An Introduction to Algebra Upon the Inductive Method of InstructionHilliard, Gary, Little, and Wilkins, 1830 - 276 σελίδες |
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Αποτελέσματα 1 - 5 από τα 22.
Σελίδα 3
... solve several by himself . The most simple combinations are given first , then those which are more difficult . The learner is expected to derive most of his know- ledge by solving the examples himself ; therefore care has been taken to ...
... solve several by himself . The most simple combinations are given first , then those which are more difficult . The learner is expected to derive most of his know- ledge by solving the examples himself ; therefore care has been taken to ...
Σελίδα 5
Warren Colburn. In order to study this work to advantage , the learner should solve every question in course , and do it algebraically . If he finds a ques- tion which he can solve as easily without the aid of algebra as with it , he may ...
Warren Colburn. In order to study this work to advantage , the learner should solve every question in course , and do it algebraically . If he finds a ques- tion which he can solve as easily without the aid of algebra as with it , he may ...
Σελίδα 9
... solving abstruse and complicated questions consists in discovering how the operations are to be applied . It is often difficult , and sometimes absolutely impossible to discover , by the ordinary modes of reasoning , how the funda ...
... solving abstruse and complicated questions consists in discovering how the operations are to be applied . It is often difficult , and sometimes absolutely impossible to discover , by the ordinary modes of reasoning , how the funda ...
Σελίδα 13
... solving most of the equations that ever occur . After the preceding questions were put into equation , the first thing was to reduce all the terms containing the unknown quantity to one term , which was done by adding the coeffi- cients ...
... solving most of the equations that ever occur . After the preceding questions were put into equation , the first thing was to reduce all the terms containing the unknown quantity to one term , which was done by adding the coeffi- cients ...
Σελίδα 26
... solve than any of the preceding . In the first place I subtract 76 from both mem- bers , so as to remove it from the first member . Then to get 3x out of the second member , which is there subtracted , I add 3 x to both members ; then ...
... solve than any of the preceding . In the first place I subtract 76 from both mem- bers , so as to remove it from the first member . Then to get 3x out of the second member , which is there subtracted , I add 3 x to both members ; then ...
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Άλλες εκδόσεις - Προβολή όλων
An Introduction to Algebra: Upon the Inductive Method of Instruction Warren Colburn Πλήρης προβολή - 1837 |
An Introduction to Algebra Upon the Inductive Method of Instruction Warren Colburn Πλήρης προβολή - 1826 |
An Introduction to Algebra Upon the Inductive Method of Instruction Warren Colburn Πλήρης προβολή - 1831 |
Συχνά εμφανιζόμενοι όροι και φράσεις
12 rods 3d power a b c A's share a² b² a² b³ a²x² added algebra algebraic quantities answer the conditions apiece apples approximate root Arith becomes binomial Binomial Theorem bought breadth bushels cents coefficient compound interest compound quantities contain decimal denominator difference divide the number dividend divisor equal equation example exponent expression factor find the root formula fourth fraction gallons gives greater Hence less Let the number letter logarithm merator miles multiplicand negative quantity number consisting number of dollars number of terms observe pears quan question quotient remainder required to find rule second power second root shillings sold square rods subtracted Suppose third power third root tities twice unknown quantity whole number yards zero
Δημοφιλή αποσπάσματα
Σελίδα 92 - It will be seen by the above section that if both the numerator and denominator be multiplied by the same number, the value of the fraction will not be altered...
Σελίδα 2 - District Clerk's Office. BE IT REMEMBERED, That on the seventh day of May, AD 1828, in the fifty-second year of the Independence of the UNITED STATES OF AMERICA, SG Goodrich, of the said District, has deposited in this office the...
Σελίδα 233 - RULE. Multiply the sum of the two extremes by half the number of terms, or multiply...
Σελίδα 234 - The sum of all the terms. Any three of which being given, the other two may be found.
Σελίδα 97 - Hence, to divide a fraction by a fraction, multiply the numerator of the dividend by the denominator of the divisor, and the denominator of the dividend by the numerator of the divisor.
Σελίδα 96 - To divide a whole number by a fraction, — Multiply the dividend by the denominator of the fraction, and divide the product by the numerator.
Σελίδα 35 - ... dollars. How many days did he work, and how many days was he idle ? Ans.
Σελίδα 86 - Multiply the numerators together for a new numerator, and the denominators together for a new denominator.
Σελίδα 149 - ... square feet more than it would, if it were only equal to the breadth. Required the length and breadth of the room. 12. There is a rectangular field, whose length is to its breadth in the proportion of 6 to 5. A part of this, equal to | of the whole, being planted, there remain for ploughing 625 square yards. What are the dimensions of the field r 13.
Σελίδα 276 - The fore wheel of a carriage makes 6 revolutions more than the hind wheel in going 120 yards ; but if the...