EXAMPLES. 1. How much shalloon that is yard wide, will line 5§ yards of cloth which is 14 yard wide? Yds. yds. yds. Yds. As 15 And 7× ×=385=16,1 Ans. 2. If a man perform a journey in 3 days, when the day is 12 hours long; in how many days will he do it. when the day is but 9 hours. 3. If 15 men in 113days, mow 21 days will 8 men do the same. 4. How much in length that is 7 make a square foot? Ans.44 days. acres, in how many Ans. 1823 days. inches broad, will Ans. 20 inches. 5. If 254s. will pay for the carriage of an cwt. 1454. miles; how far may 63 cwt. be carried for the same mo ney? Ans. 22 miles. 222% 6. How many yards of baize which is 14 yards wide, will line 187 yards of camblet 4 yd. wide? Ans. 11yds. 1qr. 11⁄2 na. RULE OF THREE DIRECT IN DECIMALS. RULE. REDUCE your fractions to decimals, and state your question as in whole numbers: multiply the second and third together; divide by the first, and the quotient will be the answer, &c. EXAMPLES. 1. If of a yd. cost of a pound; what will 15 yds. come to? Yds. As ,875,583 :: 7,875,583+and =,75 Yds. £. £• £.'s. d. qrs. 15,75: 10,494≈10 9 10 2,24 Ans. 2. If 1 pint of wine cost 1,2s. what cost 12,5 hhds. ? Ans. £.378 3. If 4 yds. cost 3s. 44d. what will 30g yds. cost? Ans. £.1 4s. 3d, 3qrs.+ 1 4. If 1,4 cwt. of sugar cost 10 dols. 9 cts. what will 9 cwt. 3 qrs. cost at the same rate? cwt. As 1,4 come to ? 10,09: : 9,75: 70,269-870, 26cts. 9m.+ 5. If 19 yards cost 25,75 dols. what will 435 yards Ans. $590, 21cts. 7m. 6. If 345 yards of tape cost 5 dols. 17 cents, 5m. what will 1 vard cost? Ans. ,015 1cts. 7. If a man lays out 121 dols. 23 cts. in merchandize, and thereby gains 39,51 dols. how much will he gain in laying out 12 dollars at the same rate ? ins. 3,91 dols. =$3, 91cts. 8. How many yards of ribbon can I buy for 25 dols. if 29 yds. cost 44 dollars ? Ans. 1784 yards. 9. If 178 yds. cost 25 dollars, what cost 293 yards? Ans. $44 10. If 1,6 cwt. of sugar cost 12 dols. 12 cts. what cost 3 hhds. each 11 cwt. 3 qrs. 10,12 lb. ? Ans. 269,072 dols.=$269, 7cts. 2m.+ SIMPLE INTEREST BY DECIMALS. Ratio is the simple interest of 11. for one year; or in federal money, of $1 for one year, at the rate per cent. agreed on. RULE. Multiply the Principal, Ratio and time continually together, and the last product will be the interest required. EXAMPLES. 1. Required the interest of 211 dols. 45 cts. for 5 years, at 5 per cent. per annum? $cts. 211,45 Principal. 10,5725 Interest for one year. 52,8625 Ans. 852, 86cts. 24m. 2. What is the interest of 645l. 10s. for 3 years, at 6 per cent. per annum ? £645,5X06×3=116,190=116 3s. 9d. 2,4grs. Ans. 3. What is the interest of 121l. 8s. 6d. for 4 years, at 6 per cent. per annum ? Ans. £32 15s. 8d. 1,36qrs. 4. What is the amount of 556 dollars 39 cents, for 14 years, at 6 per cent. per annum ? Ans. $584,6651 5. Required the amount of 648 dols. 50 cts. for 12 yrs. at 5 per cent. per annum? Ans. $1103, 26cts. + CASE II. The amount, time and ratio given, to find the principal. RULE. Multiply the ratio by the time, add unity to the product for a divisor, by which sum divide the amount, and the quotient will be the principai. EXAMPLES. 1. What principal will amount to 1235,975 dollars, in 5 years, at 6 per cent. per annum ? $ ,06×5+1=1,30)1235,975(950,75 Ans. 2. What principal will amount to 873l. 19s. in 9 years, at 6 per cent. per annum? Ans. £567 10s. 3. What principal will amount to 626 dols. 6 cts. in 12 years, at 7 per cent. ? Ans. $340,25=$340, 25cts. 4. What principal will amount to 956l. 10s. 4,125d. in 8 years, at 5 per cent. ? Ans. £645 15s. CASE III. The amount, principal and time given, to find the ratio. RULE. Subtract the principal' from the amount, divide the remainder by the product of the time and principal, and the quotient will be the ratio. 1. At what rate per cent, will 950,75 dols. amount to 1235,975 dols. in 5 years? 285,2250 950,75×5=4753,75)285,2250(,06-6 per cent Ans. 2. At what rate per cent. will 5677. 10s. amount to 8731. 19s. in 9 years? Ans. 6 per cent. Ans. 7 per cent. 3. At what rate per cent. will 340 dols. 25 cts. amount to 626 dols. 6 cts. in 12 years? 4. At what rate per cent. will 645l. 15s. amount to 956l. 10s. 4,125d. in 83 years ? CASE IV. Ans. 5 per cent. cent. given, to find Subtract the principal from the amount; divide the remainder by the product of the ratio and principal; and the quotient will be the time. EXAMPLES. annum ? 1. In what time will 950 dols. 75 cts. amount to 1235 dollars, 97,5 cents, at 6 per cent. per From the amount $1235,975 Take the principal 950,75 950,75X06=57,0450)285,2250(5 years, Ans. 285,2250 2. In what time will 5677. 10s. amount to 8731. 19s. Ans. 9 years. at 6 per cent. per annum ? 3. In what time will 340 dols. 25 cts. amount to 626 dols. 6 cents at 7 per cent. per annum ? Ans. 12 years. 4. In what time will 645l. 15s. amount to 956l. 10s.. 4,125d. at 5 per ct. per annum ? Ans.8,75=84 years. TO CALCULATE INTEREST FOR DAYS. RULE. Multiply the principal by the given number of days, and that product by the ratio; divide the last product by 365 (the number of days in a year) and it will give the înterest required. EXAMPLES. 1. What is the interest of 360l. 10s. for 146 days, at 6 per cent. ? 360,5x146x,06 365 £. s. d. qrs. =8652-8 13 0 1,9 Ans. Ans. $10,53cts.+ Ans. £4,1235=4l. 2s. 54d.+ 2. What is the interest of 640 dols. 60 cts. for 100 days 3. Required the interest of 250l. 17s. for 120 days at 4. Required the interest of 481 dollars 75 cents, for 25 at 6 per cent. per annum ? 5 per cent. per annum? days, at 7 per cent. per annum ? Ans. $2, 30cts. 9m.+ A TABLE, showing the number of Days from any day of one month, to the same day of any other month. FROM ANY DAY OF Jan. Feb. Mar Ap'l. May June July Aug. Sept. Oct. Nov Dec. Feb. 31 31 365 337 306 276 245 215 184 153 123 92 62 Mar 59 28 365 334 304 273 243 212 181 151 120 Ap'l. 90 59 90 31 365 335 304 274 248 212 182 151 121 Oct. 273 242 214 183 153 122 30 365 334 303 273 242 212 30 365 334 304 92 |