 | Silas Totten - 1836 - 332 σελίδες
...7bd Ans. .•; — . 6ac DIVISION OF POLYNOMIALS. To divide a Polynomial by a Monomial. RULE. (15.) Divide each term of the dividend by the divisor, according to the preceding rule, observing, that when the signs of the divisor and dividend are alike, the quotient... | |
 | Thomas Sherwin - 1841 - 314 σελίδες
...different signs, that is, one -\- and the other — , the quotient must have thf sign — . Art. 42. Hence, we have the following RULE FOR DIVIDING A POLYNOMIAL,...term of the dividend by the divisor, according to the principles given in Art. 4O for dividing one monomial by another, observing the rule established above... | |
 | Thomas Sherwin - 1844 - 320 σελίδες
...-f- and the other —, the quotient must have the sign—. Art. 42. Hence, we have the following ROLE FOR DIVIDING A POLYNOMIAL BY A MONOMIAL. Divide each...term of the dividend by the divisor, according to the principles given in Art. 4O for dividing one monomial by another, observing the rule established above... | |
 | Joseph Ray - 1848 - 252 σελίδες
...a polynomial by a monomial, we multiply each term of the multiplicand by the multiplier; therefore, we have the following RULE, FOR DIVIDING A POLYNOMIAL...of the dividend, by the divisor, according to the mle for the dimsion of monomials. EXAMPLES. 1. Divide 6z+12y by 3 Ans. 2x+4y. 2. Divide 15z— 206... | |
 | Joseph Ray - 1848 - 250 σελίδες
...the multiplicand by the multiplier; therefore, we have the following RULE, FOR DIVIDING A POLVNOMIAL BY A MONOMIAL. Divide each term of the dividend, by the divisor, according to the rule for the divvsion of monomials. EXAMPLES. 1. Divide 6x+l 2y by 3 ........... Ans. 2x+4y. 2. Divide 15x-206by5... | |
 | Joseph Ray - 1852 - 408 σελίδες
...— J2)Xa=o2i — ai>2; hence, (a2i— aZ>2)-ja=ak—&2 ; therefore, we have the following RULE FOK DIVIDING A POLYNOMIAL BY A MONOMIAL. — Divide each...according to the rule for the division of monomials. EXAMPLES FOR PRACTICE. 1. Divide a2+ai by a. Am. a-}-b 2. Divide 3m/-(-2a:2y by — xy. Ans. — 3—... | |
 | Joseph Ray - 1848 - 250 σελίδες
...we multiply each term of the multiplicand by the multiplier; therefore, we have the following BULB FOR DIVIDING A POLYNOMIAL BY A MONOMIAL. Divide each...term of the dividend, by the divisor, according to th« rtde for the division of monomials. EXAMPLES. 1. Divide 6z+12y by 3 Ans. 2x+4y. 2. Divide 15x—... | |
 | Thomas Sherwin - 1855 - 318 σελίδες
...— , the quotient must have the sign — . Art. 42. Hence, we have the following RULE FOR JUVJI'IM; A POLYNOMIAL BY A MONOMIAL. Divide each term of the dividend by the divisor, according to the principles given in Art. 4O for dividing one monomial by another, observing the rule established above... | |
 | Thomas Sherwin - 1855 - 262 σελίδες
...From what precedes, we derive the following RULE FOR THE DIVISION OF A POLYNOMIAL BY A MONOMIAL. 1. Divide each term of the dividend by the divisor, according to the rule for dividing one monomial by another ; the partial quotients, taken together, will form the entire quotient.... | |
 | Joseph Ray - 1857 - 408 σελίδες
...by the multiplier. Thus, (db — J2)Xo=o26 — a62; hence, (a26 — ab2)-za=.=ab — b2 ; therefore, we have the following RULE FOR DIVIDING A POLYNOMIAL...according to the rule for the division of monomials. EXAMPLES TOR PRACTICE. 1. Divide a2-|-«6 by a. Ans. a-\-b 2. Divide 3xy-\-2x2y by — xy. Ans. —... | |
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Since, in multiplying a polynomial by a monomial, we multiply each term of the multiplicand by the multiplier ; therefore, we have the following RULE, FOR DIVIDING A POLYNOMIAL BY A MONOMIAL. Divide each term of the dividend, by the divisor, according... 
