Elements of Geometry: With Practical Applications ...H.H. Howley and Company, 1847 - 308 σελίδες |
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Αποτελέσματα 1 - 5 από τα 64.
Σελίδα 2
... common notion of a point is derived from the extremity of some slender body , such as the end of a common sewing needle . This being perceptible to the senses , is a physical point , and not a mathematical point ; for , by the ...
... common notion of a point is derived from the extremity of some slender body , such as the end of a common sewing needle . This being perceptible to the senses , is a physical point , and not a mathematical point ; for , by the ...
Σελίδα 15
... common , be taken away from each of these equals , the remaining angle AFC will be equal to the remaining angle BFD ( Ax . III ) . And in the same manner it may be shown that the angle AFD is equal to BFC . PROPOSITION III . THEOREM ...
... common , be taken away from each of these equals , the remaining angle AFC will be equal to the remaining angle BFD ( Ax . III ) . And in the same manner it may be shown that the angle AFD is equal to BFC . PROPOSITION III . THEOREM ...
Σελίδα 17
... common , and the angle GDF equal to GDB , each being a right angle ; therefore those triangles are equal ( Prop . II ) : consequently the angle DGB is equal to the angle DGF ; but DGF is equal to the opposite angle AGC ( Prop . II ) ...
... common , and the angle GDF equal to GDB , each being a right angle ; therefore those triangles are equal ( Prop . II ) : consequently the angle DGB is equal to the angle DGF ; but DGF is equal to the opposite angle AGC ( Prop . II ) ...
Σελίδα 18
... common , and the contained angle FDB equal to FDC , each being a right angle . Therefore ( Prop . 1 ) the triangle FBD is equal to FCD ; consequently FB is equal to FC . The solution is ef- fected in the same way when the tree is sup- F ...
... common , and the contained angle FDB equal to FDC , each being a right angle . Therefore ( Prop . 1 ) the triangle FBD is equal to FCD ; consequently FB is equal to FC . The solution is ef- fected in the same way when the tree is sup- F ...
Σελίδα 20
... common ; therefore the two triangles are identical , or equal in all respects ( Prop . ш ) , and consequently the angle B is equal to the angle A. Cor . 1. Hence the line which bisects the vertical angle of an isosceles triangle ...
... common ; therefore the two triangles are identical , or equal in all respects ( Prop . ш ) , and consequently the angle B is equal to the angle A. Cor . 1. Hence the line which bisects the vertical angle of an isosceles triangle ...
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Elements of Geometry With Practical Applications George R Perkins Δεν υπάρχει διαθέσιμη προεπισκόπηση - 2023 |
Συχνά εμφανιζόμενοι όροι και φράσεις
a+b+c AC² altitude angle ACD angle BAC bisect centre chord circ circular sector circumference cone consequently convex surface cylinder diagonal diameter distance draw equal and parallel equiangular equilateral triangle equivalent exterior angle figure formed four right angles given line greater half the arc hypothenuse inscribed circle intersection isosceles join less Let ABC lines drawn magnitude measured by half meet multiplied number of sides opposite angles parallel planes parallelogram parallelopipedon pendicular perimeter perpendicular plane MN point G prism PROBLEM produced Prop PROPOSITION pyramid radii radius rectangle regular polygon respectively equal right angles right-angled triangle Sabc Schol Scholium semicircle semicircumference side AC similar similar triangles solid angle solid described sphere spherical triangle square straight line suppose tangent THEOREM three sides triangle ABC triangular prism vertex VIII
Δημοφιλή αποσπάσματα
Σελίδα 37 - The sum of all the angles of a polygon is equal to twice as many right angles as the polygon has sides, less two.
Σελίδα 180 - THEOREM. If one of two parallel lines is perpendicular to a plane, the other will also be perpendicular to this plane. Let AP & ED be parallel lines, of which AP is perpendicular to the plane MN ; then will ED be also perpendicular to this plane.
Σελίδα 139 - PROBLEM. To inscribe a circle in a given triangle. Let ABC be the given triangle : it is required to inscribe a circle in the triangle ABC.
Σελίδα 224 - The radius of a sphere is a straight line, drawn from the centre to any point of the...
Σελίδα 43 - In a right-angled triangle, the side opposite the right angle is" called the Hypothenuse ; and the other two sides are cal4ed the Legs, and sometimes the Base and Perpendicular.
Σελίδα 184 - THEOREM. If two angles, not situated in the same plane, have their sides parallel and lying in the same direction, they will be equal, and the planes in which they are situated will be parallel.
Σελίδα 10 - A circle is a plane figure contained by one line, which is called the circumference, and is such, that all straight lines drawn from a certain point within the figure to the circumference are equal to one another.
Σελίδα 226 - We conclude then, that the solidity of a cylinder is equal to the product of its base by its altitude.
Σελίδα 22 - If two sides and the included angle of the one are respectively equal to two sides and the included angle of the other...
Σελίδα 12 - If equals be added to unequals, the wholes are unequal. V. If equals be taken from unequals, the remainders are unequal. VI. Things which are double of the same, are equal to one another.