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" By examining the above examples, it will be found that this purpose is effected, by multiplying the numerator of the dividend, by the denominator of the divisor, and the denominator of the dividend by the numerator of the divisor. "
Arithmetic: Being a Sequel to First Lessons in Arithmetic - Σελίδα 199
των Warren Colburn - 1824 - 267 σελίδες
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Analytical Institutions in Four Books: Originally Written in Italian, Τόμοι 1-2

Maria Gaetana Agnesi - 1801 - 724 σελίδες
...Fraftions 34. The Divifion of Fractions is performed by multiplying crofs-wife, that how divided. iS} by multiplying the numerator of the dividend by the denominator of the divifor, which product muft be the numerator of the fraction which is to be the quotient : and then...

A portable cyclopædia; or, Compendious dictionary of arts and sciences

C T. Watkins - 1810 - 1056 σελίδες
...value is diminished { •f product being less than the Dumber multiplied. Division.— Rule. Multiply the numerator of the dividend by the denominator of the divisor, and the product is the numerator of t tin' quotient: then mut iply the deno> minntur of the dividend by the...

The Modern Preceptor Or a General Course of Education: Containing ..., Τόμος 1

John Dougall - 1810 - 554 σελίδες
...by multiplication «f mixed numbers. SK DIVISION DIVISION OF VULGAR FRACTIONS. Division is performed by multiplying the numerator oF the dividend by the denominator of the divisor, for a numerator to the quotient, and the denominator, of the dividend by the numerator of the divisor,...

The Young Man's Best Companion and Guide to Useful Knowledge

John Dougall - 1815 - 514 σελίδες
...!«'><;} feet. DIVISION OF VUIGAR FRACTIONS. Division is performed by cross multiplication : that is by multiplying the numerator of the dividend by the denominator of the divisor ; for a numerator to the quotient, and the denominator of the dividend by the numerator of the divisor,...

An Introduction to the Elements of Algebra: Designed for the Use of Those ...

Leonhard Euler - 1821 - 380 σελίδες
...represented simply by the division of ad by bc ; which gives r— . Hence the following rule : Multiply the numerator of the dividend by the denominator of the divisor, and the denominator q/\ the dividend by the numerator ojj the divisor ; the first product will be the numerator of the...

An Elementary Treatise on Arithmetic: Taken Principally from the Arithmetic of

Silvestre François Lacroix - 1825 - 394 σελίδες
...represented simply by the division of ad by bc ; which gives r— . Hence the following rule : Multiply the numerator of the dividend by the denominator of the divisor, and tlie denominator of tlie dividend by the numerator of the divisor ; tlie first product unll be the...

Arithmetic Upon the Inductive Method of Instruction: Being a Sequel to ...

Warren Colburn - 1826 - 264 σελίδες
...either or both of the numbers are mixed numbers, they must first be reduced to improper fractions. Note. As the common denominator itself is not used in the...operation, it is not necessary actually to find it, but onlji to multiply the numerators by the proper numbers to reduce them. By examining the above examples,...

Arithmetic Upon the Inductive Method of Instruction: Being a Sequel to ...

Warren Colburn - 1828 - 288 σελίδες
...either or both of the numbers are mixed numbers, they must first be reduced to improper fractions. Note. As the common denominator itself is not used in the...purpose is effected, by multiplying the numerator ef the dividend by the denominator of the divisor, and the denominator of the dividend by the numerator...

An Introduction to Algebra Upon the Inductive Method of Instruction

Warren Colburn - 1831 - 282 σελίδες
...is — о a dadado part of bc ad a Ans. — ad Hence, to divide a fraction by a fraction, multiply the numerator of the dividend by the denominator of the divisor, and the denominator of tJie dividend by the numerator of the divisor. Or more generally, when the divisor is a fraction, multiply...

Arithmetic Simplified in Three Parts

Catharine Esther Beecher - 1833 - 296 σελίδες
...the answer is i|, and it is the same process, as if we had not inverted the divisor, but multiplied the numerator of the dividend by the denominator of the divisor and its denominator by the numerator of the divisor. This method therefore is given as the easiest rule,...




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