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" Multiply the first term by that power of the ratio whose index is one less than the number of terms, and the product will be the... "
Graded Problems in Arithmetic and Mensuration - Σελίδα 116
των Samuel Mecutchen - 1880 - 232 σελίδες
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A Course of Mathematics ...: Composed for the Use of the Royal Military ...

Charles Hutton - 1811 - 406 σελίδες
...to find the other Extreme, and the Sum of the Series. -'..•' MULTIPLT the common difference by 1 less than the number of terms, and the product will be the difference of the extremes : Therefore add the product to the less extreme, to give the greater ; or...

A Course of Mathematics: For the Use of Academies as Well as Private Tuition

Charles Hutton - 1812 - 620 σελίδες
...of Terms : to find the other Extreme, andthe Sum of the Series. MULTIPLY the common difference by I less than the number of terms, and the product will be the difference of the extremes: Therefore add the product to the less extreme, to give the greater ; or...

An Introduction to Algebra: Being the First Part of a Course of Mathematics ...

Jeremiah Day - 1814 - 304 σελίδες
...that is, 439. In geometrical progtession, the greatest term it equal to the product of the least, into that, power of the ratio whose index is one less than the number of terms. When the least term and the ratio are the same, ihe equation becomes z=rrn~i=rn. See art. 437. 440....

A New and Complete System of Arithmetick: Composed for the Use of the ...

Nicolas Pike - 1822 - 536 σελίδες
...tlie 8th term •would be 2X2T, ami so on. In nu ascending scries, therefore, multiply tlie first t?rm by that power of the ratio whose index is one less than the number of tlie term sought, and the product is tlie terni tough! . In a descending series, as 213, 81,27,9,3,...

A New and Complete System of Arithmetick: Composed for the Use of the ...

Nicolas Pike - 1822 - 562 σελίδες
...2X2X2X2X?, &e. or thus 2, 2X2>, 8X?a, 2X21. 2X2-', anil so on. Any term alter the first is evidently that power of the ratio whose index is one less than the number of the term multiplied by the lint term. Thus, the 3d term is 2x2^ ; the 4th term is2X2:1, aud the ittli...

A Course of Mathematics: For the Use of Academies, as Well as Private ...

Charles Hutton - 1822 - 616 σελίδες
...of Terms ; to find the other Extreme, and the sum of the Series. MULTIPLY the common difference by 1 less than the number of terms, and the product will be the difference of the extremes : Therefore add the product to the less extreme, to give the greater ; or...

An Introduction to Algebra: Being the First Part of a Course of Mathematics ...

Jeremiah Day - 1827 - 352 σελίδες
...that is, 439. In geometrical progression, the last term is equal to the product of the Jirst, into that power of the ratio whose index is one less than the number of terms. When the least term and the ratio are the same, the equation becomes z^=rr»~ =r". See art. 437. 440....

A New and Complete System of Arithmetick: Composed for the Use of the ...

Nicolas Pike - 1832 - 544 σελίδες
...1th term is 2X0 ! , ai.d the 8th term would be 2X27, nnd so on. In an asvending series, therefore, multiply the first term by that power of the ratio whose index is one less, than the number of the term sought, anil the product is the term sought. In a descending scries, as 243, 81, 27, '.',...

The Youth's Assistant in Theorhetic [sic] and Practical Arithmetic: Designed ...

Zadock Thompson - 1832 - 186 σελίδες
...27=23X24=8X16=128. Ans. I. The first term and ratio given to find any other term. RULE. — Find the power of the ratio, whose index is one less than the number of the required term, and multiply this power by the first term, the product will be the answer, if the...

The Youth's Assistant in Theoretic and Practical Arithmetic: Designed for ...

Zadock Thompson - 1832 - 186 σελίδες
...s X2*=8X 16=128. Ans. I. The first term and ratio given to find any other term. RULE. — Find the power of the ratio, whose index is one less than the number of the required term, and multiply this power. by the first term, the product will be the answer, if the...




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