| John Keill - 1723 - 444 σελίδες
...Angle HAC is alfo equal to the Angle MDF. Therefore the two Triangles MDF, HAC, have two Angles of the one equal to two Angles Of the other, each to each, and one Side of the one equal to one Side of the other, viz. that which is fubtended by one of the equal... | |
| Euclid, John Keill - 1733 - 444 σελίδες
...Angle HAG is alfo equa to the Angle MDF. Therefore the two Triangles MDF, HA C, have two Angles of the one equal to two Angles of the other, each to each, and one Side of the one equal to one Side of the other, viz. that which is fubtended by one of the equal... | |
| Robert Simson - 1762 - 488 σελίδες
...BAC is greater than the angle EDF. Wherefore if two triangles, &c. Q^ED PROP. XXVI. THEOR. T*. " TF two triangles have two angles of one equal to two angles of the other; each to each, and one fide equal to. one fide, viz. cither the lides adjacent to the equal angles> or the fides oppofue... | |
| Euclid - 1765 - 492 σελίδες
...Clavius has alfo tranflated them into Latin. PROP. XXVI. THEO R. If two triangles have two angles of the one equal to two angles of the other, each to each, and one fide of the one equal to one fide of the other, either that fide which is hetween the equal angles,... | |
| Robert Simson - 1775 - 534 σελίδες
...angle BAC is greater than the angle EDF. Wherefore, if two triangles, &c. QJLD. PROP. XXVI. THEO R. TF two triangles have two angles of one equal to two angles of the other, each to each ; and one fide equal to one fide, viz. either the fides adjacent to the equal angles, or the fides oppofite... | |
| Euclid - 1776 - 326 σελίδες
...EDF, it muft be greater. Wherefore, &c. PROP. XXVI. THEO R. TF two triangles have two angles of the one equal to two angles •*• of the other, each to each, and aJiJe of the one equal to ajide of the other, either thejide lying between the equal angks, orj'ubtending... | |
| Robert Simson - 1781 - 534 σελίδες
...right angi« \ FCK is equal to the right angle FCL. therefore in the two triangles FKC, FLC, there are two angles of one equal to two angles of the other, each to each, and the fide FC, which is adjacent to the equal angles in each, is common to both ; therefore the other... | |
| Euclid - 1781 - 552 σελίδες
...Fl angle FCK is equal to the right angle FCL : Therefore, in the two triangles FKC, FLC, there ate two angles of one equal to two angles of the other, each t» each, and the fide FC, which is adjacent to the equal angles in each, is common to both ; theiefore... | |
| Euclid, John Playfair - 1795 - 462 σελίδες
...to the angle EEC : and the angle AEG is equal to the angle BEH a ; therefore the triangles AEG, BEH have two angles of one equal to two angles of the other, each to each, and the fides AE, EB, adjacent to the equal angles, equal to one another ; wherefore they lliall have their... | |
| Benjamin Donne - 1796 - 120 σελίδες
...of another, the remaining angle of me nwji be equal to the remaining angle of the other. THEOREM 15. If two triangles have two angles of one equal to two angles of the other, each to each, and one s1de of one equal to one D side side of the other, the triangles are equal in every refpcEl. —... | |
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