Dialogues on the First Principles of the Newtonian System, Τόμος 4J. Parker, 1828 - 68 σελίδες |
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Αποτελέσματα 1 - 5 από τα 11.
Σελίδα 14
... described in the same time without any new impulse , and another side will be the line which it would have described in the same time , from a state of rest , by the sole force of the new impulse . A. This certainly requires proof . B ...
... described in the same time without any new impulse , and another side will be the line which it would have described in the same time , from a state of rest , by the sole force of the new impulse . A. This certainly requires proof . B ...
Σελίδα 26
... described instead of the triangle SBC , and that these two triangles are equal . But , by Prop . XII . , these equal triangles must be between the same parallels , that is , CD must be parallel to BS . And again , the line BE ( being ...
... described instead of the triangle SBC , and that these two triangles are equal . But , by Prop . XII . , these equal triangles must be between the same parallels , that is , CD must be parallel to BS . And again , the line BE ( being ...
Σελίδα 28
... described , must be a right angle also ; for it is the moment when she shows just half of that face to us which she presents entire to the sun . Here then is a triangle , two of whose angles , to all appearance , are right angles . ance ...
... described , must be a right angle also ; for it is the moment when she shows just half of that face to us which she presents entire to the sun . Here then is a triangle , two of whose angles , to all appearance , are right angles . ance ...
Σελίδα 34
... described upon the hypothenuse ( or side opposite to the right angle ) of a right - angled triangle , is equal to the sum of the squares described upon the two other sides . Thus , let ABC be a triangle , having a right angle at A. It ...
... described upon the hypothenuse ( or side opposite to the right angle ) of a right - angled triangle , is equal to the sum of the squares described upon the two other sides . Thus , let ABC be a triangle , having a right angle at A. It ...
Σελίδα 35
... described upon BA . This proposition is of great service in the application of arithmetic to geometry . A. How is that application effected ? B. By dividing any space into a multitude of equal parts , we are enabled to represent its ...
... described upon BA . This proposition is of great service in the application of arithmetic to geometry . A. How is that application effected ? B. By dividing any space into a multitude of equal parts , we are enabled to represent its ...
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Dialogues on the First Principles of the Newtonian System Walter Henry Burton Δεν υπάρχει διαθέσιμη προεπισκόπηση - 2009 |
Συχνά εμφανιζόμενοι όροι και φράσεις
altitude angle ABC angle ACB angle MPH arithmetical progression ascertain attraction bisect centre of gravity centripetal force circle circumference common centre curve curvilinear figure ABC definite diagonal DIALOGUE diameter difference direction divided drawn parallel ellipses equal bases exterior angle fixed point fraction greater hypothenuse indefinitely small portion instance law of motion line BD line be drawn line drawn magnitude monstration moon move multiplying number of equal number of longitudinal number of terms observed orbit parallel lines parallelogram pass perpendicular planets produced Prop proportional proportionate proposition prove quantities of matter quotient radii radius rallel ratio rectangle CD rection represented respectively equal right angles round the earth SBD is equal single impulse space square described square of CD square root straight line sun's supposed supposition thing three angles three sides tion triangle ABC uniform velocity wind XXIII
Δημοφιλή αποσπάσματα
Σελίδα 2 - Certainly, it is heaven upon earth, to have a man's mind move in charity, rest in providence, and turn upon the poles of truth.
Σελίδα 2 - If two triangles have two sides of the one equal to two sides of the...
Σελίδα 19 - Equal triangles upon the same base, and upon the same side of it, are between the same parallels.
Σελίδα 37 - IF a straight line be divided into two equal, and also into two unequal parts ; the squares of the two unequal parts are together double of the square of half the line, and of the square of the line between the points of section.
Σελίδα 2 - Euclid's, and show by construction that its truth was known to us ; to demonstrate, for example, that the angles at the base of an isosceles triangle are equal...
Σελίδα 10 - Prove that parallelograms on the same base and between the same parallels are equal in area.
Σελίδα 51 - Multiply one half the sum of the first and last terms by the number of terms. Thus, the sum of eight terms of the series whose first term is 3 and last term 38 is 8 x * (3 + 38) = 164.
Σελίδα 19 - Parallelograms on the same base, and between the same parallels, are equal to one another.
Σελίδα 38 - Two parallelograms are similar when they have an angle of the one equal to an angle of the other, and the including sides proportional.
Σελίδα 6 - Then, because the three angles of every triangle are together equal to two right angles, [I.