Primary Elements of Plane and Solid Geometry: For Schools and AcademiesWilson, Hinkle & Company, 1862 - 98 σελίδες |
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Αποτελέσματα 1 - 5 από τα 11.
Σελίδα 80
... solidity of a right parallelopiped is equal to the area of its base multiplied by its hight . Let ABC be a right paral- lelopiped . It is to be proved that its solidity is equal to the area of its base AB , multiplied by its hight DC ...
... solidity of a right parallelopiped is equal to the area of its base multiplied by its hight . Let ABC be a right paral- lelopiped . It is to be proved that its solidity is equal to the area of its base AB , multiplied by its hight DC ...
Σελίδα 81
... solidity . Now , in the layer next to the base , there will be as many of these solid units as there are corresponding units of area in the base ; and there will be as many equal layers as there are corresponding linear units in the ...
... solidity . Now , in the layer next to the base , there will be as many of these solid units as there are corresponding units of area in the base ; and there will be as many equal layers as there are corresponding linear units in the ...
Σελίδα 83
... solidity of any parallelopiped on a rect- angular base , is equal to the area of its base multi- plied by its altitude ; for it is equivalent to a right parallelopiped of the same base and altitude . SEC . XV . THE PRISM AND THE ...
... solidity of any parallelopiped on a rect- angular base , is equal to the area of its base multi- plied by its altitude ; for it is equivalent to a right parallelopiped of the same base and altitude . SEC . XV . THE PRISM AND THE ...
Σελίδα 85
... solidity of any prism is equal to the area of its base multiplied by its altitude . Let ABCD be any prism . Now , A whatever may be the form of its base , AB , it is evident that it may be divided into an indefinitely large number of ...
... solidity of any prism is equal to the area of its base multiplied by its altitude . Let ABCD be any prism . Now , A whatever may be the form of its base , AB , it is evident that it may be divided into an indefinitely large number of ...
Σελίδα 86
... solidity is equal to the area of its base multiplied by its altitude . Let ABCD be a cylinder , having A a prism ... solidity of the prism with the solidity of the cylinder . But the convex surface of the prism is equal to the perimeter ...
... solidity is equal to the area of its base multiplied by its altitude . Let ABCD be a cylinder , having A a prism ... solidity of the prism with the solidity of the cylinder . But the convex surface of the prism is equal to the perimeter ...
Άλλες εκδόσεις - Προβολή όλων
Primary Elements of Plane and Solid Geometry: For Schools and Academies E W (Evan Wilhelm) 1827-1874 Evans Δεν υπάρχει διαθέσιμη προεπισκόπηση - 2021 |
Primary Elements of Plane and Solid Geometry: For Schools and Academies E. W. 1827-1874 Evans Δεν υπάρχει διαθέσιμη προεπισκόπηση - 2016 |
Συχνά εμφανιζόμενοι όροι και φράσεις
AB² ABCDEF allel alternate angles altitude angle BAC angles ABC apothegm base multiplied bisect called chord circle circumference cone consequently convex surface diagonals diameter divided draw Eclectic Reader equal Theo equal to half equivalent frustum Geometry given point half the arc half the product Hence hypotenuse included angle inscribed angle intersect isosceles triangle Let ABCD let fall McGuffey's measured by half mutually equiangular mutually equilateral number of equal number of sides opposite parallelogram perimeter perpendicular perpendicular distance prism proportion proved Published by W. B. quadrilateral radii radius Ray's rectangle regular inscribed regular polygon regular pyramid right angles right parallelopiped right-angled triangle Schol semicircle side BC slant hight solidity square straight line SUPT tangent THEOREM trapezoid triangles ABC triangles are equal triangular vertex W. B. SMITH
Δημοφιλή αποσπάσματα
Σελίδα 69 - If from a point without a circle, a tangent and a secant be drawn, the tangent will be a mean proportional between the secant and its external segment.
Σελίδα 42 - The circumference of every circle is supposed to' be divided into 360 equal parts, called degrees ; each degree into 60 minutes, and each minute into 60 seconds. Degrees, minutes, and seconds are designated by the characters °, ', ". Thus 23° 14' 35" is read 23 degrees, 14 minutes, and 35 seconds.
Σελίδα 21 - If two triangles have two sides, and the included angle of the one equal to two sides and the included angle of the other, each to each, the two triangles are equal in all respects.
Σελίδα 47 - It follows, then, that the area of a circle is equal to half the product of its circumference and its radius.
Σελίδα 72 - The areas of two circles are to each other as the squares of their radii. For, if S and S' denote the areas, and R and R
Σελίδα 33 - The square described on the hypothenuse of a right-angled triangle is equivalent to the sum of the squares described on the other two sides.
Σελίδα 38 - The area of a regular polygon is equal to half the product of its apothem and perimeter.
Σελίδα 52 - PROBLEM VII. Two angles of a triangle being given, to find the third angle. The three angles of every triangle are together equal to two right angles (Prop.
Σελίδα 30 - The area of a rectangle is equal to the product of its base and altitude.
Σελίδα 69 - If two triangles have two angles of the one equal to two angles of the other, each to each, and one side equal to one side, viz. either the sides adjacent to the equal...