The New Federal Calculator, Or, Scholar's Assistant: Containing the Most Concise and Accurate Rules for Performing the Operations in Common Arithmetic : Together with Numerous Examples Under Each of the Rules, Varied So as to Make Them Conformable to Almost Every Kind of Business : for the Use of Schools and Counting HousesGrigg & Elliott, 1825 - 180 σελίδες |
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Σελίδα 45
... Suppose a man to have 5 granaries , 3 of which con- tain each 756bu . 2pe . , and the other two each 854bu . 5qt . , how many bushels do the five granaries contain ? Ans . 3977bu . 3pe . 2bt . COMPOUND MULTIPLICATION . Compound ...
... Suppose a man to have 5 granaries , 3 of which con- tain each 756bu . 2pe . , and the other two each 854bu . 5qt . , how many bushels do the five granaries contain ? Ans . 3977bu . 3pe . 2bt . COMPOUND MULTIPLICATION . Compound ...
Σελίδα 75
... Suppose 20 days be required for 12 men to build a house , in what time can 18 men do the same ? Ans . 13days . 4h . 44. If 8 men can mow a piece of ground in 24 days , how many men can do it in 4 days ? Ans . 48men . 45. In what time ...
... Suppose 20 days be required for 12 men to build a house , in what time can 18 men do the same ? Ans . 13days . 4h . 44. If 8 men can mow a piece of ground in 24 days , how many men can do it in 4 days ? Ans . 48men . 45. In what time ...
Σελίδα 79
... Suppose 8 men can make 120 pair of shoes in 30 days , how many can 12 men make in 90 days ? Ans . 540 pair . 8. If 37 lbs . of beef be sufficient for 12 persons 4 days , how many pounds will suffice 38 men 16 days ? Ans . 468lbs . 10oz ...
... Suppose 8 men can make 120 pair of shoes in 30 days , how many can 12 men make in 90 days ? Ans . 540 pair . 8. If 37 lbs . of beef be sufficient for 12 persons 4 days , how many pounds will suffice 38 men 16 days ? Ans . 468lbs . 10oz ...
Σελίδα 103
... Suppose 1000 dollars , at 4 per cent . per annum amount to 1281 dols . 25 cts . how long was it at interest ? Ans . 6 years 3 months . COMPOUND INTEREST . 1. What is the compound interest of 150 dol . for 5 years at 4 per cent , per ...
... Suppose 1000 dollars , at 4 per cent . per annum amount to 1281 dols . 25 cts . how long was it at interest ? Ans . 6 years 3 months . COMPOUND INTEREST . 1. What is the compound interest of 150 dol . for 5 years at 4 per cent , per ...
Σελίδα 142
... Suppose a number and work with it as directed in the question , as though it were a real number un- you mention the result which will be the error . til 2. Suppose some other number and proceed in the same way to find a second result or ...
... Suppose a number and work with it as directed in the question , as though it were a real number un- you mention the result which will be the error . til 2. Suppose some other number and proceed in the same way to find a second result or ...
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Συχνά εμφανιζόμενοι όροι και φράσεις
100 dollars 75 cents acres aliquot amount annuity annum Arithmetical Progression barrels Bought Bring bushels cents per bushel cents per cwt cents per lb ciphers compound interest containing cube root decimal point Divide dividend divisor exceeds 12 dollars 50 cents dollars or pounds dollars per cent drams DRY MEASURE exact product Examples farthings FEDERAL MONEY feet figures furlongs gain gallons given number given price given sum given to find gross half yearly highest denomination hogshead LAND MEASURE long division lowest denomination miles months multiplicand multiplication table Multiply neat weight ounces pecks pence pennyweights perches present worth proceed quarters Questions quotient rate per cent Reduce remainder Repeat the rule rule for performing rule of three shillings sold square inches square root sterling tare TARE AND TRET TROY WEIGHT upper denomination VULGAR FRACTIONS whole number yards of cloth
Δημοφιλή αποσπάσματα
Σελίδα 134 - The construction of this table is from an algebraic theorem, given by the learned A, de Moivre, in his treatise of Annuities on Lives, which may be in words, thus : For half yearly payments take a unit from the ratio, and from the square root of the ratio; half the quotient of the first remainder divided by the latter, will be the tabular number. For quarterly payments use the 4th root as above, and take one quarter of the quotient.
Σελίδα 20 - The number to be divided is called the dividend. The number by which we divide is called the divisor.
Σελίδα 111 - If the errors are alike, divide the difference of the products by the difference of the errors, and the quotient will be the answer.
Σελίδα 69 - ... principal is the money for which interest is to be received. The rate per cent, per annum, is the interest of 100 pounds or dollars for one year. The time is the number of years or months, &c. for which interest is to be calculated. The amount is the sum of the principal and interest. CASE 1. To find the interest when the time is one year, and the rate per cent, is pounds or dollars only. RULE...
Σελίδα 97 - RULE. Multiply all the numerators together for a new numerator, and all the denominators for a new denominator: then reduce the new fraction to its lowest terms.
Σελίδα 92 - Case 5. To find a common denominator. Rule. 1. Find the least common denominator, by dividing the given denominators by any number that will divide two or more without a remainder. 2. Set the quotients and individual numbers underneath, and continue the division till no two numbers can be lessened. 3. Multiply the quotients and the divisor or divisors, and the product will be the least common denominator; into which, divide each...
Σελίδα 29 - Scale: 4 farthings (far.) = 1 penny (d.); 12 pence = 1 shilling (s.) ; 20 shillings — 1 pound (£). 156.
Σελίδα 100 - Reduce compound fractions to simple ones, and mixt numbers to improper fractions ; then multiply the numerators together for a new numerator, and the denominators for. a new denominator.
Σελίδα 31 - WEIGHT. 16 drams (dr.) make 1 ounce, marked oz. 16 ounces 1 pound Ib. 28 pounds 1 quarter qr. 4 quarters 1 hundred weight cwt. 20 hundred weight 1 ton T.