Elements of Algebra: For Colleges, Schools, and Private Students, Βιβλίο 2Wilson, Hinkle & Company, 1866 - 406 σελίδες |
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Αποτελέσματα 1 - 5 από τα 34.
Σελίδα 15
... consisting of three terms ; as , a + b — c . 27. The Numerical Value of an algebraic expression is the number obtained by giving a particular value to each letter , and then performing the operations indicated . Thus , in the algebraic ...
... consisting of three terms ; as , a + b — c . 27. The Numerical Value of an algebraic expression is the number obtained by giving a particular value to each letter , and then performing the operations indicated . Thus , in the algebraic ...
Σελίδα 45
... consists of two factors , b and am — 1 — ¿ m — 1 . Now , if the second of these factors , viz . , am — 1 — ¿ m — ì , is divisible by a — b , then will the quantity am — bm be divisible by a -- b . That is , If the difference of the same ...
... consists of two factors , b and am — 1 — ¿ m — 1 . Now , if the second of these factors , viz . , am — 1 — ¿ m — ì , is divisible by a — b , then will the quantity am — bm be divisible by a -- b . That is , If the difference of the same ...
Σελίδα 74
... consists of an unlimited num . ber of terms which observe the same law . The Law of a Series is a relation existing between its terms , such as that when some of them are known the others may be found . Thus , in the infinite series 1 ...
... consists of an unlimited num . ber of terms which observe the same law . The Law of a Series is a relation existing between its terms , such as that when some of them are known the others may be found . Thus , in the infinite series 1 ...
Σελίδα 87
... consists of two distinct parts : 1st . Expressing the conditions of the problem in algebraic language ; that is , forming the equation . 2d . Solving the equation ; that is , finding the value of the unknown quantity . Sometimes the ...
... consists of two distinct parts : 1st . Expressing the conditions of the problem in algebraic language ; that is , forming the equation . 2d . Solving the equation ; that is , finding the value of the unknown quantity . Sometimes the ...
Σελίδα 97
... consists in finding the value of one of the unknown quantities in one of the equations , and substituting this value in the other equa- tion 2d Bk . 9 * To explain this method , let it be required to SIMPLE EQUATIONS . 97.
... consists in finding the value of one of the unknown quantities in one of the equations , and substituting this value in the other equa- tion 2d Bk . 9 * To explain this method , let it be required to SIMPLE EQUATIONS . 97.
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Άλλες εκδόσεις - Προβολή όλων
Συχνά εμφανιζόμενοι όροι και φράσεις
2d Bk algebraic ALGEBRAIC QUANTITIES arithmetical progression binomial Binomial Theorem coefficient common divisor Completing the square Corollary cube root decimal degree denominator derived polynomial Divide dividend division equa equal roots equation containing equation whose roots evident example exponent Extract the square factors Find the cube find the number Find the square Find the sum find the value geometrical progression given equation given number gives greater greatest common divisor Hence imaginary inequality less letters logarithms method minus monomial Multiply negative roots nth root number of balls number of terms perfect square positive root preceding Proposition quadratic equation quotient ratio real roots reduced remainder Required the number required to find result second term solved square root Sturm's theorem substituted subtracted taken Theorem third tion transform transposing trinomial unity unknown quantity Whence whole number X₁
Δημοφιλή αποσπάσματα
Σελίδα 136 - Multiply the divisor, thus increased, by the last figure of the root; subtract the product from the dividend, and to the remainder bring down the next period for a new dividend.
Σελίδα 289 - Take the first term from the second, the second from the third, the third from the fourth, &c. and the remainders will form a new series, called the first order of
Σελίδα 35 - Obtain the exponent of each literal factor in the quotient by subtracting the exponent of each letter in the divisor from the exponent of the same letter in the dividend; Determine the sign of the result by the rule that like signs give plus, and unlike signs give minus.
Σελίδα 39 - Divide the first term of the dividend by the first term of the divisor, and write the result as the first term of the quotient. Multiply the whole divisor by the first term of the quotient, and subtract the product from the dividend.
Σελίδα 148 - ... by the last figure of the root, and subtract the product from the dividend ; to the remainder bring down the next period for a new dividend.
Σελίδα 187 - CD, and, on meeting, it appeared that A had traveled 18 miles more than B ; and that A could have gone B's journey in 15 £ days, but B would have been 28 days in performing A's journey.
Σελίδα 68 - Reduce the fractions to a common denominator ; then subtract the numerator of the subtrahend from the numerator of the minuend, and write the result over the common denominator. EXAMPLES. H ,_, Zx . ^ 3x 1. From -^- subtract — . oo . Eeducing to a common denominator, the fractions become Wx 9x "15...
Σελίδα 37 - Since, in multiplying a polynomial by a monomial, we multiply each term of the multiplicand by the multiplier ; therefore, we have the following RULE, FOR DIVIDING A POLYNOMIAL BY A MONOMIAL. Divide each term of the dividend, by the divisor, according to the rule for the division of monomials.
Σελίδα 236 - In any proportion the product of the means is equal to the product of the extremes.
Σελίδα 43 - The square of the difference of two quantities is equal to the square of the first minus twice the product of the first by the second, plus the square of the second.