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PROPOSITION XII. THEOREM.

69. CONVERSELY: When two straight lines are cut by a third straight line, if the alternate-interior angles be equal, the two straight lines are parallel.

[blocks in formation]

Let E F cut the straight lines A B and C D in the points

H and K, and let the

AHK = ZH KD.

We are to prove

AB to C D.

then

Through the point H draw M N to CD;

[blocks in formation]

But

[blocks in formation]

.. A B, which coincides with MN, is to C D.

§ 68

Hyp.

Ax. 1.

Cons.

Q. E. D.

[blocks in formation]

70. If two parallel lines be cut by a third straight line, the exterior-interior angles are equal.

[blocks in formation]

Let A B and C D be two parallel lines cut by the straight line E F, in the points H and K.

[blocks in formation]

71. COROLLARY. The alternate-exterior angles, EHB and

CKF, and also A HE and D KF, are equal.

PROPOSITION XIV. THEOREM.

72. CONVERSELY: When two straight lines are cut by a third straight line, if the exterior-interior angles be equal, these two straight lines are parallel.

[blocks in formation]

Let EF cut the straight lines A B and C D in the points II and K, and let the EH B ZHKD.

We are to prove AB to CD.

=

Through the point H draw the straight line MN to CD.

[blocks in formation]

.. A B, which coincides with MN, is to CD.

Cons.

Q. E. D.

PROPOSITION XV. THEOREM.

73. If two parallel lines be cut by a third straight line, the sum of the two interior angles on the same side of the secant line is equal to two right angles.

[blocks in formation]

Let A B and C D be two parallel lines cut by the straight line EF in the points H and K.

ZBHK+ ZHKD = two rt. .

We are to prove

[blocks in formation]

PROPOSITION XVI. THEOREM.

74. CONVERSELY: When two straight lines are cut by a third straight line, if the two interior angles on the same side of the secant line be together equal to two right angles, then the two straight lines are parallel.

[blocks in formation]

Let EF cut the straight lines A B and C D in the points H and K, and let the BHK + Z HKD equal two right angles.

Then

But

We are to prove AB to CD.

Through the point I draw MN | to CD.

LNHK+ HKD = 2 rt. 4,

Z

(being two interior & on the same side of the secant line).

2 BHK + Z H K D = 2 rt. .

$73

Hyp.

Ax. 1.

[blocks in formation]

:. LNH K+ 2 H K D = 2 BHK + Z HKD.

But

.. the lines A B and M N coincide.

MN is to CD ;

.. A B, which coincides with MN, is to C D.

Cons.

Q. E D.

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