Εικόνες σελίδας
PDF
Ηλεκτρ. έκδοση

in the

e cubic

torrid

seldom exceeds 300; in stronger earth it becomes 370; and in some fa vourable cases more than 45o,

1. If h = AD, x = AE, 0 = 4 DA G, and S and s represent the specific gravities of the wall and earth, the state of equilibrium is expressed by this equation,

x2. S h2. s. tan. 0.

Ex. Suppose the wall to be 39.37 feet high, of brick, specific gravity 2000, and the bank of earth specific gravity 1428, and the natural slope 53°; then

a, 2000% X 39.37 X 1428 X tan.2 2640,

.9.6 feet thickness of wall,

The following practical results may be found useful.

Values of DG for different materials.

[merged small][merged small][ocr errors][merged small][ocr errors]
[ocr errors][ocr errors][ocr errors][merged small]

Do. of vegetable earth mixed with small gravel
Do. of rubbles

Do. of vegetable earth mixed with large gravel.

[blocks in formation]

www

DG.646 h.

DG 414 h.

DG.618 h..

Thickness of walls, both faces vertical.

1. Wall brick, 109 lbs. per cubic foot, bank vegetable
earth carefully laid course by course www.ins
2. Wall unhewn stones, 135 lbs. per cubic foot, earth
as before

3. Wall brick, earth clay well rammed www.n
4. Wall unhewn stones, earth as before www.avaraamat
5. Wall of hewn freestone, 170 lbs. per cubic foot,
bank vegetable earth www______

6. Do. bank clay

7. Bank of earth mixed with large gravel, wall of

[ocr errors][merged small]
[blocks in formation]

When the earth of the bank is liable to be much saturated with water the proportional thicknesses of the walls must at least be doubled.

2. For walls with an interior slope, or a slope towards the bank, let

[merged small][merged small][merged small][merged small][merged small][merged small][subsumed][subsumed][ocr errors][subsumed][subsumed][merged small]

where m = .0424 for vegetable or clayey earth, mixed with large gravel; m = .0464 if the earth be mixed with small gravel; m = .1528 for sand; and m.166 for semifluid earths.

Ex. Let the height of a wall be 20 feet, and 1

20

of the height for the base of the slope, suppose also the specific gravity of the wall and bank to be 2600 and 1400, and the earth semifluid; then

[blocks in formation]

5 feet, while the thickness of the wall at the bottom will be 6 feet.

EASTER, to find it on any year.-(Delambre.)

1. Divide the year proposed by 19 ............... Call remainder a.

2. Divide the same number by 4

Call remainder b.

[merged small][merged small][ocr errors][merged small]

Call remainder e.

5. Divide (2b+ 4 c + 6 d + N) by 7

6. Then Easter day will fall either on (22 +d+e) of March; or on

[merged small][merged small][merged small][merged small][ocr errors][merged small][merged small][merged small]

2. If it give

............ 24 ............ 5

1. If the computation give April 26, substitute the 19th.

April 25, substitute the 18th.

ECCENTRICITY of a Planet's orbit.-(Woodhouse, Playfair.)
Let e be the eccentricity of the orbit, g the greatest equation of the

centre, found by observation, and put

[ocr errors][merged small]

g 570.29578

=h, then

[blocks in formation]

bank, let

gravel; r sand;

or the

bank

tom

In the earth's orbit h is very small, .. eh nearly.

The secular diminution = 18". 79, and .. if this diminution continued uniform (which, however, we have not a right to suppose) the earth's orbit would become a circle in about 36300 years.

ECHO.

That an echo may return one syllable as soon as it is pronounced, the reflecting surface should be 80 or 90 feet distant; for a dissyllablic echo 170 feet, &c. This is upon the supposition that sound proceeds at the rate of 1142 feet per second, and that the ear can distinguish the succes

sion of two sounds or syllables, when the interval between them is
of a second.--(Playfair.)

1

-th

An echo in Woodstock Park repeats 17 syllables by day, and 20 by night. An echo on the north side of Shipley church in Sussex, repeats 21 syllables.(Young's Nat. Phil.)

