Dialogues on the First Principles of the Newtonian System, Τόμος 4J. Parker, 1828 - 68 σελίδες |
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Αποτελέσματα 1 - 5 από τα 9.
Σελίδα 3
... respectively equal , would also coincide in length ; and then the two third sides , or bases , could not choose but coincide also . This is clear at first sight . B. And not only are the three sides equal to the three sides , each to ...
... respectively equal , would also coincide in length ; and then the two third sides , or bases , could not choose but coincide also . This is clear at first sight . B. And not only are the three sides equal to the three sides , each to ...
Σελίδα 4
... respectively equal to AB , BC , we shall have the triangle DCB equal to the triangle ABC by Prop . I .; which shows the supposition to be false . A. This cannot be denied . What is your next proposition ? B. That if all the three sides ...
... respectively equal to AB , BC , we shall have the triangle DCB equal to the triangle ABC by Prop . I .; which shows the supposition to be false . A. This cannot be denied . What is your next proposition ? B. That if all the three sides ...
Σελίδα 20
... respectively equal to the angles of another , the sides enclosing the same angles in both are proportional to each other . For sup- posing the two triangles ( as ABC , ADE ) to be so applied to each other , that their equal angles at A ...
... respectively equal to the angles of another , the sides enclosing the same angles in both are proportional to each other . For sup- posing the two triangles ( as ABC , ADE ) to be so applied to each other , that their equal angles at A ...
Σελίδα 21
... respectively to BE and BC , which shall meet in a point which we call D. Now you know the result of all this is , that the body , which in one second moved from A to B , will move in the next from B to D. And observe , that the triangle ...
... respectively to BE and BC , which shall meet in a point which we call D. Now you know the result of all this is , that the body , which in one second moved from A to B , will move in the next from B to D. And observe , that the triangle ...
Σελίδα 34
... respectively described upon AC and AB . In the first place then let AD be drawn parallel to those sides of the square BE , between which it passes ; and draw the straight lines AE and BF . Now because BC is equal to CE , and CF to CA ...
... respectively described upon AC and AB . In the first place then let AD be drawn parallel to those sides of the square BE , between which it passes ; and draw the straight lines AE and BF . Now because BC is equal to CE , and CF to CA ...
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Dialogues on the First Principles of the Newtonian System Walter Henry Burton Δεν υπάρχει διαθέσιμη προεπισκόπηση - 2009 |
Συχνά εμφανιζόμενοι όροι και φράσεις
altitude angle ABC angle ACB angle MPH arithmetical progression ascertain attraction bisect centre of gravity centripetal force circle circumference common centre curve curvilinear figure ABC definite diagonal DIALOGUE diameter difference direction divided drawn parallel ellipses equal bases exterior angle fixed point fraction greater hypothenuse indefinitely small portion instance law of motion line BD line be drawn line drawn magnitude monstration moon move multiplying number of equal number of longitudinal number of terms observed orbit parallel lines parallelogram pass perpendicular planets produced Prop proportional proportionate proposition prove quantities of matter quotient radii radius rallel ratio rectangle CD rection represented respectively equal right angles round the earth SBD is equal single impulse space square described square of CD square root straight line sun's supposed supposition thing three angles three sides tion triangle ABC uniform velocity wind XXIII
Δημοφιλή αποσπάσματα
Σελίδα 2 - Certainly, it is heaven upon earth, to have a man's mind move in charity, rest in providence, and turn upon the poles of truth.
Σελίδα 2 - If two triangles have two sides of the one equal to two sides of the...
Σελίδα 19 - Equal triangles upon the same base, and upon the same side of it, are between the same parallels.
Σελίδα 37 - IF a straight line be divided into two equal, and also into two unequal parts ; the squares of the two unequal parts are together double of the square of half the line, and of the square of the line between the points of section.
Σελίδα 2 - Euclid's, and show by construction that its truth was known to us ; to demonstrate, for example, that the angles at the base of an isosceles triangle are equal...
Σελίδα 10 - Prove that parallelograms on the same base and between the same parallels are equal in area.
Σελίδα 51 - Multiply one half the sum of the first and last terms by the number of terms. Thus, the sum of eight terms of the series whose first term is 3 and last term 38 is 8 x * (3 + 38) = 164.
Σελίδα 19 - Parallelograms on the same base, and between the same parallels, are equal to one another.
Σελίδα 38 - Two parallelograms are similar when they have an angle of the one equal to an angle of the other, and the including sides proportional.
Σελίδα 6 - Then, because the three angles of every triangle are together equal to two right angles, [I.