Euclid's Elements of geometry, the first three books (the fourth, fifth, and sixth books) tr. from the Lat. To which is added, A compendium of algebra (A compendium of trigonometry).1846 |
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Σελίδα
... evident that he was not the author of all under that title ; yet even the compilation of such a work would be sufficient to deserve the praise he has received from all enlightened nations . Apollonius was cotemporary with Archimedes ...
... evident that he was not the author of all under that title ; yet even the compilation of such a work would be sufficient to deserve the praise he has received from all enlightened nations . Apollonius was cotemporary with Archimedes ...
Σελίδα 41
... evident by itself . 5. A theorem is a truth which becomes evident by means of a reasoning called demonstration . 6. A problem is a question proposed , which requires a solution . 7. A lemma is a truth employed subsidiarily for the ...
... evident by itself . 5. A theorem is a truth which becomes evident by means of a reasoning called demonstration . 6. A problem is a question proposed , which requires a solution . 7. A lemma is a truth employed subsidiarily for the ...
Σελίδα 46
... evident the rectangle BL , is equal to the rectangles BG , DK , and EL , but the rectangle BL , is the rectangle under A and BC ; for BF is equal to A ; but the rectangles BG , DK , and EL , are the rectangles under A and BD , A and DE ...
... evident the rectangle BL , is equal to the rectangles BG , DK , and EL , but the rectangle BL , is the rectangle under A and BC ; for BF is equal to A ; but the rectangles BG , DK , and EL , are the rectangles under A and BD , A and DE ...
Σελίδα 47
... evident the area of a rectangle is found , by multiplying the altitude into the base ; and from Prop . 35 and 36 , B. 1 , the area of any parallelogram is found by multiplying the altitude into the base : and from Prop . 37 and 38 , B ...
... evident the area of a rectangle is found , by multiplying the altitude into the base ; and from Prop . 35 and 36 , B. 1 , the area of any parallelogram is found by multiplying the altitude into the base : and from Prop . 37 and 38 , B ...
Σελίδα 50
... evident . But if they be not bisected , let there be AB and CD , and divide them in E and F. Let them be bisected in G and H , and because the right lines themselves are equal , ( by Hypoth . ) , the halves of them will be equal , and ...
... evident . But if they be not bisected , let there be AB and CD , and divide them in E and F. Let them be bisected in G and H , and because the right lines themselves are equal , ( by Hypoth . ) , the halves of them will be equal , and ...
Συχνά εμφανιζόμενοι όροι και φράσεις
absurd AC and CB AC by Prop AC is equal angle ABC angle equal angles by Prop arch bisected centre circumference co-efficient Const construct contained oftener diameter divided divisor double equal angles equal by Constr equal by Hypoth equal by Prop equal right lines equal to AC equal to twice equi-multiples equi-submultiples equiangular equilateral external angle fore fraction given angle given circle given line given right line given triangle greater half a right inscribed less multiplied opposite parallel parallelogram perpendicular PROPOSITION quantities quotient ratio rectangle under AC remaining angles remaining side right angle right line AB right line AC SCHOL segment semicircle side AC similar similarly demonstrated squares of AC submultiple subtract THEOREM tiple touches the circle triangle BAC twice the rectangle twice the square whole
Δημοφιλή αποσπάσματα
Σελίδα 20 - If two triangles have two sides of the one equal to two sides of the...
Σελίδα 30 - DE : but equal triangles on the same base and on the same side of it, are between the same parallels ; (i.
Σελίδα 209 - ... they have an angle of one equal to an angle of the other and the including sides are proportional; (c) their sides are respectively proportional.
Σελίδα 218 - If two triangles have one angle of the one equal to one angle of the other and the sides about these equal angles proportional, the triangles are similar.
Σελίδα 114 - To reduce fractions of different denominators to equivalent fractions having a common denominator. RULE.! Multiply each numerator into all the denominators except its own for a new numerator, and all the denominators together for a common denominator.
Σελίδα 90 - The angle in a semicircle is a right angle ; the angle in a segment greater than a semicircle is less than a right angle ; and the angle in a segment less than a semicircle is greater than a right angle.
Σελίδα 129 - In any proportion, the product of the means is equal to the product of the extremes.
Σελίδα 163 - Magnitudes are said to be in the same ratio, the first to the second and the third to the fourth, when, if any equimultiples whatever be taken of the first and third, and any equimultiples whatever of the second and fourth, the former equimultiples alike exceed, are alike equal to, or alike fall short of, the latter equimultiples respectively taken in corresponding order.
Σελίδα 215 - ... are to one another in the duplicate ratio of their homologous sides.
Σελίδα 160 - PROPOSITION XV. PROBLEM. To inscribe an equilateral and equiangular hexagon in a given circle. Let ABCDEF be the given circle.