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In higher works on trigonometry, it has been demonstrated that, in any triangle, the sines of the angles are proportional to the lengths of the sides opposite to them. In other words, sin A : sin B :: BC : AC; or, sin A : sin C:: BC : AB, and sin B :...
Dictionary of the Mathematical and Physical Sciences, According to the ... - Σελίδα 524
επεξεργασία από - 1823 - 576 σελίδες
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## A Popular Course of Pure and Mixed Mathematics ...: With Tables of ...

Peter Nicholson - 1825 - 372 σελίδες
...the sine of that angle measured in the circle ; therefore the sides of the triangle are to each other as the. sines of the opposite angles measured in the...consequently as the sines of the same angles measured in a circle whose radius is that of the tables. Hence the following proposition of such frequent use in...

## An essay on the theory and practice of setting out railway curves

...the sine of that angle measured in the circle ; therefore the sides of the triangle are to each other as the sines of the opposite angles measured in the...Trigonometry. In any triangle, the sines of the angles measured by any one circle are proportional to the sides opposite those same angles. In our plan of...

## Liber Cantabrigiensis, an account of the aids afforded to poor students, the ...

Robert Potts - 1855
...nearest him (from which his distance is a) in a straight line. Find the radius of the curve. 6. Shew that in any triangle the sines of the angles are proportional to the opposite sides. 8. Prove that for all values of m, cos mO + -J{- 1) sin mO is a value of {cos 0 + V(-...

## A mathematical course for the University of London. (2nd)

Thomas Kimber - 1865 - 192 σελίδες
...+ g = . Account for the value of tan. A + В given by this formula, if A = В = 45°. 13. In every triangle the sines of the angles are proportional to the sides opposite to them. Find the area of the triangle whose sides are 30, 40, 50 feet. 14. Given two angles and a...

## Examination for women. Examination papers, with lists of syndics and examiners

...particular case. /o Having given that cos 330° = ~ , find the cosine and sine of 165°. 4. Prove that, in any triangle, the sines of the angles are proportional to the sides respectively opposite to the angles, and that any side divided by the sine of the opposite angle, is...

## London graduation mathematics, questions in arithmetic and algebra set from ...

Thomas Kimber - 1880
...В . — Account for the value of tan. A + В given by this formula, if A s= В = 45°. 18. In every triangle the sines of the angles are proportional to the sides opposite to them. Find the area of the triangle whose sides are 30, 40, 50 feet. 14. Given two angles and a...

## Elementary text-book of trigonometry

Robert Hamilton Pinkerton - 1884 - 176 σελίδες
...magnitude from 0° up to 180°, but that the angle VES will always be limited in magnitude. Now, since in any triangle the sines of the angles are proportional to the opposite sides, whatever be the positions of V and E, we have the equation sinSEV_VS_5 sinSVE ~ ES...

## Mechanics' Pocket Memoranda: A Convenient Pocketbook for All Persons ...

International Correspondence Schools - 1897 - 318 σελίδες
...a triangle given to find the other two sides AB and C B. In Trigonometry, it is demonstrated that, in any triangle the sines of the angles are proportional to the lengths of the sides opposite to them. In other words, sin A : sin B :: BC : AC; or, sin A : sin U...

## A Textbook on Surveying and Mapping ...: Arithmetic, formulas, geometry and ...

...method, however, is the following: In higher works on trigonometry, it has been demonstrated that, in any triangle, the sines of the angles are proportional to the lengths of the sides opposite to them. In other words, sin A : sin B::BC : AC; or, sin A : sin C:;BC...

## The Elements of Civil Engineering: Prepared for Students of the ..., Τόμος 3

...method, however, is the following: In higher works on trigonometry, it has been demonstrated that, in any triangle, the sines of the angles are proportional to the lengths of the sides opposite to them. In other words, sin A : sin B::BC:AC; or, sin A : sin C:: BC...