The geometry, by T. S. Davies. Conic sections, by Stephen FenwickJ. Weale, 1853 |
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Αποτελέσματα 1 - 5 από τα 100.
Σελίδα 4
... wherefore CA , AB , BC are equal to one another ; and the triangle ABC is therefore equilateral , and it is described upon the given straight line AB . Which was required to be done . PROPOSITION II . PROB . From a given point to draw a ...
... wherefore CA , AB , BC are equal to one another ; and the triangle ABC is therefore equilateral , and it is described upon the given straight line AB . Which was required to be done . PROPOSITION II . PROB . From a given point to draw a ...
Σελίδα 5
... wherefore AL and BC are each of them equal to BG ; and things that are equal to the same are equal ( 1 Ax . ) to one another ; therefore the straight line AL is equal to BC . Wherefore from the given point A a straight line AL has been ...
... wherefore AL and BC are each of them equal to BG ; and things that are equal to the same are equal ( 1 Ax . ) to one another ; therefore the straight line AL is equal to BC . Wherefore from the given point A a straight line AL has been ...
Σελίδα 6
... wherefore also the point C shall coincide with the point F , because the straight line AC ( Hyp . ) is equal to DF : But the point B coincides with the point E ; wherefore the base BC shall coincide with the base EF , because the point ...
... wherefore also the point C shall coincide with the point F , because the straight line AC ( Hyp . ) is equal to DF : But the point B coincides with the point E ; wherefore the base BC shall coincide with the base EF , because the point ...
Σελίδα 7
... Wherefore , if two angles , etc. Q. E. D. COR . Hence every equiangular triangle is also equilateral . PROPOSITION VII . THEOR . Upon the same base , and on the same side of it , there cannot be two triangles that have their sides which ...
... Wherefore , if two angles , etc. Q. E. D. COR . Hence every equiangular triangle is also equilateral . PROPOSITION VII . THEOR . Upon the same base , and on the same side of it , there cannot be two triangles that have their sides which ...
Σελίδα 8
... wherefore the angle FDC is likewise greater than BCD ; much more then is the angle BDC greater than the angle BCD . Again , because CB is equal ( Hyp . ) to DB . the angle BDC is equal ( 5. 1. ) to the angle BCD ; but BDC has been ...
... wherefore the angle FDC is likewise greater than BCD ; much more then is the angle BDC greater than the angle BCD . Again , because CB is equal ( Hyp . ) to DB . the angle BDC is equal ( 5. 1. ) to the angle BCD ; but BDC has been ...
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ABCD axis base bisected called centre circle circumference coincide common cone construction contained coordinate curve described diameter difference dihedral angles direction distance divided double draw drawn edges ellipse equal equal angles equimultiples extremities faces figure formed four fourth given line given point greater hence horizontal inclination intersection join less likewise magnitudes manner meet method multiple opposite parallel parallelogram pass perpendicular perspective picture plane MN plane of projection position preceding prisms problem produced projector Prop proportional PROPOSITION proved ratio reason rectangle remaining respectively right angles SCHOLIUM segment shown sides similar sphere square straight line surface taken tangent THEOR third touch trace transverse triangle triangle ABC trihedral vertex vertical Whence Wherefore whole
Δημοφιλή αποσπάσματα
Σελίδα 19 - That, if a straight line falling on two straight lines make the interior angles on the same side less than two right angles, the two straight lines, if produced indefinitely, meet on that side on which are the angles less than the two right angles.
Σελίδα 35 - If a straight line be divided into two equal parts, and also into two unequal parts ; the rectangle contained by the unequal parts, together with the square on the line between the points of section, is equal to the square on half the line.
Σελίδα 4 - AB; but things which are equal to the same are equal to one another...
Σελίδα 128 - EQUIANGULAR parallelograms have to one another the ratio which is compounded of the ratios of their sides.* Let AC, CF be equiangular parallelograms, having the angle BCD equal to the angle ECG : the ratio of the parallelogram AC to the parallelogram CF, is the same with the ratio which is compounded of the ratios of their sides. Let BG, CG, be placed in a straight line ; therefore DC and CE are also in a straight line (14.
Σελίδα 8 - If two triangles have two sides of the one equal to two sides of the...
Σελίδα 36 - If a straight line be bisected and produced to any point, the rectangle contained by the whole line thus produced and the part of it produced...
Σελίδα 21 - BCD, and the other angles to the other angles, (4. 1.) each to each, to which the equal sides are opposite : therefore the angle ACB is equal to the angle CBD ; and because the straight line BC meets the two straight lines AC, BD, and makes the alternate angles ACB, CBD equal to one another, AC is parallel (27. 1 .) to DB ; and it was shown to be equal to it. Therefore straight lines, &c.
Σελίδα 65 - If a straight line touch a circle, and from the point of contact a straight line be drawn cutting the circle, the angles which this line makes with the line touching the circle shall be equal to the angles which are in the alternate segments of the circle.
Σελίδα 4 - Magnitudes which coincide with one another, that is, which exactly fill the same space, are equal to one another.
Σελίδα 116 - If two triangles have one angle of the one equal to one angle of the other and the sides about these equal angles proportional, the triangles are similar.