 Prove that the square of the sum of any two numbers equals the square of the first number, plus twice the product of the two numbers, plus the square of the second number.  First Course in Algebra - Σελίδα 101των Walter Burton Ford, Charles Ammerman - 1919 - 334 σελίδεςΠλήρης προβολή - Σχετικά με αυτό το βιβλίο
 | Thomas Kerigan - 1828 - 776 σελίδες
...numbers. Thus, 10+6=16; now, 16x10= 160; 16x6 = 96; and 160 + 96 = 256. Again, 10+6=16; and 16x16=256. The square of the sum of any two numbers is equal to four times the square of half their sum. — Thus, 10+6= 16; and 16x16= 256; then 10 + 6= 16+2 = S,... | |
 | A. Turnbull - 1836 - 368 σελίδες
...be in the square root of any given square. At paragraph 4K4, it is shown by algebraical deduction, that the square of the sum of any two numbers, is equal to the sum of the squares of these two numbers added to twice ALGEBRAICALLY. their product, (o + b)' =: 0+6... | |
 | Thomas Kerigan - 1838 - 804 σελίδες
...numbers. Thus, 10+6= 16; now, 16x10= 160; 16x6 = 96; and 160 + 96 = 256. Again, 10+6= 16; and 16x 16= 256. The square of the sum of any two numbers is equal to four times the square of half their sum. — Thus, 10+6=16; and 16x16= 256; then 10+6= 16-1-2 = 8,... | |
 | Rufus Putnam - 1849 - 402 σελίδες
...(10 + 2)*; (Ю + 4)2; (10 + 5)*; (3 + 2)*; (5 + 3)*. From these examples and illustrations, wo see that the square of the sum of any two numbers is equal to the square of the first, plus twice the product of the first into the second, plus the square of the second. 5. Find by this... | |
 | George Roberts Perkins - 1849 - 344 σελίδες
...+ 8, is equal to 6 2 + 2x 6.8 + S 2 , which result may be thus expressed : The square of the sum of two numbers is equal to the square of the first number, plus twice the product of the first number into the second, plus the square of the second. If we wish the square of the sum of three... | |
 | George Roberts Perkins - 1849 - 346 σελίδες
...482=(40+8)2=402+2 x 40.8+82= 1600+640+64. From the above, we draw the following property : The square of the sum of two numbers is equal to the square of the first number, plus twice the product of the first number into the second, plus the square of the second. If we wish the square of the sum of three... | |
 | George Roberts Perkins - 1849 - 356 σελίδες
...third. Continuing in this way, we could show that, the square of the sum of any number of numbers is the square of the first number, plus twice the product of the first number into the second, plus the square of the second ; plus twice the product of the sum of... | |
 | George Roberts Perkins - 1850 - 364 σελίδες
...the sum of 6 and 8 into 9, plus the square of 9 Or in general terms, The square of the sum of three numbers is equal to the square of the first number, plus twice the product ofthejirst number into the second, plus the square of the second ; plus twice the product of the sum... | |
 | George Roberts Perkins - 1850 - 356 σελίδες
...the sum of 6 and 8 into 9, plus the square of 9. Or in general terms, The square of the sum of three numbers is equal to the square of the first number, plus twice the pfoduct of the first number into the second, plus the square of the second; plus twice the product... | |
 | George Roberts Perkins - 1851 - 356 σελίδες
...x 40.8+8 2 = 1600+640+64. From the above, we draw the following property: The square of the sum of two numbers is equal to the square of the first number, plus twice the product of the first number into the second, plus the square of the second. If we wish the square of the sum of three... | |
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