Dialogues on the First Principles of the Newtonian System, Τόμος 4J. Parker, 1828 - 68 σελίδες |
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Αποτελέσματα 1 - 5 από τα 11.
Σελίδα 23
... passes . But all these rectangles , if they were made to slide along upon their bases , parallel to AC , till they reached the line BC , would coincide with the single rect- angle BCDE ; and that rectangle may therefore henceforth be ...
... passes . But all these rectangles , if they were made to slide along upon their bases , parallel to AC , till they reached the line BC , would coincide with the single rect- angle BCDE ; and that rectangle may therefore henceforth be ...
Σελίδα 24
... passes , to see the application of this to the last proposition . A. You said that proposition was of great im- portance . Has it any immediate connection with the phenomena ? B. Kepler ( who , with Tycho Brahe and Ga- lileo , may be ...
... passes , to see the application of this to the last proposition . A. You said that proposition was of great im- portance . Has it any immediate connection with the phenomena ? B. Kepler ( who , with Tycho Brahe and Ga- lileo , may be ...
Σελίδα 30
... pass through the centres of both circles . A. Why must it pass through their centres ? B. Because if the centre of either circle be supposed to lie any where out of that line , as at D , and lines be drawn from that supposed centre to ...
... pass through the centres of both circles . A. Why must it pass through their centres ? B. Because if the centre of either circle be supposed to lie any where out of that line , as at D , and lines be drawn from that supposed centre to ...
Σελίδα 34
... passes ; and draw the straight lines AE and BF . Now because BC is equal to CE , and CF to CA , and the angle BCF to the angle ACE , ( for each is composed of the angle ACB and a right angle , ) we have the triangle BCF equal to the ...
... passes ; and draw the straight lines AE and BF . Now because BC is equal to CE , and CF to CA , and the angle BCF to the angle ACE , ( for each is composed of the angle ACB and a right angle , ) we have the triangle BCF equal to the ...
Σελίδα 38
... passing through the centre , ) and be bisected by another straight line drawn at right angles to it , the last line will ... pass through the centre , without being also at right angles to that line ; nor be at right angles to it without ...
... passing through the centre , ) and be bisected by another straight line drawn at right angles to it , the last line will ... pass through the centre , without being also at right angles to that line ; nor be at right angles to it without ...
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Dialogues on the First Principles of the Newtonian System Walter Henry Burton Δεν υπάρχει διαθέσιμη προεπισκόπηση - 2009 |
Συχνά εμφανιζόμενοι όροι και φράσεις
altitude angle ABC angle ACB angle MPH arithmetical progression ascertain attraction bisect centre of gravity centripetal force circle circumference common centre curve curvilinear figure ABC definite diagonal DIALOGUE diameter difference direction divided drawn parallel ellipses equal bases exterior angle fixed point fraction greater hypothenuse indefinitely small portion instance law of motion line BD line be drawn line drawn magnitude monstration moon move multiplying number of equal number of longitudinal number of terms observed orbit parallel lines parallelogram pass perpendicular planets produced Prop proportional proportionate proposition prove quantities of matter quotient radii radius rallel ratio rectangle CD rection represented respectively equal right angles round the earth SBD is equal single impulse space square described square of CD square root straight line sun's supposed supposition thing three angles three sides tion triangle ABC uniform velocity wind XXIII
Δημοφιλή αποσπάσματα
Σελίδα 2 - Certainly, it is heaven upon earth, to have a man's mind move in charity, rest in providence, and turn upon the poles of truth.
Σελίδα 2 - If two triangles have two sides of the one equal to two sides of the...
Σελίδα 19 - Equal triangles upon the same base, and upon the same side of it, are between the same parallels.
Σελίδα 37 - IF a straight line be divided into two equal, and also into two unequal parts ; the squares of the two unequal parts are together double of the square of half the line, and of the square of the line between the points of section.
Σελίδα 2 - Euclid's, and show by construction that its truth was known to us ; to demonstrate, for example, that the angles at the base of an isosceles triangle are equal...
Σελίδα 10 - Prove that parallelograms on the same base and between the same parallels are equal in area.
Σελίδα 51 - Multiply one half the sum of the first and last terms by the number of terms. Thus, the sum of eight terms of the series whose first term is 3 and last term 38 is 8 x * (3 + 38) = 164.
Σελίδα 19 - Parallelograms on the same base, and between the same parallels, are equal to one another.
Σελίδα 38 - Two parallelograms are similar when they have an angle of the one equal to an angle of the other, and the including sides proportional.
Σελίδα 6 - Then, because the three angles of every triangle are together equal to two right angles, [I.