 | William Smyth - 1830 - 278 σελίδες
...units and tens, is composed of three parts, viz. the square of the tens, plus twice the product of the tens multiplied by the units, plus the square of the units. Thus in 2209, the square of 47, we have The square of the tens (a2) = 1600 twice the tens by the units... | |
 | Charles William Hackley - 1846 - 542 σελίδες
...the square of the tens, the remainder, 1184, contains, as we have seen above, twice the product of the tens multiplied by the units plus the square of the units. But the product of the tens multiplied by the units must be tens, or have one cipher on the right,... | |
 | James Robinson (of Boston.) - 1847 - 304 σελίδες
...every number composed of tens and units must contain the square of the tens, plus twice the product of the tens multiplied by the units, plus the square of the units. We will now reverse the process of finding the second power of 40 -f- 8, and we shall obtain one of... | |
 | Rufus Putnam - 1850 - 274 σελίδες
...tens from the given cube, the remainder contains three times the square of the tens, plus three times the tens multiplied by the units, plus the square of the units, all multiplied by the units. (Why?) (97.) Therefore, dividing the cd 1744 remainder by the former factor,... | |
 | Daniel Leach - 1851 - 280 σελίδες
...(40)2~4800. 302. The complete divisor is always three times the square of the tens, phis three times the tens, multiplied by the units, plus the square of the units / as? 3 (40)2+3 (40x5)+52zz:5425. 303. The difference between any trial divisor and the next complete... | |
 | Daniel Leach - 1853 - 622 σελίδες
...(40+5 )a= 3 (40)3 +6(40X5)+3(5)2=6075. It is evident, from the preceding propositions, that three times the tens multiplied by the units, plus the square of the units, added to any trial divisor, will give the next complete divisor. It is also evident, that the difference... | |
 | William Smyth - 1855 - 370 σελίδες
...units and tens, is composed of three parts, viz. the square of the tens, plus twice the product of the tens multiplied by the units, plus the square of the units. Thus in 2209, the square of 47, we have The square of the tens (a2) = 1600 Twice the tens by the units... | |
 | 1856 - 46 σελίδες
...that number. The square of any number is equal to the square of the tens, plus twice the product of the tens multiplied by the units, plus the square of the units. 1. What is the product of 125 multiplied by 125 ? Solution. 120 x 120 = 14400 + 120 x 5 x 2 = 15600... | |
 | Benjamin Greenleaf - 1857 - 452 σελίδες
...tens, hundreds, &c. of .the square root of the number. 2. The square of a number consisting O/TENS and UNITS is equal to the square of the tens, plus twice the product of the tens into the units, plus the square of the units. Thus, if the tens of a number be... | |
 | Benjamin Greenleaf - 1858 - 456 σελίδες
...lens, hundreds, &c. of the square root of the number. 2. The square of a number consisting O/"TENS and UNITS is equal to the square of the tens, plus twice the product of the tens into the units, plus the square of the units. Thus, if the tens of a number be... | |
| |
The square of a number composed of tens and units is equal to the square of the tens, plus twice the product of the tens by the units, plus the square of the units. tens' + 2 x tens x units + units 
