A Complete Treatise on Practical Mathematics: Including the Nature and Use of Mathematical Instruments: Logarithmic Tables, Trigonometry, Mensuration of Heights and Distances,--of Surfaces & Solids, Land Surveying, Gunnery, Gauging, Artificer's Measuring, Miscellaneous Exercises. With an Appendix on Algebra ... Principally Designed for the Use of Schools and AcademiesBell and Bradfute, 1792 - 431 σελίδες |
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Σελίδα xi
... Spindle , To find the Solidity of a circular Spindle , To find the Solidity of the middle Zone of a circular Spin- dle , To find the Area and Solidity of the five regular Bodies , To find the Surface and Solidity of a cylindric Ring ...
... Spindle , To find the Solidity of a circular Spindle , To find the Solidity of the middle Zone of a circular Spin- dle , To find the Area and Solidity of the five regular Bodies , To find the Surface and Solidity of a cylindric Ring ...
Σελίδα 199
... spindle . RULE . Multiply the length of the spindle by the radius of the re- volving arch ; again multiply the distance between the centre of the revolving arch and the centre of the spindle by the length of 1 of the revolving arch ...
... spindle . RULE . Multiply the length of the spindle by the radius of the re- volving arch ; again multiply the distance between the centre of the revolving arch and the centre of the spindle by the length of 1 of the revolving arch ...
Σελίδα 200
... spindle , whose length is 40 and thickness 30 inches . AD2 BD 400 15 AD2 + BD AB the chord of the arch ABC ; that is , = = 400 + 225 25 = DH and DH + BD = FB rad . alfo FB - BD = DF cent . dift . 2 = 26.6 and 26.6 + 16 = 20.83 rad ...
... spindle , whose length is 40 and thickness 30 inches . AD2 BD 400 15 AD2 + BD AB the chord of the arch ABC ; that is , = = 400 + 225 25 = DH and DH + BD = FB rad . alfo FB - BD = DF cent . dift . 2 = 26.6 and 26.6 + 16 = 20.83 rad ...
Σελίδα 201
... spindle . Multiply the area of the revolving fegment by the distance between the centres of the arch and fpindle , fubtract the prc- duct from the cube of half the length of the spindle , then multiply the remainder by 4 , and this ...
... spindle . Multiply the area of the revolving fegment by the distance between the centres of the arch and fpindle , fubtract the prc- duct from the cube of half the length of the spindle , then multiply the remainder by 4 , and this ...
Σελίδα 202
... area of the sector AFCB . 8.75X30 262.5 the area of the triangle ACF . 987.5 the area of the rev . fegm . ACB . 4.375 the half the central dift . DF . 49375 69125 29625 29500 4320.3125 30 half the spindle . 30 900 30 3 ) 60 202 MENSURATION.
... area of the sector AFCB . 8.75X30 262.5 the area of the triangle ACF . 987.5 the area of the rev . fegm . ACB . 4.375 the half the central dift . DF . 49375 69125 29625 29500 4320.3125 30 half the spindle . 30 900 30 3 ) 60 202 MENSURATION.
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Συχνά εμφανιζόμενοι όροι και φράσεις
abfciffa acres againſt alfo alſo altitude amplitude axis bafe baſe becauſe breadth centre chain chord of half circle circumference Co-fec Co-tan column cone conjugate cube defcribe dift diſtance divide divifor elevation Engliſh equal Euclid EXAMPLE fame fecond fegment fhall fimilar find the area find the folidity firſt fquare root fquare yards fruftum ftraight line fubtract fuch fuperficies furface girt given greateſt half the arch height horizontal houſe hypothenufe inftrument laft acquired velocity laſt lefs logarithm malt bufhels meaſure obferved off-fets oppofite ordinate parabolic perpendicular plane Plate quantity quotient rectangle Required the area Required the content Required the folidity rhombus right angles RULE Secant Secant Co-fec ſpace ſphere ſpindle ſquare ſteeple Suppofe tangent theodolite theſe thickneſs tranfverfe trapezium triangle triangular uſed verfed whofe diameter whofe fide whofe length whoſe wine gallons
Δημοφιλή αποσπάσματα
Σελίδα 27 - The circumference of every circle is supposed to be divided into 360 equal parts, called degrees ; and each degree into 60 equal parts, called minutes ; and each minute into 60 equal parts, called seconds ; and these into thirds, etc.
Σελίδα 115 - Therefore all the angles of the figure, together with four right angles, are equal to twice as many right angles as the figure has sides.
Σελίδα 3 - A diameter of a circle is a straight line drawn through the centre, and terminated both ways by the circumference.
Σελίδα 232 - E, is equal to twice as many right angles as the figure has sides, less four right angles.
Σελίδα 1 - ... common to the two triangles AFE, BFE, there are two sides in the one equal to two sides in the other, each to each ; and the base EA is equal to the base EB ; (i.
Σελίδα 38 - BG; that is, the fum of the fides is to their difference, as the tangent of half the fum of the angles at the bafe to the tangent of half their difference.
Σελίδα 372 - Subtract the square number from the left hand period, and to the remainder bring down the next period for a dividend. III. Double the root already found for a divisor ; seek how many times the divisor is contained...
Σελίδα 38 - AB the greater side for a distance, let a circle be described, meeting AC, produced in E, F, and BC in D; join DA, EB, FB; and draw FG parallel to BC, meeting EB in G. The angle EAB (32.
Σελίδα 38 - ACB (32. 1.) is equal to the angles CAD and ADC, or ABC together ; therefore FAD is the difference of the angles at the...
Σελίδα 395 - TO divide a given ftraight line into two parts, fo that the rectangle contained by the whale, and one of the parts, fhall be equal to the fquare of the other part. Let AB be the given ftraight line; it is required to divide it into two parts, fo that the rectangle contained by the whole, and one of the parts, fhall be equal to the fquare of the other part. Upon AB...