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CACE 11. When the initipler crisists of several figures. Rule.-The multipier being p.-ced under the multiplicand, unius under units, tens un er lens, &c. multiply by each significant figure in the multiplier separaly, facing the first figure in each product exactly under its multiplier : t'in add the several products togetha in the same order as the;sic n, and their sum will be the total product

ET PLES.
What number is e..u... in 47 times 3653

Multiplicand, 3 6 5
Multiplier,

4 7

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14. Multiply 760483 by 9152. Ans. 6959910416. 15. What is the total product of 7608 times 365432.

Ans. 2780206656. 16. What number is equal to 40003 times 4897685.

Ans. 195922093055.

CASE III. When there are ciphers on the right hand of either or both of the factors, neglect those cif bers; then place the significant figures under one another, and multiply by them anly, and to the right ha. d of the product, place as many rephers as were omitted in both the factors.

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7065000 X 8700=61465500000 749643000 x 695000=521001885000000

360000 x 1200000=432000000000 t

CASE IV. When the multiplier is a composite number, that is, when it is produced by multiplying any two numbers in the table Logether, multiply first by one of these figures, sic that

c: 2

product by the other, and the last product will be the total required.

EXAMPLES.

Multiply 41364 by 35

7

7 x 5=35.

289548 Product of 7.

5

1447740 Product of 35

2. Multiply 764131 by 48.

Ans. 306782 8. Multiply 312516 by 56.

Ans. 19180896 4. Multiply 209 102 by 72.

Ans. 15076944. 5. Multiply 91738 by 81.

Ans. 7130778. 6. Multiply 34462 by 108.

Ans. 3721896. 7. Multiply 615243 by•144.

Ans. 88591992

CASE V. To multiply by 10, 100, 1000, Sur.. alrex to the muli plicand all the ciphers in the multipl'r, and it will make the product required

EXAMPLES.

1. Multiply 365 hy 10.

Ans. 3650 2. Multiply 4657 lv 100.

Ans. 465700 3. Multiply 5224 by 1000.

Ans. 5224100 4. Multiply 26460 by 10900. Ans. 264600XXO

EXAMPLES FOR LXERCISE. 1. Multiply 1203450 by 9004. Ans. 10835863300 2. Multiply 9087061 by 56708 Ans. 515309055188. 3. Multiply 8706514 by 67089. Ans, 524113:330416. 4 Multiply 4321209 by 12340) Ans. 5:33276081481, 5. Multiply 3456789 by 567090. Ins. 1960310474010, 6. Multiply 8496427 by 874359.' Ans. 7428927415293.

98763542 x 98763542=8751237228385764.

Application and Use of Multiplication. In making out bills of parcels, and in finding the value goods ; when the price jf one yard, pound, &c. is given Federal Money) to find the value of the whole quantity.

***Rule.-Multiply the given price and quantity together, as in

whole numbors, and the separatrix will be as many figures from the ight hand in the product as in the given price.

EXAMPLES.

1. What will 35 yards of broad- ) $. d. c. m. cloth come to, at

3, 4 9 6 per yard ?

3 5

17 4 8 0 104 8 8

Ans. $122, 3 60=122 dol

[lars, 36 cents. 2. What cost 35 Ib. cheese at 8 cents per lb. ?

,08

yord?

per ream ?

per lb. ?

Ans. $2, 80=2 dollars 80 cents. 3. What is the value of 29 pairs of men's shoes, at 1 dol56.51 cents per pair ?

Ans. $43, 79 cents. 4. What cost 131 yards of Irish linen, at 38 cents per

Ans. $49, 78 cents. 5. What cost 140 reams of paper, at 2 dollars 35 cents

Ans. $329. 1. What cost 144 lb. of hyson tea; at 3 dollars 51 cenis

Ans $505, 44 cents. 7. What cost 94 busliels of oats, at 33 cents per bushel?

Ans. $31, 2 cents. 8. What do 50 firkins of butter come to, at 7 dollars 1 : cents per firkin ?

Ans. $357. 9. What cost 12 cwt. of Mala ya raisins, at 7 dollars 31 cents per cwt. ?

Ans. $87, 72 cents. 10. Bought 37 horses for shipping, at 52 dollars per hear: what do they come to ?

Ans. $1924. 1. What is the amount of 500 lbs. of hog's-lard, at 1.1 cents per Ib. ?

Ans. $75 12. What is the value of 75 yards of satin, at 3 dollars 75 cents per yard ?

Ans. $281, 25. 13. What cost 367 acres of land, at 14 dols. 67 cents

A'us. $5383, 89 cents.

per acre ?

cents per

at 2,

14. What does 857 bls. pork come to, at 18 duls. Si bl. ?

Ans. $10223, 1 cent. 15. What does 15 tuns of hay come to, at 20 dols. 79 cts. per tun?

Aus. $311, 70 cents. 16. Find the amount of the following

BILL OF PARCELS.

New-London, March 9, 1814. 34 Mr. Jamis Paywell, Bought of William Merchant

$. cts. 28 lb. of Green Tea

15
per

Ib. 41 lb. of Coffee,

at 0, 21 34 lb. of Loaf Sugar,

at 0, 19 13 cwt. of Malaga Raisins at 7, 31 per crot. 35 firkins of Butter,

at 7, 14 per fir. 27 pairs of worsted Hose, at 1, 04 per pair. 94 bushels of Oats,

33
per

bus!. 29 pairs of men's Shoes, at 1, 12 per pair.

Amount, $511, 78. Received payment in full,

William MERCHANT

A SHORT RULE. Nore. The value of 100lbs. of any article will be jus as many dollars as the article is cents a pound.

For 100 lb. at 1 cent per lb.=100 cents=1 dollar.

100 lb. of beef at 4 cents a lb. comes to 400 cents dollars, &c.

at 0,

DIVISION OF WHOLE NUMBERS. SIMPLE DIVISION teaches to find how many tiine one whole number is contained in another; and also wha: remains; and is a concise way of performing several sub) tractions.

Four principal parts are to be noticed in Division : 1. The Dividend, or number given to be divided. 2. The Divisor, or number given to divide by.

3. The Quotient, or answer to the question, which showa how inany times the divisor is contained in the dividend.

4. The Remainder, which is always less than the divisor and of the same name with the Dividend.

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