 | Euclid, John Keill - 1733 - 444 σελίδες
...unequal to EF, therefore it is equal to it. But AB is alfo equal to D E. Wherefore the two Sides AB, BC, are equal to the two Sides DE, EF, each to each ; and they cpntain equal Angles. And fo the Bafe AC is equal to the Bafe DF, the Triangle BAC to the Triangle... | |
 | John Keill - 1772 - 462 σελίδες
...which let be AB, make GB equal to DE, and join <3 C. t Then, becaufe BG is equal to DE, and BC to EF, the two Sides GB, BC, are equal to the two Sides DE,...equal to the Angle DE F. The Bafe GC is * equal to th«» 4 »/'««• Bafe DF, and the Triangle GBC to the Triangle DEF, and the remaining Angles equal... | |
 | Euclid, James Williamson - 1781 - 324 σελίδες
...DE, EF 1 ~" v ~~' each to each; and the angle GBC is equal (by fupp.) to DEF: therefore (by prop. 4.) the bafe GC is equal to the bafe DF; and the triangle GCB will be equal to the triangle DEF; and the remaining angles will be equal to the remaining angles,... | |
 | Euclid, John Playfair - 1795 - 462 σελίδες
...equal to the two DE,. EF, each to each; and the angle GBC is.equal to the angle DEF ; therefore me bafe GC is equal » to the bafe DF, and the triangle GBC to the triangle DEF, and the other angles to the other angles, each, to each,, to. which the equal fideS are oppofite ; thereforei... | |
 | John Playfair, Euclid - 1804 - 468 σελίδες
...equal to the two DE, FT, each to each ; and the angle GBC is equal to the angle DEF; therefore the bale GC is equal" to the bafe DF, and the triangle GBC to the triangle DEF, and the other angles to the other angles, each to each, to which the equal fides are oppofite ; therefore the... | |
 | Pierce Morton - 1830 - 584 σελίδες
...will be between L and B. Join QC: and, because the triangles Q В С, DEF have the two sides QB, В С equal to the two sides DE, EF, each to each, and the included angles equal to one another, the third sides QC, DF are equal to one another (13.) ; and,... | |
 | 1835 - 684 σελίδες
...will be between L and B. Join QC: and, because the triangles QBG, DEF have the two sides QB, В С equal to the two sides DE, EF, each to each, and the included angles equal to one another, the third sides QC, DF are equal to one another (13.) ; and,... | |
 | John Playfair - 1836 - 148 σελίδες
...equal to DE, and join CG ; therefore, because BG is equal to DE, and BC to EF, the two sides GB, BC arc equal to the two sides DE, EF, £ each to each ; and the angle GBC is equal to the angle DEF ; therefore the base CG is equal (4.1.) to the base DF, and the triangle... | |
 | Euclides - 1855 - 270 σελίδες
...EF ; that is, B С is equal to K F. And AB is equal (Hyp.) to D E. Therefore the two sides AB, B С are equal to the two sides DE, EF, each to each. And the angle AB С is equal (Hyp.) to the angle DE F. Therefore the base A С is equal (I. 4) to the base DF, and... | |
 | Euclides - 1862 - 140 σελίδες
...Demonstration. — 1. Because BG is assumed to be equal to DE (const.), and BC is equal to EF (hyp.), the two sides GB, BC, are equal to the two sides DE, EF, each to each. 2. And the angle GBC is equal to the angle DEF, (hyp.) 3. Therefore the base GC is equal to the base... | |
| |
EF (Hyp.), the two sides GB, BC are equal to the two sides DE, EF, each to each. And the angle GBC is equal to the angle DEF (Hyp.); Therefore the base GC is equal to the base DF (I. 
