Practical and Mental Arithmetic on a New Plan: In which Mental Arithmetic is Combined with the Use of the Slate : Containing a Complete System for All Practical Purposes Being in Dollars and CentsMarshall, Williams & Butler, 1829 - 284 σελίδες |
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Σελίδα 19
... hence its introduction nto our own country . Q. About what time was it introduced into England ? A. About the middle of the eleventh century . Q. How extensively is it now used ? A. All over the civilized world . A. Ten , ( 10. ) Q. How ...
... hence its introduction nto our own country . Q. About what time was it introduced into England ? A. About the middle of the eleventh century . Q. How extensively is it now used ? A. All over the civilized world . A. Ten , ( 10. ) Q. How ...
Σελίδα 40
... hence the 5 must be placed in the tens ' place To explain why you add the two products together . Q. What does multiplying 365 by 6 give ? 4. The number of days in 6 years . Q. What does multiplying 365 by 3 tens give ? A. As the 3 ...
... hence the 5 must be placed in the tens ' place To explain why you add the two products together . Q. What does multiplying 365 by 6 give ? 4. The number of days in 6 years . Q. What does multiplying 365 by 3 tens give ? A. As the 3 ...
Σελίδα 41
... hence the value is in- creased 10 times . Q. What effect would two ciphers have , or three ciphers , & c . ? A. Two ciphers would remove any figure two places towards the left , and of course increase it 100 times , and so on for 1000 ...
... hence the value is in- creased 10 times . Q. What effect would two ciphers have , or three ciphers , & c . ? A. Two ciphers would remove any figure two places towards the left , and of course increase it 100 times , and so on for 1000 ...
Σελίδα 57
... hence , when the cents are less than 10 , they must Occupy the units ' place of cents , and a cipher the tens ' place of cents . Q. In writing down mills with dollars , when there are no cents , how many ciphers must you place between ...
... hence , when the cents are less than 10 , they must Occupy the units ' place of cents , and a cipher the tens ' place of cents . Q. In writing down mills with dollars , when there are no cents , how many ciphers must you place between ...
Σελίδα 79
... Hence , to divide by 55 , 304 , & c . , we need only bring the divisor into halves , quarters , & c . , also the dividend into the sa , and the quotient will be the answer . 29. In 30 yards how many rods ? In 4224 yards ? A. 792 rods ...
... Hence , to divide by 55 , 304 , & c . , we need only bring the divisor into halves , quarters , & c . , also the dividend into the sa , and the quotient will be the answer . 29. In 30 yards how many rods ? In 4224 yards ? A. 792 rods ...
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12 cents 12 leaves 25 cents 50 cents acres amount annuity apiece apples bbls broadcloth bushels called ciphers cloth cost common denominator common fraction compound interest contained cord feet corn cube root currency derive the following dimes divide dividend divisor dollars equal example Exercises farthings federal money feet long feet wide following RULE gain gallons gals gills give greatest common divisor hence hogshead hundred illustrations we derive improper fraction James least common least common multiple length lowest terms miles mills mixed number molasses months Multiply number of terms OPERATION oranges ounces payment pence pints pounds present worth proceed pupil pwts quarts ratio Reduce remainder shillings Slate sold solid feet solid inches square feet square rods square root subtract third term units whole number write yards of cloth