Ans. $43,79 cts.

7. What is the value of 29 pairs of men's shoes, at 1 dollar 51 cents per pair? 8. What cost 140 reams of paper, at 2 dollars 35 cents per ream? Ans. $329. 9. In one pipe of wine there are 126 gallons; how many gallons are there in 15 pipes? Ans. 1890 galls.

10. A merchant bought at one time 278 barrels of fish: at another time three times as many, wanting 184 barrels, at 9 dollars per barrel; what did he pay for the whole ? Ans. $8352.

11. A man bought 675 sheep, at 2 dollars 25 cents per head; also, 46 pigs, at 2 dollars per head; what did he pay for the whole? Ans. $1610,75 cts.

12. A gentleman bought 2428 barrels of flour at one time; at another time as many as at the first, wanting 987 barrels; he lost as many as he bought at the last time, wanting 764 barrels; sold the remainder at 8 dollars per barrel; what did they come to? Ans. $25536. 13. What will one year's board come to, at 6 dollars per week? Ans. $312. 14. What will 40,000 brick cost, at 3 dollars per thousand? Ans. $120,000.

SIMPLE DIVISION

TEACHETH to find how often one number is contained in another of the same name.

The number to be divided is called the dividend. The number by which to divide is called the divisor. The number of times the divisor is contained in the dividend is called the quotient.

The remainder, if there be any, will always be less than the divisor.

Rule. On the right and left of the dividend draw a curved line, and write the divisor on the left hand, and the quotient, as it arises, on the right. Find how many

times the divisor is contained in as many figures as are necessary in the dividend, and write the number in the quotient.

Multiply the divisor by the quotient figure, and set the product under that part of the dividend used.

Subtract the product last found from that part of the dividend under which it is placed, and to the right hand of the remainder bring down the next figure of the dividend; divide this number as before, and so on, till the whole is finished. If it be necessary to bring down more figures than one to the remainder, in order to make it as large as the divisor, a cipher must be written in the quotient for every figure so brought down, till the number be sufficient to contain the divisor.

Proof. Multiply the quotient by the divisor, and to the product add the remainder, and the sum will be equal to the dividend, if the work is right. When there are ciphers annexed to the divisor, cut off the ciphers from it, and the same number of digits from the dividend, then divide the remaining figures by each other, as usual, the quotient is the answer; and what remains, placed before the figures cut off, is the true remainder.

When the divisor does not exceed twelve, or is a composit number, or when ciphers may be cut off from it, the division may be shortened by multiplying and dividing mentally, and writing the quotient under the dividend.