ECLIPSES.-(Woodhouse, Playfair.)

1. Eclipses of the Moon.

1. The length of the earth's shadow varies, according to the distance of the sun and earth, between the limits of 212,896, and 220,238 semidiameters of the earth; its mean length being 216,531. And in general if r be the earth's radius, the apparent semidiameter, and p the horizontal par

allax of the sun, the length of the shadow, reckoned from the earth's centre,

[merged small][ocr errors][ocr errors][merged small][ocr errors][merged small]

2. Hence half the angle subtended at the earth's centre by the section of the shadow, at the distance of the moon, (if P be the horizontal parallax of the moon) is

[blocks in formation]
[ocr errors]

From this formula the apparent diameters of the earth's shadow may be computed for various distances of the sun and moon, as in the following Table.

Moon in apogee

Apparent diam, of
earth's shadow.

1o. 15'. 24,3036

at mean distance.............. 1. 23. 2:31

Sun in perigee

Cin perigee

1. 30, 40,3164

[blocks in formation]

3. The distance of the centres of the moon and of the earth's shadow, when the moon's disk just touches the shadow (if d = moon's diameter)

[blocks in formation]

D

16. 13, we have the mean

2

diameter of the earth's shadow

Cor. If P57.1", p =8", 8, and apparent 41. 8",5, which is nearly three apparent diameters of the moon. Hence since the moon in the space of an hour moves over a space nearly equal to its diameter, the moon may be entirely within the shadow, or a total eclipse may endure, about two hours.

4. The apparent diameter of a section of the penumbra at the moon's orbit=

[blocks in formation]

And the distance of the moon's centre and of the centre of the shadow, when the moon first enters the penumbra, is

D d
P+ P+ +
2

5. To find the time, duration, and magnitude of a lunar eclipse.

Let m moon's motion in longitude,

nmoon's motion in latitude,

ssun's (or the shadow's centre's) motion in longitude,
amoon's latitude when in opposition,

time from opposition,

e distance of moon and earth's shadow,

[merged small][merged small][merged small][merged small][merged small][merged small][ocr errors][merged small][merged small]
[merged small][merged small][ocr errors][merged small][merged small][ocr errors][ocr errors][merged small][merged small]

from which expression may be deduced values of the time, corresponding to any assigned values of c, as in the following instances.

(j) To determine the time at which the moon first enters the penumD

bra, for c put P+p+ + t has two values, and the second value

2 2

[ocr errors]

will denote the time at which the moon quits the penumbra.

(ii) To determine the time at which the moon enters the umbra, put

[blocks in formation]

(iii) To determine the time when the whole disk has just entered the shadow, we must deduct d from the preceding value, and make c=P+

[merged small][ocr errors][merged small][merged small][merged small][merged small]

sin.2 0

[ocr errors]

(jjjj) To find the middle of the eclipse, we have t=— a

and in

[ocr errors]
[ocr errors]

that case the distance of the centres (c) is a cos. 0.

[ocr errors][merged small]

(v) The nearest approach of the centres being known, the magnitude of the eclipse is easily ascertained. Thus on the supposition that a cos, d

is less than the distance (P+P + ē

at which the moon's

limb just touches the shadow, some part of the moon's disk is eclipsed; and the portion of the diameter of the eclipsed part is

[merged small][merged small][ocr errors][merged small][merged small][merged small]

The portion of the diameter of the non-eclipsed part is the moon's apparent diameter d, minus the preceding expression, and therefore is

[blocks in formation]

If this expression should be equal nothing, the eclipse would be just a total one. If the expression should be negative, the eclipse may be said to be more than a total one, since the upper boundary of the moon's disk would be below the upper boundary of the section of the shadow.

[merged small][merged small][merged small][merged small][ocr errors][merged small][merged small][merged small][merged small][merged small]

first entering to her finally quitting the shadow or umbra. And if in the

« ΠροηγούμενηΣυνέχεια »