Description and Use of a Diagram of Navigation: By which All Problems in Plane, Traverse, Parallel, Middle Latitude and Mercator's Sailing May be Instantly and Accurately Resolved. Adapted to the Capacity of All who Know the Use of Figures. Designed as an Easy Introduction, by Sensible Demonstration, to the Principles, and the Practice of Navigation. With a Diagram EngravedFellowes & Simpson, 1822 - 4 σελίδες |
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Σελίδα 23
... course 34 points and the distance 193 give the diff . lat . 155 , and the departure 115 ; hence the lat . is in 36 deg . 35 m . N. and the mid . lat . is 35 deg . 18 , which with the departure 115 give the diff . of 23.
... course 34 points and the distance 193 give the diff . lat . 155 , and the departure 115 ; hence the lat . is in 36 deg . 35 m . N. and the mid . lat . is 35 deg . 18 , which with the departure 115 give the diff . of 23.
Σελίδα 28
... Hence the mer . diff . lat . is 184 , which with the course 42 deg . gives the diff . lon . 166 miles . 1 CASE 4 . 101. Given both LATITUDES and the 28 Case 1, to find the course and distance 2, to find the course, distance, and diff lon,
... Hence the mer . diff . lat . is 184 , which with the course 42 deg . gives the diff . lon . 166 miles . 1 CASE 4 . 101. Given both LATITUDES and the 28 Case 1, to find the course and distance 2, to find the course, distance, and diff lon,
Σελίδα 30
... hence the lat . in is 27 deg . 37 m . and the mer . diff . of Lat . is 241 , which with the course 2 points give the diff .. lon . 129 miles . CASE 7 . 104. Given one LATITUDE , the DISTANCE and DEPARTURE , to find the COURSE ...
... hence the lat . in is 27 deg . 37 m . and the mer . diff . of Lat . is 241 , which with the course 2 points give the diff .. lon . 129 miles . CASE 7 . 104. Given one LATITUDE , the DISTANCE and DEPARTURE , to find the COURSE ...
Σελίδα 31
... hence the proper diff . of lat . is 117 , which with the course gives the distance 149 miles . Lat . left 42 deg . equal 2782 mer . parts . Add . mer . lat . 160 2942-43 ° 57 ′ the lat . in . 106. To find by the diagram the value of any ...
... hence the proper diff . of lat . is 117 , which with the course gives the distance 149 miles . Lat . left 42 deg . equal 2782 mer . parts . Add . mer . lat . 160 2942-43 ° 57 ′ the lat . in . 106. To find by the diagram the value of any ...
Σελίδα 49
... hence the other is 53 deg . 219. Given one of the legs , and the sum of the hyp and the other leg , to find these sides separately and the angles . Rule . Set the index so that the sum of the hyp . and leg sought shall meet the given ...
... hence the other is 53 deg . 219. Given one of the legs , and the sum of the hyp and the other leg , to find these sides separately and the angles . Rule . Set the index so that the sum of the hyp . and leg sought shall meet the given ...
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Συχνά εμφανιζόμενοι όροι και φράσεις
arc of latitude arc or angle chord circle circumference co-sine co-tangent contiguous angle course 3 points course 3 pts course 38 deg COURSE and DEPARTURE Course and Diff course and distance course sailed curve line departure 84 Diagram of Navigation difference of lati difference of latitude difference of longitude direct course dist DISTANCE and DEPARTURE distance sailed ence of longitude Example Example.-A ship sails find the COURSE find the DISTANCE give the course give the diff give the distance Given both LATITUDES Given-one LATITUDE index remaining index set index to meet meet the difference Mercator's sailing merid meridian distance meridional difference middle lat parallel sailing plane sailing proper diff radius be equal required the course right line drawn right-angled plane triangle Rule Rule.-Set the index secant Set the index ship in lat side as radius side marked equator tance tangent traverse table tude