Euclid's Elements of geometry, transl. To which are added, algebraic demonstrations to the second and fifth books; also deductions in the first six, eleventh and twelfth books, with notes, by G. Phillips. Part 1, containing book i-vi1826 |
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Σελίδα 32
... AC is equal to the base DB , and the triangle ABC is equal to the triangle BCD . Therefore the diameter BC bisects ... square , at equal distances from the four angles , four other points be taken , one in each side , the figure contained by ...
... AC is equal to the base DB , and the triangle ABC is equal to the triangle BCD . Therefore the diameter BC bisects ... square , at equal distances from the four angles , four other points be taken , one in each side , the figure contained by ...
Σελίδα 40
... square . a E Let AB be the given right line . It is required upon the line AB to describe a square . Draw from the given point A the right line AC , at right angles to AB , and make AD equal to AB , and through the point D draw DE ...
... square . a E Let AB be the given right line . It is required upon the line AB to describe a square . Draw from the given point A the right line AC , at right angles to AB , and make AD equal to AB , and through the point D draw DE ...
Σελίδα 41
... square , and has been described on the given right line AB . Q. E. F. COROLLARY . Hence every parallelogram having ... AC , the squares GB , HC ; and through A draw AL parallel either to BD or CE , and join AD , Fc . Therefore because the ...
... square , and has been described on the given right line AB . Q. E. F. COROLLARY . Hence every parallelogram having ... AC , the squares GB , HC ; and through A draw AL parallel either to BD or CE , and join AD , Fc . Therefore because the ...
Σελίδα 42
... AC . Therefore the square described on the side BC , subtending the right angle , is equal to the squares described on the sides BA , AC , containing the right angle . Therefore in right angled triangles , & c . Q. E. D. Deductions . 1 ...
... AC . Therefore the square described on the side BC , subtending the right angle , is equal to the squares described on the sides BA , AC , containing the right angle . Therefore in right angled triangles , & c . Q. E. D. Deductions . 1 ...
Σελίδα 43
... AC , and make AD equal to BA , and join DC . Therefore because DA is equal to AB , the square also described on DA is equal to the square described on AB . Add the square of AC , which is common . Therefore the Therefore the squares of ...
... AC , and make AD equal to BA , and join DC . Therefore because DA is equal to AB , the square also described on DA is equal to the square described on AB . Add the square of AC , which is common . Therefore the Therefore the squares of ...
Συχνά εμφανιζόμενοι όροι και φράσεις
ABC is equal adjacent angles Algebra angle ABC angle ACB angle BAC angles equal base BC bisected centre circle ABC circumference diameter double draw equal angles equal circles equal right lines equal to F equi equiangular equimultiples Euclid EUCLID'S ELEMENTS exceed exterior angle fore four magnitudes fourth given circle given point given right line gnomon greater ratio hence inscribed isosceles triangle join less Let ABC multiple parallel parallelogram perpendicular polygon proportional Q. E. D. Deductions Q. E. D. PROPOSITION rectangle contained remaining angle right line AB right line AC right line drawn segment side AC similar and similarly square of AC subtending THEOREM three right lines tiple touches the circle triangle ABC triangle DEF whence whole
Δημοφιλή αποσπάσματα
Σελίδα xxx - A diameter of a circle is a straight line drawn through the centre, and terminated both ways by the circumference. XVIII. A semicircle is the figure contained by a diameter and the part of the circumference cut off by the diameter. XIX. "A segment of a circle is the figure contained by a straight line, and the circumference it cuts off.
Σελίδα 74 - The straight line drawn at right angles to the diameter of a circle, from the extremity of it, falls without the circle...
Σελίδα 33 - The complements of the parallelograms, which are about the diameter of any parallelogram, are equal to one another.
Σελίδα 146 - If two triangles have one angle of the one equal to one angle of the other and the sides about these equal angles proportional, the triangles are similar.
Σελίδα 27 - And because the angle ABC is equal to the angle BCD, and the angle CBD to the angle ACB, therefore the whole angle ABD is equal to the whole angle ACD • (ax.
Σελίδα 2 - Things which are double of the same are equal to one another. 7. Things which are halves of the same are equal to one another.
Σελίδα 28 - Parallelograms upon the same base, and between the same parallels, are equal to one another.
Σελίδα 73 - DH ; (i. def. 15.) therefore DH is greater than DG, the less than the greater, which is impossible : therefore no straight line can be drawn from the point A, between AE and the circumference, which does not cut the circle : or, which amounts to the same thing, however great an acute angle a straight line makes with the diameter at the point A, or however small an angle it makes with AE, the circumference must pass between that straight line and the perpendicular AE.
Σελίδα 88 - From a given circle to cut off a segment, which shall contain an angle equal to a given rectilineal angle.
Σελίδα 95 - IN a given circle to inscribe a triangle equiangular to a given triangle. Let ABC be the given circle, and DEF the given triangle; it is required to inscribe in the circle ABC a triangle equiangular to the triangle DEF. Draw (1 7. 3.) the straight line G AH touching the circle in the point A, and. at the point A, in the straight line AH, make (23.