 Divide this quantity, omitting the last figure, by twice the part of the root already found, and annex the result to the root and also to the divisor, then multiply the divisor as it now stands by the part of the root last obtained for the subtrahend.  Notes on Arithmetic - Σελίδα 27των Rorert Kater Vinter - 1877 - 29 σελίδεςΠλήρης προβολή - Σχετικά με αυτό το βιβλίο
 | 1801 - 446 σελίδες
...figure in division, and- it will be the first figure of the root required. 2. Subtract the assumed square from the first period, and to the remainder bring down the next period for a dividend. ' 3. Place viz. 2oooop ; but 100000 has one place less than 1000 and 100 together... | |
 | James Wood - 1815 - 338 σελίδες
...whose square is contained in the first period, 1 this is the first figure in the root ; subtract it's square from the first period, and to the remainder bring down the next period ; divide this quantity, omitting the last figure, by twice the part of the root already obtained,... | |
 | John Davidson, Robert Scott (writing master) - 1818 - 190 σελίδες
...greatest square number contained in the first part to the left ; write the square root of this number as the first figure of the root, subtract its square from the first part, and to the remainder annex the next part for a dividend. Double the first figure of the root... | |
 | Daniel Staniford - 1818 - 332 σελίδες
...hand period, and place it under this period, and its root in the quotient ; subtract the square number from the first period, and to the remainder bring down the next period and call this the Resolvend. 3. Double the quotient for a divisor. 4. Find how often the divisor... | |
 | Benjamin Snowden - 1835 - 108 σελίδες
...left hand period, and put its root for the first figure of the root sought. 2. — Subtract this cube from the first period, and to the remainder bring down the next period for a dividend. 3. — Find a divisor by multiplying the square of the root by 300. 4. — Divide... | |
 | James Wood - 1841 - 492 σελίδες
...greatest number whose 126j 756 square is contained in the first period, this is the first figure in the root; subtract its square from the first period, and to the remainder bring down the next period ; divide this quantity, omittipg the last figure, by twice the part of the root already obtained,... | |
 | John Darby (teacher of mathematics.) - 1843 - 236 σελίδες
...contained in the first or left hand period, and put its root for a quotient. Subtract this square number from the first period, and to the remainder bring down the next period for a dividend. 5. Double the quotient figure, for the first portion of the divisor ; then find... | |
 | Davis Wasgatt Clark - 1844 - 394 σελίδες
...denoting the root. Multiply the term in the LAST COLUMN by the same figure, and subtract the product from the first period, and to the remainder bring down the next period, and it will form the FIRST DIVIDEND. Jlgain, add this same figure to the term of the FIRST... | |
 | William Watson (of Beverley.) - 1845 - 188 σελίδες
...placing the square under the same, and its root in the quotient. 3. — Subtract the square number from the first period, and to the remainder bring down the next two figures or period for a dividend. 4. — Double the quotient and place it for a divisor on the... | |
 | Davis Wasgatt Clark - 1846 - 374 σελίδες
...on the right, in the place of a quotient in division. Subtract the cube of this figure of the root from the first period, and to the remainder bring down the next period, and call this num. ber the dividend. 3. Multiply the square of the root just found by 300 for... | |
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