελίδες
...=4ac. 36 rods. 160- Ans. CASE 2. — To measure a parallelogram, or long square. RULE — Multiply the length, by the breadth, and the product will be the area, or superficial content, in the same name as that, in which the dimension was taken, whether inches, feet,...

Daboll's Schoolmaster's Assistant: Improved and Enl. ...

Nathan Daboll - 1829 - 252 σελίδες
...676-;- 160=4 a. 36 r. the Answer. ART. 2. To measure a parallelogram, or long square. RULE. Multiply the length by the breadth, and the product will be the area, or superficial content. EXAMPLES. 1. A certain .garden, in form of a long square, is фб feet long, and...

A Short System of Practical Arithmetic: Compiled from the Best Authorities ...

William Kinne - 1831 - 248 σελίδες
...therefore r=4ac. 36 ro. 160 Ans. CASE 2.— To measure a parallelogram or long square. RULE.—Multiply the length by the breadth, and the product will be the area, or superficial content, in the same name as that, in which the dimension was taken, whether inches, feet,...

A New System of Arithmetick: In which the Rules are Familiarly Demonstrated ...

William Ruger - 1832 - 282 σελίδες
...product will bf the area. How do you find the area of a parallelogram or long square ; A. Multiply the length by the breadth, and the product will be the area. Ho w do you find the area of a right angled triangle ? A. Bymultiplying the base by one half the perpendicular,...




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