Description and Use of a Diagram of Navigation: By which All Problems in Plane, Traverse, Parallel, Middle Latitude and Mercator's Sailing May be Instantly and Accurately Resolved. Adapted to the Capacity of All who Know the Use of Figures. Designed as an Easy Introduction, by Sensible Demonstration, to the Principles, and the Practice of Navigation. With a Diagram EngravedFellowes & Simpson, 1822 - 4 σελίδες |
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Σελίδα 5
... dist . :: sec . of lat .: diff . of lon . In publishing the remarks which accompany the Di- agram , after the description and use , my original inten- tion was to have added only the rules , examples and illustrations which are ...
... dist . :: sec . of lat .: diff . of lon . In publishing the remarks which accompany the Di- agram , after the description and use , my original inten- tion was to have added only the rules , examples and illustrations which are ...
Σελίδα 34
... dist . sailed 157 miles . lat . in 42 ° 06 ′ N. lon . in 66 56 W. 117. A ship leaving Boston light house in lat . 42 deg . 20 m . N. and lon . 70 deg . 54 m . W. sails E. by SS . and by observation it is found she is in lat . 40 deg ...
... dist . sailed 157 miles . lat . in 42 ° 06 ′ N. lon . in 66 56 W. 117. A ship leaving Boston light house in lat . 42 deg . 20 m . N. and lon . 70 deg . 54 m . W. sails E. by SS . and by observation it is found she is in lat . 40 deg ...
Σελίδα 51
... dist . 243 2.38561 So is co - sine course 3 pts . A 9.91985 To diff . lat . 202 2.30546 And as rad . 90 ° 10.00000 Is to dist . 243 2.38561 So is sine course 3 pts . 9.74474 135 2.13035 To departure By inspection . In the table of ...
... dist . 243 2.38561 So is co - sine course 3 pts . A 9.91985 To diff . lat . 202 2.30546 And as rad . 90 ° 10.00000 Is to dist . 243 2.38561 So is sine course 3 pts . 9.74474 135 2.13035 To departure By inspection . In the table of ...
Σελίδα 52
... dist . 178 and the dep . 106 . SARP 1 224. Theorem.In a right - angled plane triangle , if one side as radius be equal to the departure , and a contiguous angle be equal to the complement of the course , the side adjacent to this angle ...
... dist . 178 and the dep . 106 . SARP 1 224. Theorem.In a right - angled plane triangle , if one side as radius be equal to the departure , and a contiguous angle be equal to the complement of the course , the side adjacent to this angle ...
Σελίδα 53
... dist . is to rad . so is the diff . lat . to the co - sine of the course ; and as rad .: dist . :: sine course dep . Example . Given the distance 212 miles and diff . lat . 187 ; what is the course and departure ? As distance 212 Is to ...
... dist . is to rad . so is the diff . lat . to the co - sine of the course ; and as rad .: dist . :: sine course dep . Example . Given the distance 212 miles and diff . lat . 187 ; what is the course and departure ? As distance 212 Is to ...
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arc of latitude arc or angle chord circle circumference co-sine co-tangent contiguous angle course 3 points course 3 pts course 38 deg COURSE and DEPARTURE Course and Diff course and distance course sailed curve line departure 84 Diagram of Navigation difference of lati difference of latitude difference of longitude direct course dist DISTANCE and DEPARTURE distance sailed ence of longitude Example Example.-A ship sails find the COURSE find the DISTANCE give the course give the diff give the distance Given both LATITUDES Given-one LATITUDE index remaining index set index to meet meet the difference Mercator's sailing merid meridian distance meridional difference middle lat parallel sailing plane sailing proper diff radius be equal required the course right line drawn right-angled plane triangle Rule Rule.-Set the index secant Set the index ship in lat side as radius side marked equator tance tangent traverse table tude