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" RULE.* Multiply the principal by the 'rate per cent, and divide the product by 100: the quotient will be the interest for 1 year. "
The Teacher's Assistant: Or, A System of Practical Arithmetic: Wherein the ... - Σελίδα 97
1831 - 198 σελίδες
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A New System of Mercantile Arithmetic: Adapted to the Commerce of the United ...

Michael Walsh - 1807 - 290 σελίδες
...Hate, is the sum per cent.-agreed on. Amount, is the principal and interest added together. GENERAL RULE. Multiply the principal by the rate per cent, and divide the product by 100, and the quotient is the answer for one year.. EXAMPLES. 1 . What is the interest of ¿£.496 for one...

The American Tutor's Assistant Revised, Or, A Compendious System of ...

Zachariah Jess - 1810 - 222 σελίδες
...arises from tta principal only. CASE 1. When tfcfc time is any number of years, asd the rate per cent, pounds or dollars only ; RULE. Multiply the principal by the rate per cent, and divide the produél by 1 00, the quotient will be the interest for one year ; which multiply by the years given....

A New and Plain System of Arithmetic: Containing the Several Rules of that ...

Elijah H. Hendrick - 1810 - 220 σελίδες
...Simple and Compound.!, SIMPLE INTEREST is that which arifes from the principal only. General Rule. I. Multiply the principal by the rate per cent, and divide the product by loo, (or, which is the fame, cut-off two right hand figures in the pounds, which mint be reduced to...

The Teachers Assistant. Or, A System of Practical Arithmetic: Wherein the ...

1811 - 210 σελίδες
...dollars, for one year. Fourth. The amount, which is the sum of the principal and interest. CASE*1!. When the time is one year, and the rate per cent,...the rate per cent, and divide the product by 100. PROOF. , , By the Single Rule of Three. EXAMPLES. 1. What is the interest of 525 L. for 1 year, at...

Daboll's Schoolmaster's Assistant: Improved and Enlarged, Being a Plain ...

Nathan Daboll - 1815 - 250 σελίδες
...principal and interest added together. CASE I. To find the interest of any given sum for one year. RULE. Multiply the principal by the rate per cent,...divide the product by 100 ; the quotient will be the answer. EXAMPLE!. 1. What is the interest of 39Z. lls. 8id. for one year at 61. per cent, per annum...

Daboll's Schoolmaster's Assistant, Improved and Enlarged: Eing a Plain ...

Nathan Daboll - 1823 - 262 σελίδες
...principal and interest added together. CASE I. To find the interest of any given sum for one yeai» RULE. Multiply the principal by the rate per cent....divide the product by 100 ; the quotient will be the answer. EXAMPLES. 1. What is the interest of S9/. Us. 8itI. for one year, at 61. per cent. per annum...

Daboll's Schoolmaster's Assistant: Improved and Enlarged. Being a Plain ...

Nathan Daboll - 1824 - 264 σελίδες
...principal and interest added together • CASE I. To find the interest of any given sum for one year. RULE. Multiply the principal by the rate per cent. and divide the product by 100} the quotient \vill be the answer. EXAMPLES. 1. What is the interest of 391. lls. 8Jd. for one year at 6/. per cent....

The American Tutor's Assistant Revised, Or, A Compendious System of ...

Zachariah Jess - 1824 - 224 σελίδες
...ii any number of years, and the rate per cent, pounds or dollars only ; '•; ik-V'~" "-*' •*'"' RULE* Multiply the principal by the rate per cent, and divide the produftby too, the quotient will be the interest for one year } which multiply by the years given....

Daboll's Schoolmaster's Assistant, Improved and Enlarged

Nathan Daboll - 1825 - 248 σελίδες
...principal and interest addeâ together. CASE i. Vb find {he interest of any given sum for one ysar. RULE. Multiply the principal by the rate per cent....divide the product by 100 ; the quotient will be the answer. EXAMPLES. 1. What is the interest of 391. 11s. SJd. for one year. at 61. per cent, per annum...

Pike's System of Arithmetic Abridged: To which are Added Appropriate ...

Nicolas Pike, Dudley Leavitt - 1826 - 214 σελίδες
...insurance of his property, and is generally at so much per cent. RULE. — Multiply the sum to be insured by the rate per cent. and divide the product by 100 ; — the quotient will be the premium or answer. EXAMPLE. What will be the annual premium for insuring a house against los» *iy...




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