An Introduction to Algebra Upon the Inductive Method of InstructionHilliard, Gary, Little, and Wilkins, 1830 - 276 σελίδες |
Αναζήτηση στο βιβλίο
Αποτελέσματα 1 - 5 από τα 8.
Σελίδα 8
... LII . Questions relating to Compound Interest LIII . Same subject continued LIV . Annuities Miscellaneous Examples 256 260 264 267 268 ALGEBRA . Introduction . THE operations explained in Arithmetic are 8 Table of Contents .
... LII . Questions relating to Compound Interest LIII . Same subject continued LIV . Annuities Miscellaneous Examples 256 260 264 267 268 ALGEBRA . Introduction . THE operations explained in Arithmetic are 8 Table of Contents .
Σελίδα 260
... rate per cent . r , at com- pound interest . Suppose first , that the principal is $ 1 , or £ 1 , or one unit of money of any kind . The interest of 1 for one year is 1 X 260 LII . Algebra . Questions relating to Compound Interest.
... rate per cent . r , at com- pound interest . Suppose first , that the principal is $ 1 , or £ 1 , or one unit of money of any kind . The interest of 1 for one year is 1 X 260 LII . Algebra . Questions relating to Compound Interest.
Σελίδα 261
... compound interest ? Here p = 753.37 , r = .06 , and n = 5 } . log . 1 + r1.06 0.025306 n = 530 0.0031631 3 0.009490 0.126530 log . 753.37 log . ( 1 + r ) 5 # 0.136020 2.877008 log ... interest will amount to $ LII . 261 Compound Interest .
... compound interest ? Here p = 753.37 , r = .06 , and n = 5 } . log . 1 + r1.06 0.025306 n = 530 0.0031631 3 0.009490 0.126530 log . 753.37 log . ( 1 + r ) 5 # 0.136020 2.877008 log ... interest will amount to $ LII . 261 Compound Interest .
Σελίδα 262
Warren Colburn. 2. What principal put at interest will amount to $ 5000 in 13 years at 5 per cent . compound interest ? By the above formula A p = ( 1 + r ) " log . 1 + r1.05 log . A = 5000 0.021189 n = 13 .063567 21189 Subtract .275457 ...
Warren Colburn. 2. What principal put at interest will amount to $ 5000 in 13 years at 5 per cent . compound interest ? By the above formula A p = ( 1 + r ) " log . 1 + r1.05 log . A = 5000 0.021189 n = 13 .063567 21189 Subtract .275457 ...
Σελίδα 263
... compound interest of $ 947 for 4 years and 3 months at 5 per cent . ? 6. What will $ 157.63 amount to in 17 years at 4 per cent . ? 7. A note was given the 15th of March 1804 , for $ 58.46 , at the rate of 6 per cent . compound interest ...
... compound interest of $ 947 for 4 years and 3 months at 5 per cent . ? 6. What will $ 157.63 amount to in 17 years at 4 per cent . ? 7. A note was given the 15th of March 1804 , for $ 58.46 , at the rate of 6 per cent . compound interest ...
Περιεχόμενα
189 | |
193 | |
195 | |
197 | |
202 | |
208 | |
217 | |
221 | |
95 | |
102 | |
112 | |
121 | |
122 | |
131 | |
142 | |
150 | |
159 | |
175 | |
182 | |
186 | |
226 | |
228 | |
233 | |
239 | |
242 | |
254 | |
256 | |
260 | |
264 | |
267 | |
268 | |
Άλλες εκδόσεις - Προβολή όλων
An Introduction to Algebra: Upon the Inductive Method of Instruction Warren Colburn Πλήρης προβολή - 1837 |
An Introduction to Algebra Upon the Inductive Method of Instruction Warren Colburn Πλήρης προβολή - 1826 |
An Introduction to Algebra Upon the Inductive Method of Instruction Warren Colburn Πλήρης προβολή - 1831 |
Συχνά εμφανιζόμενοι όροι και φράσεις
12 rods 3d power a b c A's share a² b² a² b³ a²x² added algebra algebraic quantities answer the conditions apiece apples approximate root Arith becomes binomial Binomial Theorem bought breadth bushels cents coefficient compound interest compound quantities contain decimal denominator difference divide the number dividend divisor equal equation example exponent expression factor find the root formula fourth fraction gallons gives greater Hence less Let the number letter logarithm merator miles multiplicand negative quantity number consisting number of dollars number of terms observe pears quan question quotient remainder required to find rule second power second root shillings sold square rods subtracted Suppose third power third root tities twice unknown quantity whole number yards zero
Δημοφιλή αποσπάσματα
Σελίδα 92 - It will be seen by the above section that if both the numerator and denominator be multiplied by the same number, the value of the fraction will not be altered...
Σελίδα 2 - District Clerk's Office. BE IT REMEMBERED, That on the seventh day of May, AD 1828, in the fifty-second year of the Independence of the UNITED STATES OF AMERICA, SG Goodrich, of the said District, has deposited in this office the...
Σελίδα 233 - RULE. Multiply the sum of the two extremes by half the number of terms, or multiply...
Σελίδα 234 - The sum of all the terms. Any three of which being given, the other two may be found.
Σελίδα 97 - Hence, to divide a fraction by a fraction, multiply the numerator of the dividend by the denominator of the divisor, and the denominator of the dividend by the numerator of the divisor.
Σελίδα 96 - To divide a whole number by a fraction, — Multiply the dividend by the denominator of the fraction, and divide the product by the numerator.
Σελίδα 35 - ... dollars. How many days did he work, and how many days was he idle ? Ans.
Σελίδα 86 - Multiply the numerators together for a new numerator, and the denominators together for a new denominator.
Σελίδα 149 - ... square feet more than it would, if it were only equal to the breadth. Required the length and breadth of the room. 12. There is a rectangular field, whose length is to its breadth in the proportion of 6 to 5. A part of this, equal to | of the whole, being planted, there remain for ploughing 625 square yards. What are the dimensions of the field r 13.
Σελίδα 276 - The fore wheel of a carriage makes 6 revolutions more than the hind wheel in going 120 yards ; but if the...